Question

这是我想要实现的目标：我想要替换

void some_function(int,  int *, float);

带

void some_function(int a, int *b, float c);

到目前为止，我试图用chr（97 + i）替换“，”，因为我循环遍历字符串。

text = len("void some_function(int,  int *, float);")
i = 0
for j in range(0, length)
    if text[j] == ",":
       rep = " " + chr(97+i) + " .,"
       text = text.replace("," rep)
       i = i + 1
       j = 0 # resetting the index, but this time I want to find the next occurrence of "," which I am not sure

但这不是在做这项工作。如果有更好的方法，请告诉我。

Answer 1

import re

i = 96
def replace(matches):
    global i
    i += 1
    return " " + chr(i) + matches.group(0)

re.sub(',|\)', replace, "void some_function(int,  int *, float);")

Answer 2

text = "void some_function(int,  int *, float);".replace(',', '%s,') % (' a', 'b')

Answer 3

最初的想法不起作用，因为最后一个参数后面没有'，'而是'''。

import re
import string

def fix(text):
    n = len(re.findall('[,(]', text))
    return re.sub('([,)])', ' %s\\1', text) % tuple(string.letters[:n])

使用python在字符串中插入字符

3 个答案: