Question

全局变量m_xDoc

我有

的财产

public XmlDocument xDoc
{
    get {return m_xDoc; }
    set {value = m_xDoc; }           
} 

string xml = "<head><body><Inner> welcome </head></Inner><Outer> Bye</Outer></body></head>"

现在我必须使用此字符串将该属性设置为XML文档...请指导我如何执行此操作

Answer 1

使用XmlDocument的LoadXml方法;

string xml = "<head><body><Inner> welcome </head> </Inner> <Outer> Bye</Outer></body></head>";
xDoc.LoadXml(xml);

Answer 2

// using System.Xml;

String rawXml =
      @"<root>
          <person firstname=""Riley"" lastname=""Scott"" />
          <person firstname=""Thomas"" lastname=""Scott"" />
      </root>";

XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(rawXml);

我认为这应该有用。

Answer 3

string test = "<body><head>test header</head></body>";

XmlDocument xmltest = new XmlDocument();
xmltest.LoadXml(test);

XmlNodeList elemlist = xmltest.GetElementsByTagName("head");

string result = elemlist[0].InnerXml; 

//result -> "test header"

Answer 4

xDoc.LoadXML("<head><body><Inner> welcome </head> </Inner> <Outer> Bye</Outer>                    
                    </body></head>");

如何使用C＃将字符串转换为XML

4 个答案: