我需要解析RSS提要(XML版本2.0)并在HTML页面中显示已解析的详细信息。
答案 0 :(得分:212)
(不要真的推荐那个,请参阅其他选项。)
jQuery.getFeed({
url : FEED_URL,
success : function (feed) {
console.log(feed.title);
// do more stuff here
}
});
$.get(FEED_URL, function (data) {
$(data).find("entry").each(function () { // or "item" or whatever suits your feed
var el = $(this);
console.log("------------------------");
console.log("title : " + el.find("title").text());
console.log("author : " + el.find("author").text());
console.log("description: " + el.find("description").text());
});
});
$.ajax({
url : document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=10&callback=?&q=' + encodeURIComponent(FEED_URL),
dataType : 'json',
success : function (data) {
if (data.responseData.feed && data.responseData.feed.entries) {
$.each(data.responseData.feed.entries, function (i, e) {
console.log("------------------------");
console.log("title : " + e.title);
console.log("author : " + e.author);
console.log("description: " + e.description);
});
}
}
});
但这意味着你很依赖他们在线和可以上网。
成功从Feed中提取所需信息后,您可以创建DocumentFragment
s(document.createDocumentFragment()
包含您想要的元素(使用document.createElement()
创建)注入以显示您的数据。
在页面上选择所需的容器元素并将文档片段附加到其上,然后使用innerHTML完全替换其内容。
类似的东西:
$('#rss-viewer').append(aDocumentFragmentEntry);
或:
$('#rss-viewer')[0].innerHTML = aDocumentFragmentOfAllEntries.innerHTML;
使用此question's feed,在撰写本文时提供:
<?xml version="1.0" encoding="utf-8"?>
<feed xmlns="http://www.w3.org/2005/Atom" xmlns:creativeCommons="http://backend.userland.com/creativeCommonsRssModule" xmlns:re="http://purl.org/atompub/rank/1.0">
<title type="text">How to parse a RSS feed using javascript? - Stack Overflow</title>
<link rel="self" href="https://stackoverflow.com/feeds/question/10943544" type="application/atom+xml" />
<link rel="hub" href="http://pubsubhubbub.appspot.com/" />
<link rel="alternate" href="https://stackoverflow.com/q/10943544" type="text/html" />
<subtitle>most recent 30 from stackoverflow.com</subtitle>
<updated>2012-06-08T06:36:47Z</updated>
<id>https://stackoverflow.com/feeds/question/10943544</id>
<creativeCommons:license>http://www.creativecommons.org/licenses/by-sa/3.0/rdf</creativeCommons:license>
<entry>
<id>https://stackoverflow.com/q/10943544</id>
<re:rank scheme="http://stackoverflow.com">2</re:rank>
<title type="text">How to parse a RSS feed using javascript?</title>
<category scheme="https://stackoverflow.com/feeds/question/10943544/tags" term="javascript"/><category scheme="https://stackoverflow.com/feeds/question/10943544/tags" term="html5"/><category scheme="https://stackoverflow.com/feeds/question/10943544/tags" term="jquery-mobile"/>
<author>
<name>Thiru</name>
<uri>https://stackoverflow.com/users/1126255</uri>
</author>
<link rel="alternate" href="https://stackoverflow.com/questions/10943544/how-to-parse-a-rss-feed-using-javascript" />
<published>2012-06-08T05:34:16Z</published>
<updated>2012-06-08T06:35:22Z</updated>
<summary type="html">
<p>I need to parse the RSS-Feed(XML version2.0) using XML and I want to display the parsed detail in HTML page, I tried in many ways. But its not working. My system is running under proxy, since I am new to this field, I don't know whether it is possible or not. If any one knows please help me on this. Thanks in advance.</p>
</summary>
</entry>
<entry>
<id>https://stackoverflow.com/questions/10943544/-/10943610#10943610</id>
<re:rank scheme="http://stackoverflow.com">1</re:rank>
<title type="text">Answer by haylem for How to parse a RSS feed using javascript?</title>
<author>
<name>haylem</name>
<uri>https://stackoverflow.com/users/453590</uri>
</author>
<link rel="alternate" href="https://stackoverflow.com/questions/10943544/how-to-parse-a-rss-feed-using-javascript/10943610#10943610" />
<published>2012-06-08T05:43:24Z</published>
<updated>2012-06-08T06:35:22Z</updated>
<summary type="html"><h1>Parsing the Feed</h1>
<h3>With jQuery's jFeed</h3>
<p>Try this, with the <a href="http://plugins.jquery.com/project/jFeed" rel="nofollow">jFeed</a> <a href="http://www.jquery.com/" rel="nofollow">jQuery</a> plug-in</p>
<pre><code>jQuery.getFeed({
url : FEED_URL,
success : function (feed) {
console.log(feed.title);
// do more stuff here
}
});
</code></pre>
<h3>With jQuery's Built-in XML Support</h3>
<pre><code>$.get(FEED_URL, function (data) {
$(data).find("entry").each(function () { // or "item" or whatever suits your feed
var el = $(this);
console.log("------------------------");
console.log("title : " + el.find("title").text());
console.log("author : " + el.find("author").text());
console.log("description: " + el.find("description").text());
});
});
</code></pre>
<h3>With jQuery and the Google AJAX APIs</h3>
<p>Otherwise, <a href="https://developers.google.com/feed/" rel="nofollow">Google's AJAX Feed API</a> allows you to get the feed as a JSON object:</p>
<pre><code>$.ajax({
url : document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&amp;num=10&amp;callback=?&amp;q=' + encodeURIComponent(FEED_URL),
dataType : 'json',
success : function (data) {
if (data.responseData.feed &amp;&amp; data.responseData.feed.entries) {
$.each(data.responseData.feed.entries, function (i, e) {
console.log("------------------------");
console.log("title : " + e.title);
console.log("author : " + e.author);
console.log("description: " + e.description);
});
}
}
});
</code></pre>
<p>But that means you're relient on them being online and reachable.</p>
<hr>
<h1>Building Content</h1>
<p>Once you've successfully extracted the information you need from the feed, you need to create document fragments containing the elements you'll want to inject to display your data.</p>
<hr>
<h1>Injecting the content</h1>
<p>Select the container element that you want on the page and append your document fragments to it, and simply use innerHTML to replace its content entirely.</p>
</summary>
</entry></feed>
调用:
$.get('https://stackoverflow.com/feeds/question/10943544', function (data) {
$(data).find("entry").each(function () { // or "item" or whatever suits your feed
var el = $(this);
console.log("------------------------");
console.log("title : " + el.find("title").text());
console.log("author : " + el.find("author").text());
console.log("description: " + el.find("description").text());
});
});
打印出来:
------------------------
title : How to parse a RSS feed using javascript?
author :
Thiru
https://stackoverflow.com/users/1126255
description:
------------------------
title : Answer by haylem for How to parse a RSS feed using javascript?
author :
haylem
https://stackoverflow.com/users/453590
description:
调用:
$.ajax({
url : document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=10&callback=?&q=' + encodeURIComponent('https://stackoverflow.com/feeds/question/10943544'),
dataType : 'json',
success : function (data) {
if (data.responseData.feed && data.responseData.feed.entries) {
$.each(data.responseData.feed.entries, function (i, e) {
console.log("------------------------");
console.log("title : " + e.title);
console.log("author : " + e.author);
console.log("description: " + e.description);
});
}
}
});
打印出来:
------------------------
title : How to parse a RSS feed using javascript?
author : Thiru
description: undefined
------------------------
title : Answer by haylem for How to parse a RSS feed using javascript?
author : haylem
description: undefined
答案 1 :(得分:39)
另一个已弃用 (感谢@daylight)选项,对我来说最简单(这是我用于SpokenToday.info的内容):
Google Feed API没有使用JQuery,只有两步:
导入库:
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">google.load("feeds", "1");</script>
查找/加载供稿(documentation):
var feed = new google.feeds.Feed('http://www.google.com/trends/hottrends/atom/feed?pn=p1');
feed.load(function (data) {
// Parse data depending on the specified response format, default is JSON.
console.dir(data);
});
要解析数据,请检查documentation about the response format。
答案 2 :(得分:2)
不幸的是,对于其他人(从2019年开始)阅读本文档,大多数JS RSS阅读实施现在都无法使用。首先,Google API已关闭,因此这不再是一种选择,并且由于CORS安全策略,您现在通常无法跨域请求RSS源。
Access to XMLHttpRequest at 'https://feeds.feedburner.com/raymondcamdensblog?format=xml' from origin 'MYSITE' has been blocked by CORS policy: No 'Access-Control-Allow-Origin' header is present on the requested resource.
这是正确的,也是最终网站的安全预防措施,但现在确实意味着上述答案不太可能。
我的解决方法可能是通过PHP解析RSS feed,并允许javascript访问我的PHP,而不是尝试访问最终目标feed本身。
答案 3 :(得分:1)
如果您正在为rss小部件寻找Google Feed API的简单且免费的替代方案,那么 rss2json.com 可能是一个合适的解决方案
您可以尝试查看以下 api documentation 中的示例代码的工作原理:
google.load("feeds", "1");
function initialize() {
var feed = new google.feeds.Feed("https://news.ycombinator.com/rss");
feed.load(function(result) {
if (!result.error) {
var container = document.getElementById("feed");
for (var i = 0; i < result.feed.entries.length; i++) {
var entry = result.feed.entries[i];
var div = document.createElement("div");
div.appendChild(document.createTextNode(entry.title));
container.appendChild(div);
}
}
});
}
google.setOnLoadCallback(initialize);
<html>
<head>
<script src="https://rss2json.com/gfapi.js"></script>
</head>
<body>
<p><b>Result from the API:</b></p>
<div id="feed"></div>
</body>
</html>
答案 4 :(得分:1)
我被许多误导性的文章和答案所激怒,以至于我写了自己的RSS阅读器: https://gouessej.wordpress.com/2020/06/28/comment-creer-un-lecteur-rss-en-javascript-how-to-create-a-rss-reader-in-javascript/
您可以使用AJAX请求来获取RSS文件,但是只有当您使用CORS代理时,它才能工作。我将尝试编写自己的CORS代理,以为您提供更强大的解决方案。同时,它可以正常工作,我将其部署在Debian Linux下的服务器上。
我的解决方案不使用JQuery,我仅使用无第三方库的普通Javascript标准API,并且即使在Microsoft Internet Explorer 11中也可以使用。
答案 5 :(得分:0)
如果您想使用普通的javascript API,请在https://github.com/hongkiat/js-rss-reader/
处举一个很好的例子。https://www.hongkiat.com/blog/rss-reader-in-javascript/
的完整描述它使用fetch
方法作为异步获取资源的全局方法。下面是一段代码:
fetch(websiteUrl).then((res) => {
res.text().then((htmlTxt) => {
var domParser = new DOMParser()
let doc = domParser.parseFromString(htmlTxt, 'text/html')
var feedUrl = doc.querySelector('link[type="application/rss+xml"]').href
})
}).catch(() => console.error('Error in fetching the website'))
答案 6 :(得分:0)
您可以使用jquery-rss或Vanilla RSS,它们带有漂亮的模板并且非常易于使用:
// Example for jquery.rss
$("#your-div").rss("https://stackoverflow.com/feeds/question/10943544", {
limit: 3,
layoutTemplate: '<ul class="inline">{entries}</ul>',
entryTemplate: '<li><a href="{url}">[{author}@{date}] {title}</a><br/>{shortBodyPlain}</li>'
})
// Example for Vanilla RSS
const RSS = require('vanilla-rss');
const rss = new RSS(
document.querySelector("#your-div"),
"https://stackoverflow.com/feeds/question/10943544",
{
// options go here
}
);
rss.render().then(() => {
console.log('Everything is loaded and rendered');
});
有关有效的示例,请参见http://jsfiddle.net/sdepold/ozq2dn9e/1/。
答案 7 :(得分:0)
现在试图为这个问题找到一个好的解决方案,我碰巧遇到了FeedEk jQuery RSS/ATOM Feed Plugin,它通过jQuery Feed API很好地解析和显示RSS和Atom提要。对于基本的基于XML的RSS提要,我发现它的工作原理很吸引人,不需要服务器端脚本或其他CORS解决方法,就可以在本地运行。