你好,我有2个数组,我想把它们放在一个字符串中。我的数组可以取值从0到maxNum-1。所以我要说myArray1 [i]和myArray2 [i] 我想制作一个这样的字符串:
string = "myArray1ID" + 1 + "=" + (myArray1[1])
+ "&" +"myArray2ID" + 1 + "=" + (myArray2[1])
+ "&" + "myArray1ID" + 2 + "=" + (myArray1[2])
+ "&" + "myArray2ID" + 2 + "=" + (myArray2[2])
+ ......
+ "myArray1ID" + (maxNum - 1) + "=" + (myArray[maxNum-1])
+ "&" "myArray2ID" + (maxNum - 1) + "=" + (myArray2[maxNum-1]);
有可能吗?
答案 0 :(得分:3)
使用循环的力量。
var output = [];
for (var i = 1; i < maxNum; ++i) {
output.push(
'myArray1ID' + i + '=' + myArray1[i],
'myArray2ID' + i + '=' + myArray2[i]
);
}
return output.join('&');
答案 1 :(得分:1)
var myString = '';
for(var i; i < myArray1.length; i++){
myString += "myArray1ID" + i + "=" + (myArray1[i]) + "&";
myString += "myArray2ID" + i + "=" + (myArray2[i]) + "&";
}
//remove trialing "&"
var myString = myString.substring(0, myString.length-1);
这假设两个数组的长度相等
答案 2 :(得分:0)
使用循环:
var stringArray = sep = "";
for(var i = 1; i < maxNum; i++) {
stringArray += sep + "myArray1ID" + i + "=" + myArray1[i];
stringArray += "&myArray2ID" + i + "=" + myArray2[i];
sep = "&";
}
var stringArray
应包含您的数组值。