我有一行包含地址示例“GILBERT AZ 85234-4512”的一部分。我想删除除85234之外的所有内容。因此删除所有字符但数字只保留5位数字。
这需要在循环中完成,因为我有1500多条记录。如果它没有太大的麻烦,它也可以删除任何遗留空间。
答案 0 :(得分:1)
使用RegExp
和变量数组(因为范围循环可能非常慢),这将最有效地完成。
Sub KillNums()
Dim rng1 As Range
Dim rngArea As Range
Dim lngRow As Long
Dim lngCol As Long
Dim lngCalc As Long
Dim objReg As Object
Dim X()
On Error Resume Next
Set rng1 = Application.InputBox("Select range for the replacement of leading zeros", "User select", Selection.Address, , , , , 8)
If rng1 Is Nothing Then Exit Sub
On Error GoTo 0
'See Patrick Matthews excellent article on using Regular Expressions with VBA
Set objReg = CreateObject("vbscript.regexp")
objReg.Pattern = "^.+?(\d+)\-.*$"
'Speed up the code by turning off screenupdating and setting calculation to manual
'Disable any code events that may occur when writing to cells
With Application
lngCalc = .Calculation
.ScreenUpdating = False
.Calculation = xlCalculationManual
.EnableEvents = False
End With
'Test each area in the user selected range
'Non contiguous range areas are common when using SpecialCells to define specific cell types to work on
For Each rngArea In Intersect(rng1, ActiveSheet.UsedRange).Areas
'The most common outcome is used for the True outcome to optimise code speed
If rngArea.Cells.Count > 1 Then
'If there is more than once cell then set the variant array to the dimensions of the range area
'Using Value2 provides a useful speed improvement over Value. On my testing it was 2% on blank cells, up to 10% on non-blanks
X = rngArea.Value2
For lngRow = 1 To rngArea.Rows.Count
For lngCol = 1 To rngArea.Columns.Count
'replace the leading zeroes
X(lngRow, lngCol) = objReg.Replace(X(lngRow, lngCol), "$1")
Next lngCol
Next lngRow
'Dump the updated array back over the initial range
rngArea.Value2 = X
Else
'caters for a single cell range area. No variant array required
rngArea.Value = objReg.Replace(rngArea.Value, "$1")
End If
Next rngArea
'cleanup the Application settings
With Application
.ScreenUpdating = True
.Calculation = lngCalc
.EnableEvents = True
End With
Set objReg = Nothing
End Sub
答案 1 :(得分:0)
快速方法是选择单元格并选择查找 - 替换(Ctrl + H)。
首先将-*
替换为空,然后替换为*
(包括空格)。
这取决于您的数据是否一致格式化,因此请检查结果并在必要时使用undo / redo。
答案 2 :(得分:0)
除非其他地址中有“ - ”,否则这应该有用。
已更新 :我对zipcodes中没有“ - ”的情况进行了更改
Sub findZip()
Dim hyphen As String
Dim zip As String
For Each cell In Range("A2:A1501")
hyphen = InStr(1, cell, "-")
If hyphen <> 0 Then
zip = Trim(Mid(cell, hyphen - 5, 5))
Else: zip = Right(Trim(cell), 5)
End If
cell.Offset(0, 1) = zip
Next
End Sub