我需要以这种形式构建一个类
namespace BestCompanyEver
{
public class PersonInfo
{
public string Name{get;set;}
public int Age{get;set;}
}
}
从表格中包含姓名和年龄的人。
有没有现成的解决方案?
我知道我可以用T4或Codesmith实现这个,但是应该有人已经做过了。
答案 0 :(得分:3)
我发现了一些我可以使用的不错的T4模板。它来自codeplex上的一个项目。
模板难以阅读,我花了一些时间来简化它。 在使用它之前,您必须从项目中下载include(CSharpDataClasses.tt)。
这是我的模板():
<# // L2ST4 - LINQ to SQL templates for T4 v0.82 - http://www.codeplex.com/l2st4
// Copyright (c) Microsoft Corporation. All rights reserved.
// This source code is made available under the terms of the Microsoft Public License (MS-PL)
#><#@ template language="C#v3.5" hostspecific="True"
#><#@ include file="L2ST4.ttinclude"
#><#@ output extension=".generated.cs"
#><# // Set options here
var options = new {
DbmlFileName = Host.TemplateFile.Replace(".tt",".dbml"), // Which DBML file to operate on (same filename as template)
SerializeDataContractSP1 = false, // Emit SP1 DataContract serializer attributes
FilePerEntity = true, // Put each class into a separate file
StoredProcedureConcurrency = false, // Table updates via an SP require @@rowcount to be returned to enable concurrency
EntityFilePath = Path.GetDirectoryName(Host.TemplateFile) // Where to put the files
};
var code = new CSharpCodeLanguage();
var data = new Data(options.DbmlFileName);
var manager = new Manager(Host, GenerationEnvironment, true) { OutputPath = options.EntityFilePath };
data.ContextNamespace = (new string[] { manager.GetCustomToolNamespace(data.DbmlFileName), data.SpecifiedContextNamespace, manager.DefaultProjectNamespace }).FirstOrDefault(s => !String.IsNullOrEmpty(s));
data.EntityNamespace = (new string[] { manager.GetCustomToolNamespace(data.DbmlFileName), data.SpecifiedEntityNamespace, manager.DefaultProjectNamespace }).FirstOrDefault(s => !String.IsNullOrEmpty(s));
manager.StartHeader();
manager.EndHeader();
var tableOperations = new List<TableOperation>();
foreach(var table in data.Tables)
tableOperations.AddRange(table.Operations);
foreach(Table table in data.Tables)
foreach(OperationType operationType in Enum.GetValues(typeof(OperationType)))
if (!tableOperations.Any(o => (o.Table == table) && (o.Type == operationType))) {}
if (!String.IsNullOrEmpty(data.ContextNamespace)) {}
foreach(Table table in data.Tables) {
foreach(TableClass class1 in table.Classes) {
manager.StartBlock(Path.ChangeExtension(class1.Name + "Info" ,".cs"));
if (!String.IsNullOrEmpty(data.EntityNamespace)) {#>
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace <#=data.EntityNamespace#>
{
<# }
#> <#=code.Format(class1.TypeAttributes)#> class <#=class1.Name#>Info
{
<# int dataMemberIndex = 1;
if (class1.Columns.Count > 0) {
#><# foreach(Column column in class1.Columns) {#>
private <#=code.Format(column.StorageType)#> <#= "_" + char.ToLower(column.Member[0]) + column.Member.Substring(1) #><# if (column.IsReadOnly) {#> = default(<#=code.Format(column.StorageType)#>)<#}#>;
<#=code.Format(column.MemberAttributes)#><#=code.Format(column.Type)#> <#=column.Member#>
{
get { return <#= "_" + char.ToLower(column.Member[0]) + column.Member.Substring(1) #>; }
set {<#= "_" + char.ToLower(column.Member[0]) + column.Member.Substring(1) #> = value;}
}
<# }
}
#>
}
}
<#
manager.EndBlock();
}
}
manager.StartFooter();
manager.EndFooter();
manager.Process(options.FilePerEntity);#>
答案 1 :(得分:2)
Entity Framework怎么办?
答案 2 :(得分:2)
或LINQ to SQL,或LLBLGen Pro
答案 3 :(得分:1)
或Subsonic,或NHibernate ......