Question

我想一次选择更多图像文件并上传为1,2,3,4，...赞：

<form action="upload_file.php" method="post" enctype="multipart/form-data">
    <input type="file" name="imgs[]" id="imgs" multiple/> 
    <input type="submit" name="submit" value="Submit" />
</form>

PHP代码：

<?php

if (file_exists("upload/" . $_FILES["imgs"]["name"]))
      {
      echo $_FILES["file"]["name"] . " already exists. ";

      }
    else
      {

//I think loop goes here 
===================
      move_uploaded_file($_FILES["file"]["tmp_name"],
      "upload/" . $_FILES["file"]["name"]);
      echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
===================

      }
?>

=============================================== ===================

这是有效的......

<form action="upload_file.php" method="post" enctype="multipart/form-data">
    <input type="file" name="uploads[]" multiple>
    <input type="submit" name="submit" value="Submit" />
</form>

PHP

<?php
$count=1;
foreach ($_FILES['uploads']['tmp_name'] as $file) {
  echo '<li>' . $file . '</li>';

  copy($file, "uploads/" . $count.".jpg");
      echo "Stored in: " . "uploads/" . $count.".jpg";
    $count++;
}
?>

这是有效的....

Answer 1

用以下内容替换您的PHP代码：

<?php
for($i=0;$i<count($_FILES["imgs"]["name"]);$i++) 
{
if (file_exists("upload/" . $_FILES["imgs"]["name"][$i]))
      {
      echo $_FILES["imgs"]["name"][$i] . " already exists. ";
      }
    else
      {

//I think loop goes here 
===================
      move_uploaded_file($_FILES["imgs"]["tmp_name"][$i],
      "upload/" . $_FILES["imgs"]["name"][$i]);
      echo "Stored in: " . "upload/" . $_FILES["imgs"]["name"][$i];
===================

      }
}
?>

Answer 2

当您有多个上传时，PHP会以奇怪的（但一致的）方式构建$_FILES数组。尝试使用三个文件输入创建此表单：

<form action="upload_file.php" method="post" enctype="multipart/form-data">
    <input type="file" name="imgs[]" id="imgs" multiple /> 
    <input type="submit" name="submit" value="Submit" />
</form>

然后在接收表单的PHP代码中，仅放置：

<?php print_r($_FILES); ?>

所以你可以看到$_FILES数组结构。在这一点上，所有人都会清楚，你将自己如何循环以保存所有上传的图像。祝你好运;）

Answer 3

我已经测试了这段代码，它有效，一旦我解决了，我忘了回答它。

<form action="upload_file.php" method="post" enctype="multipart/form-data">
 <input type="file" name="uploads[]" multiple>
 <input type="submit" name="submit" value="Submit" />
</form>

获取PHP文件中的数据，如下所示。

<?php
 $count=1;
 foreach ($_FILES['uploads']['tmp_name'] as $file) {
   echo '<li>' . $file . '</li>';

   copy($file, "uploads/" . $count.".jpg");
   echo "Stored in: " . "uploads/" . $count.".jpg";
   $count++;
 }
?>

使用输入类型文件和PHP循环（不使用jQuery或Javascript）上传多个文件

3 个答案: