Question

我对asynctask有一些问题......

我使用asynctask将一些URL（* .aspx和paramters）发送到我的服务器并插入一些数据。我的问题是如何确保数据在服务器中成功插入。然后，如果它可以插入我的服务器，我将在手机上更新数据发送成功的数据库

这是我的网址：

    vURL = Routines.URL_SEND_SJ +"?sjnumber=SJ-" + Routines.getSJNumber(vContext) +
                                 "&orgid=" + Routines.getOrgId(vContext) +
                                 "&deviceid="  + Routines.getImei(vContext) +
                                 "&savedate=" + vDate +
                                 "&savetime=" + vTime +
                                 "&status=" + vStatusSJNumber +
                                 "&latitude=" + vLatitude + 
                                 "&longitude=" + vLongitude +
                                 "&phonetype=" + vPhoneType +
                                 "&km=" + vKM;

AsyncTask类通过ASPX类发送URL

公共类ASPX {

public static String submitASPXText(String vURL){       
    String vASPXText="";
    HttpClient vHttpClient = new DefaultHttpClient();

    HttpGet vHttpGet = new HttpGet(vURL);
    try{
        ResponseHandler<String> responseHandler=new BasicResponseHandler();
        vASPXText = vHttpClient.execute(vHttpGet, responseHandler);
        vASPXText = vASPXText.replace("<span id=\"Label1\">~", "");
        vASPXText = vASPXText.replace("`</span>", Routines.SEND); 
    }catch (Exception e){
        e.printStackTrace();
    }

    return vASPXText;
}



private class LocationAsyncTask extends AsyncTask<String, Void, String>{

    @Override
    protected String doInBackground(String... vURL) {
        String vASPXText = ASPX.submitASPXText(vURL[0]);
        return vASPXText;
    }

    @Override
    protected void onPostExecute(String vASPXResult) {
        super.onPostExecute(vASPXResult);
        Toast.makeText(getApplicationContext(), "insert sucess", Toast.LENGTH_SHORT).show();
    }
}

Answer 1

为什么不让服务器返回JSON消息，然后让您的应用查看消息以查看数据是否已保存。例如，如果插入成功返回...

{
    "returnCode": 0,
    "returnMessage": "Data saved!"
}

如果有错误返回

{
    "returnCode": 1,
    "returnMessage": "Database Error! Data was not saved!"
}

在Android上，您可以使用内置的JSONObject来读取JSON消息。例如......

JSONObject object = JSONObject(json);
int returnCode = object.getInt("returnCode");
if (returnCode == 0){
    //Data was saved
} else {
    //Data was saved
}

如何使用AsyncTask函数确保数据成功发送

1 个答案: