示例:
>>> def write_to_terminal(fmt, *args):
... print fmt % args
>>> LOG = logging.getLogger(__name__)
>>> info = multicall(write_to_terminal, LOG.info)
>>> debug = multicall(write_debug_to_terminal, LOG.debug)
>>> ...
>>> info('Hello %s', 'guido') # display in terminal *and* log the message
是否有一种优雅的方式来撰写multicall
?也许在标准库的帮助下......没有重新发明轮子?
答案 0 :(得分:5)
这样的东西?
def multicall(*functions):
def call_functions(*args, **kwds):
for function in functions:
function(*args, **kwds)
return call_functions
如果你想汇总结果:
def multicall(*functions):
def call_functions(*args, **kwds):
return [function(*args, **kwds) for function in functions]
return call_functions
修改
建议装饰者;在这种情况下,它看起来像这样:
def appendcalls(*functions):
def decorator(decorated_function):
all_functions = [decorated_function] + list(functions)
def call_functions(*args, **kwds):
for function in all_functions:
function(*args, **kwds)
return call_functions
return decorator
LOG = logging.getLogger(__name__)
@appendcalls(LOG.info)
def info(fmt, *args):
print fmt % args
info('Hello %s', 'guido')
appendcalls()
在装饰函数之后调用任意数量的函数。您可能希望以不同的方式实现装饰器,具体取决于您想要的返回值 - 装饰函数中的原始值,所有函数结果的列表或者根本没有。
答案 1 :(得分:1)
您可以查看Python装饰器。
这里有一个清晰的描述:http://www.artima.com/weblogs/viewpost.jsp?thread=240808