Question

我正在尝试将xml解析为对象的层次结构，而我不确定如何正确地递归层次结构。我确实有一个粗略的解决方案（不是一个好的解决方案），它是对GetChild的调用，它解析XElement并返回一个集合。我希望有人知道如何在纯粹的linq表达式中实现这一点，即。将Parent-Child-Item关系填充到List中，而不调用GetChild（）

之类的函数

由于

var element = XElement.Parse(@"<Root RegisterVersion='1.0' xmlns='http://www.test.com.au/docs/schemas' xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:schemaLocation='http://www.test.com/docs/schemas/spin/surcharge http://www.test.com/docs/schemas/test.xsd'>
                            <Parent id='1' name='parent1'>
                                <Child id='1' name='child1'>
                                    <Item id='1' name='someitem'></Item>
                                </Child>
                            </Parent>
                            <Parent id='2' name='parent2'>
                                <Child id='2' name='child2'>
                                    <Item id='2' name='someotheritem'></Item>
                                </Child>
                            </Parent>
                            </Root>
                            ");

XNamespace ns = element.Name.Namespace;

var list =
 from compileItem in element.Elements (ns + "Parent") 
 select new Parent
 {
    Id = compileItem.Attribute("id").Value.ToString(),
    Name = compileItem.Attribute("name").Value.ToString(),
    children = GetChild(compileItem)
            // this call here I'd like to replace with another linq select
 };

 public List<Child> GetChild(XElement frag)
 {
           //etc 
 }
 public List<Item> GetItem(XElement frag)
 { 
        //etc
 }

Answer 1

小控制台app.Honestly，它的功能更具可读性。

public class Parent
    {
        public int Id { get; set; }
        public string Name { get; set; }
        public List<Child> Childrens { get; set; }
    }

    public class Child
    {
        public int Id { get; set; }
        public string Name { get; set; }
        public List<Item> Items { get; set; }
    }
    public class Item
    {
        public int Id { get; set; }
        public string Name { get; set; }
    }

    internal class Program
    {
        private class ADSetupInformation
        {
            public static void Main()
            {

                var element =
                    XElement.Parse(
                        @"<Root RegisterVersion='1.0' xmlns='http://www.test.com.au/docs/schemas' xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:schemaLocation='http://www.test.com/docs/schemas/spin/surcharge http://www.test.com/docs/schemas/test.xsd'>
                            <Parent id='1' name='parent1'>
                                <Child id='1' name='child1'>
                                    <Item id='1' name='someitem'></Item>
                                </Child>
                            </Parent>
                            <Parent id='2' name='parent2'>
                                <Child id='2' name='child2'>
                                    <Item id='2' name='someotheritem'></Item>
                                </Child>
                            </Parent>
                            </Root>
                            ");

                XNamespace ns = element.Name.Namespace;


var list =
                    element.Elements(ns + "Parent")
                        .Select(compileItem => new Parent
                                                   {
                                                       Id = Convert.ToInt32(compileItem.Attribute("id").Value),
                                                       Name = compileItem.Attribute("name").Value,
                                                       Childrens = compileItem.Elements(ns + "Child")
                                                           .Select(child => new Child
                                                                                {
                                                                                    Id = Convert.ToInt32(child.Attribute("id").Value),
                                                                                    Name = child.Attribute("name").Value,
                                                                                    Items = child.Elements(ns + "Item")
                                                                                        .Select(xe => new Item()
                                                                                                          {
                                                                                                              Id = Convert.ToInt32(xe.Attribute("id").Value),
                                                                                                              Name = xe.Attribute("name").Value,
                                                                                                          }).ToList()
                                                                                }).ToList()                             
                                                   });

如何仅使用linq将xml解析为对象树？

1 个答案: