是否可以使用带有Rails的RSpec测试给定布局的使用,例如我想要一个执行以下操作的匹配器:
response.should use_layout('my_layout_name')
我在谷歌搜索时发现了一个use_layout匹配器,但它不起作用,因为响应或控制器似乎都没有匹配器正在寻找的布局属性。
答案 0 :(得分:56)
David Chelimsky在Ruby Forum上发表了一个很好的答案:
response.should render_template("layouts/some_layout")
答案 1 :(得分:16)
这适用于我在Rails上使用边缘Rails和边缘RSpec:
response.layout.should == 'layouts/application'
不应该把它变成适合你的匹配器。
答案 2 :(得分:15)
已经有一个功能完善的匹配器:
response.should render_template(:layout => 'fooo')
(Rspec 2.6.4)
答案 3 :(得分:7)
我找到了一个how to write a use_layout
matcher的例子。以下是链接消失的代码:
# in spec_helper.rb
class UseLayout
def initialize(expected)
@expected = 'layouts/' + expected
end
def matches?(controller)
@actual = controller.layout
#@actual.equal?(@expected)
@actual == @expected
end
def failure_message
return "use_layout expected #{@expected.inspect}, got #
{@actual.inspect}", @expected, @actual
end
def negeative_failure_message
return "use_layout expected #{@expected.inspect} not to equal #
{@actual.inspect}", @expected, @actual
end
end
def use_layout(expected)
UseLayout.new(expected)
end
# in controller spec
response.should use_layout("application")
答案 4 :(得分:5)
我必须编写以下内容才能完成这项工作:
response.should render_template("layouts/some_folder/some_layout", "template-name")
答案 5 :(得分:2)
这是匹配器的更新版本。我已经更新它以符合最新版本的RSpec。我添加了相关的只读属性并删除了旧的返回格式。
# in spec_helper.rb
class UseLayout
attr_reader :expected
attr_reader :actual
def initialize(expected)
@expected = 'layouts/' + expected
end
def matches?(controller)
if controller.is_a?(ActionController::Base)
@actual = 'layouts/' + controller.class.read_inheritable_attribute(:layout)
else
@actual = controller.layout
end
@actual ||= "layouts/application"
@actual == @expected
end
def description
"Determines if a controller uses a layout"
end
def failure_message
return "use_layout expected #{@expected.inspect}, got #{@actual.inspect}"
end
def negeative_failure_message
return "use_layout expected #{@expected.inspect} not to equal #{@actual.inspect}"
end
end
def use_layout(expected)
UseLayout.new(expected)
end
此外,匹配器现在也可以使用在控制器类级别指定的布局,可以按如下方式使用:
class PostsController < ApplicationController
layout "posts"
end
在控制器规范中,您只需使用:
it { should use_layout("posts") }
答案 6 :(得分:2)
这是我最终选择的解决方案。它用于rpsec 2和rails 3.
我刚刚在spec / support目录中添加了这个文件。
链接是:https://gist.github.com/971342
# spec/support/matchers/render_layout.rb
ActionView::Base.class_eval do unless instance_methods.include?('_render_layout_with_tracking') def _render_layout_with_tracking(layout, locals, &block) controller.instance_variable_set(:@_rendered_layout, layout) _render_layout_without_tracking(layout, locals, &block) end alias_method_chain :_render_layout, :tracking end end
# You can use this matcher anywhere that you have access to the controller instance, # like in controller or integration specs. # # == Example Usage # # Expects no layout to be rendered: # controller.should_not render_layout # Expects any layout to be rendered: # controller.should render_layout # Expects app/views/layouts/application.html.erb to be rendered: # controller.should render_layout('application') # Expects app/views/layouts/application.html.erb not to be rendered: # controller.should_not render_layout('application') # Expects app/views/layouts/mobile/application.html.erb to be rendered: # controller.should_not render_layout('mobile/application') RSpec::Matchers.define :render_layout do |*args| expected = args.first match do |c| actual = get_layout(c) if expected.nil? !actual.nil? # actual must be nil for the test to pass. Usage: should_not render_layout elsif actual actual == expected.to_s else false end end
failure_message_for_should do |c| actual = get_layout(c) if actual.nil? && expected.nil? "expected a layout to be rendered but none was" elsif actual.nil? "expected layout #{expected.inspect} but no layout was rendered" else "expected layout #{expected.inspect} but #{actual.inspect} was rendered" end end
failure_message_for_should_not do |c| actual = get_layout(c) if expected.nil? "expected no layout but #{actual.inspect} was rendered" else "expected #{expected.inspect} not to be rendered but it was" end end
def get_layout(controller) if template = controller.instance_variable_get(:@_rendered_layout) template.virtual_path.sub(/layouts\//, '') end end end
答案 7 :(得分:1)
controller.active_layout.name
适合我。
答案 8 :(得分:1)
response.should render_template("layouts/some_folder/some_layout")
response.should render_template("template-name")
答案 9 :(得分:0)
这是dmcnally代码的一个版本,它允许不传递任何参数,使“should use_layout”和“should_not use_layout”工作(断言控制器分别使用任何布局,或者没有布局 - 我期望只有第二个有用,因为如果它使用布局,你应该更具体:)
class UseLayout
def initialize(expected = nil)
if expected.nil?
@expected = nil
else
@expected = 'layouts/' + expected
end
end
def matches?(controller)
@actual = controller.layout
#@actual.equal?(@expected)
if @expected.nil?
@actual
else
@actual == @expected
end
end
def failure_message
if @expected.nil?
return 'use_layout expected a layout to be used, but none was', 'any', @actual
else
return "use_layout expected #{@expected.inspect}, got #{@actual.inspect}", @expected, @actual
end
end
def negative_failure_message
if @expected.nil?
return "use_layout expected no layout to be used, but #{@actual.inspect} found", 'any', @actual
else
return "use_layout expected #{@expected.inspect} not to equal #{@actual.inspect}", @expected, @actual
end
end
end
def use_layout(expected = nil)
UseLayout.new(expected)
end
答案 10 :(得分:0)
Shoulda Matchers provides a matcher for this scenario. (Documentation) This seems to work:
expect(response).to render_with_layout('my_layout')
it produces appropriate failure messages like:
Expected to render with the "calendar_layout" layout, but rendered with "application", "application"
Tested with rails 4.2
, rspec 3.3
and shoulda-matchers 2.8.0
Edit: shoulda-matchers provides this method. Shoulda::Matchers::ActionController::RenderWithLayoutMatcher