Question

使用以下https://github.com/apache/incubator-cordova-mac制作mac os x应用程序，但似乎我无法获得打开的_blank链接。如果有人知道那会是多么好。

答案1） - 没有用

我把它放在WebViewDelegate.m -

中

UIWebViewNavigationType＆lt;是错误

- (BOOL) webView:(WebView*)theWebView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType
{
    //return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
    NSURL *url = [request URL];

    // Intercept the external http requests and forward to Safari.app
    // Otherwise forward to the PhoneGap WebView
    if ([[url scheme] isEqualToString:@"http"] || [[url scheme] isEqualToString:@"https"] || [[url scheme] isEqualToString:@"itms-apps"]) {
        [[UIApplication sharedApplication] openURL:url];
        return NO;
    }
    else {
        return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
    }
}

Answer 1

我认为_blank更改是最新版本，尚未在iOS中实现。我目前在AppDelegate.m中使用这段本机代码在Safari中打开外部网址

- (BOOL) webView:(UIWebView*)theWebView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType
{
    //return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
    NSURL *url = [request URL];

    // Intercept the external http requests and forward to Safari.app
    // Otherwise forward to the PhoneGap WebView
    if ([[url scheme] isEqualToString:@"http"] || [[url scheme] isEqualToString:@"https"] || [[url scheme] isEqualToString:@"itms-apps"]) {
        [[UIApplication sharedApplication] openURL:url];
        return NO;
    }
    else {
        return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
    }
}

Answer 2

此适用于2.3.0 oO'

- (BOOL) webView:(UIWebView*)theWebView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType{
//return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
NSURL *url = [request URL];

// Intercept the external http requests and forward to Safari.app
// Otherwise forward to the PhoneGap WebView
if ([[url scheme] isEqualToString:@"http"] || [[url scheme] isEqualToString:@"https"] || [[url scheme] isEqualToString:@"itms-apps"]) {
    [[UIApplication sharedApplication] openURL:url];
    return NO;
}
else {
    return [ super webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType ];
}}

在safari中的cordova mac打开URL

2 个答案: