如何在PostgreSQL中使用psql命令执行等效的Oracle DESCRIBE TABLE
?
答案 0 :(得分:2579)
答案 1 :(得分:659)
除了PostgreSQL方式(\ d'thing'或\ dt'table'或\ ds'sequence'等等)
SQL标准方式,如here所示:
select column_name, data_type, character_maximum_length
from INFORMATION_SCHEMA.COLUMNS where table_name = '<name of table>';
它受到许多数据库引擎的支持。
答案 2 :(得分:64)
如果要从查询而不是psql获取它,可以查询目录模式。这是一个复杂的查询:
SELECT
f.attnum AS number,
f.attname AS name,
f.attnum,
f.attnotnull AS notnull,
pg_catalog.format_type(f.atttypid,f.atttypmod) AS type,
CASE
WHEN p.contype = 'p' THEN 't'
ELSE 'f'
END AS primarykey,
CASE
WHEN p.contype = 'u' THEN 't'
ELSE 'f'
END AS uniquekey,
CASE
WHEN p.contype = 'f' THEN g.relname
END AS foreignkey,
CASE
WHEN p.contype = 'f' THEN p.confkey
END AS foreignkey_fieldnum,
CASE
WHEN p.contype = 'f' THEN g.relname
END AS foreignkey,
CASE
WHEN p.contype = 'f' THEN p.conkey
END AS foreignkey_connnum,
CASE
WHEN f.atthasdef = 't' THEN d.adsrc
END AS default
FROM pg_attribute f
JOIN pg_class c ON c.oid = f.attrelid
JOIN pg_type t ON t.oid = f.atttypid
LEFT JOIN pg_attrdef d ON d.adrelid = c.oid AND d.adnum = f.attnum
LEFT JOIN pg_namespace n ON n.oid = c.relnamespace
LEFT JOIN pg_constraint p ON p.conrelid = c.oid AND f.attnum = ANY (p.conkey)
LEFT JOIN pg_class AS g ON p.confrelid = g.oid
WHERE c.relkind = 'r'::char
AND n.nspname = '%s' -- Replace with Schema name
AND c.relname = '%s' -- Replace with table name
AND f.attnum > 0 ORDER BY number
;
它非常复杂,但它确实向您展示了PostgreSQL系统目录的强大功能和灵活性,并且可以帮助您实现pg_catalog掌握;-)。请务必更改查询中的%s。第一个是Schema,第二个是表名。
答案 3 :(得分:46)
您可以使用psql斜杠命令执行此操作:
\d myTable describe table
它也适用于其他对象:
\d myView describe view
\d myIndex describe index
\d mySequence describe sequence
来源:faqs.org
答案 4 :(得分:33)
与DESCRIBE TABLE
等效的psql为\d table
。
有关详细信息,请参阅PostgreSQL手册的psql部分。
答案 5 :(得分:20)
您可以使用星号执行\d *search pattern *
,以查找与您感兴趣的搜索模式相匹配的表格。
答案 6 :(得分:13)
除了您已找到的命令行\d+ <table_name>
之外,您还可以使用information-schema使用info_schema.columns
SELECT *
FROM info_schema.columns
WHERE table_schema = 'your_schema'
AND table_name = 'your_table'
答案 7 :(得分:12)
您可以使用:
SELECT attname
FROM pg_attribute,pg_class
WHERE attrelid=pg_class.oid
AND relname='TableName'
AND attstattarget <>0;
答案 8 :(得分:10)
使用以下SQL语句
SELECT DATA_TYPE
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_name = 'tbl_name'
AND COLUMN_NAME = 'col_name'
如果替换tbl_name和col_name,它会显示您要查找的特定coloumn的数据类型。
答案 9 :(得分:7)
查询的这种变化(如其他答案中所述)对我有用。
if some_queryset.exists():
print("There is at least one object in some_queryset")
这里详细描述: http://www.postgresqltutorial.com/postgresql-describe-table/
答案 10 :(得分:6)
这应该是解决方案:
SELECT * FROM information_schema.columns
WHERE table_schema = 'your_schema'
AND table_name = 'your_table'
答案 11 :(得分:6)
在 MySQL 中,DESCRIBE table_name
在 PostgreSQL ,\ d table_name
中或者,你可以使用这个长命令:
SELECT
a.attname AS Field,
t.typname || '(' || a.atttypmod || ')' AS Type,
CASE WHEN a.attnotnull = 't' THEN 'YES' ELSE 'NO' END AS Null,
CASE WHEN r.contype = 'p' THEN 'PRI' ELSE '' END AS Key,
(SELECT substring(pg_catalog.pg_get_expr(d.adbin, d.adrelid), '\'(.*)\'')
FROM
pg_catalog.pg_attrdef d
WHERE
d.adrelid = a.attrelid
AND d.adnum = a.attnum
AND a.atthasdef) AS Default,
'' as Extras
FROM
pg_class c
JOIN pg_attribute a ON a.attrelid = c.oid
JOIN pg_type t ON a.atttypid = t.oid
LEFT JOIN pg_catalog.pg_constraint r ON c.oid = r.conrelid
AND r.conname = a.attname
WHERE
c.relname = 'tablename'
AND a.attnum > 0
ORDER BY a.attnum
答案 12 :(得分:5)
为改进另一个答案的SQL查询(太好了!),这是一个经过修改的查询。它还包括约束名称,继承信息以及分解为组成部分的数据类型(类型,长度,精度,小数位数)。它还过滤掉已删除的列(数据库中仍然存在)。
$start = $_GET['start'];
$per_page = 60;
//count recoreds
$data = $db->query("SELECT * FROM artists");
$record_count= $data->rowCount();
//count max pages
$max_pages = $record_count / $per_page;
//may come out as a decimal
if (!$start)
$start = 0;
$sth = $db->prepare("SELECT * FROM artists ORDER BY name LIMIT ?,?");
$sth->execute(array($start,$per_page));
foreach($sth as $info) { //return content }
答案 13 :(得分:3)
答案 14 :(得分:2)
描述表格的最佳方式,例如列,类型,列的修饰符等。
\d+ tablename or \d tablename
答案 15 :(得分:2)
有很多方法可以在PostgreSQL中描述表
简单的答案是
> /d <table_name> -- OR
> /d+ <table_name>
用法
如果您位于Postgres shell [
psql
]中,则需要描述表格
您也可以通过查询来实现这一目标[很多朋友已经发布了正确的方法]
Postgres的默认表名称information_schema
中提供了有关该模式的许多详细信息。
您可以使用简单的SQL语句直接使用它来检索任何表的信息。
简单查询
SELECT
*
FROM
information_schema.columns
WHERE
table_schema = 'your_schema' AND
table_name = 'your_table';
中等查询
SELECT
a.attname AS Field,
t.typname || '(' || a.atttypmod || ')' AS Type,
CASE WHEN a.attnotnull = 't' THEN 'YES' ELSE 'NO' END AS Null,
CASE WHEN r.contype = 'p' THEN 'PRI' ELSE '' END AS Key,
(SELECT substring(pg_catalog.pg_get_expr(d.adbin, d.adrelid), '\'(.*)\'')
FROM
pg_catalog.pg_attrdef d
WHERE
d.adrelid = a.attrelid
AND d.adnum = a.attnum
AND a.atthasdef) AS Default,
'' as Extras
FROM
pg_class c
JOIN pg_attribute a ON a.attrelid = c.oid
JOIN pg_type t ON a.atttypid = t.oid
LEFT JOIN pg_catalog.pg_constraint r ON c.oid = r.conrelid
AND r.conname = a.attname
WHERE
c.relname = 'tablename'
AND a.attnum > 0
ORDER BY a.attnum
您只需要替换tablename
。
硬查询
SELECT
f.attnum AS number,
f.attname AS name,
f.attnum,
f.attnotnull AS notnull,
pg_catalog.format_type(f.atttypid,f.atttypmod) AS type,
CASE
WHEN p.contype = 'p' THEN 't'
ELSE 'f'
END AS primarykey,
CASE
WHEN p.contype = 'u' THEN 't'
ELSE 'f'
END AS uniquekey,
CASE
WHEN p.contype = 'f' THEN g.relname
END AS foreignkey,
CASE
WHEN p.contype = 'f' THEN p.confkey
END AS foreignkey_fieldnum,
CASE
WHEN p.contype = 'f' THEN g.relname
END AS foreignkey,
CASE
WHEN p.contype = 'f' THEN p.conkey
END AS foreignkey_connnum,
CASE
WHEN f.atthasdef = 't' THEN d.adsrc
END AS default
FROM pg_attribute f
JOIN pg_class c ON c.oid = f.attrelid
JOIN pg_type t ON t.oid = f.atttypid
LEFT JOIN pg_attrdef d ON d.adrelid = c.oid AND d.adnum = f.attnum
LEFT JOIN pg_namespace n ON n.oid = c.relnamespace
LEFT JOIN pg_constraint p ON p.conrelid = c.oid AND f.attnum = ANY (p.conkey)
LEFT JOIN pg_class AS g ON p.confrelid = g.oid
WHERE c.relkind = 'r'::char
AND n.nspname = 'schema' -- Replace with Schema name
AND c.relname = 'tablename' -- Replace with table name
AND f.attnum > 0 ORDER BY number;
您可以选择上述任何一种方式来描述表格。
任何人都可以编辑这些答案以改进方法。我愿意合并您的更改。 :)
答案 16 :(得分:1)
In postgres \d is used to describe the table structure.
e.g. \d schema_name.table_name;
this command will provide you the basic info of table such as, columns, type and modifiers.
If you want more info about table use
\d+ schema_name.table_name;
this will give you extra info such as, storage, stats target and description
答案 17 :(得分:1)
1)使用psql的PostgreSQL DESCRIBE TABLE
在psql命令行工具中, \ d table_name 或 \ d + table_name 可以找到表列的信息
2)使用information_schema的PostgreSQL描述表
用于查询information_schema数据库中列表的column_names,数据类型,字符最大长度的SELECT语句;
选择 COLUMN_NAME,DATA_TYPE,CHARACTER_MAXIMUM_LENGTH 来自INFORMATION_SCHEMA.COLUMNS,其中table_name ='tablename';
有关更多信息,https://www.postgresqltutorial.com/postgresql-describe-table/
答案 18 :(得分:1)
Use this command
\d table name
like
\d queuerecords
Table "public.queuerecords"
Column | Type | Modifiers
-----------+-----------------------------+-----------
id | uuid | not null
endtime | timestamp without time zone |
payload | text |
queueid | text |
starttime | timestamp without time zone |
status | text |
答案 19 :(得分:0)
当表不属于默认架构时,应输入:
\d+ schema_name.table_name
否则,您将收到错误消息,指出“该关系不存在。”
答案 20 :(得分:-2)
/ dt是commad,它列出了数据库中存在的所有表。使用
/ d命令和/ d +我们可以获取表的详细信息。 sysntax就像是
* / d table_name(或)\ d + table_name
答案 21 :(得分:-4)
I worked out the following script for get table schema.
'CREATE TABLE ' || 'yourschema.yourtable' || E'\n(\n' ||
array_to_string(
array_agg(
' ' || column_expr
)
, E',\n'
) || E'\n);\n'
from
(
SELECT ' ' || column_name || ' ' || data_type ||
coalesce('(' || character_maximum_length || ')', '') ||
case when is_nullable = 'YES' then ' NULL' else ' NOT NULL' end as column_expr
FROM information_schema.columns
WHERE table_schema || '.' || table_name = 'yourschema.yourtable'
ORDER BY ordinal_position
) column_list;