我是Facebook应用程序开发的新手,我一直试图在用户的墙上发布一条简单的消息。我设法获取访问令牌。这是POST请求的代码。我正在使用java servlets
String data = URLEncoder.encode("access_token", "UTF-8") + "=" + URLEncoder.encode(accessToken, "UTF-8");
data += "&" + URLEncoder.encode("message", "UTF-8") + "=" + URLEncoder.encode("finally", "UTF-8");
out.println("data is\n"+data);
// Send data
String u="https://graph.facebook.com/me/feed";
URL urls = new URL(u);
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(data);
wr.flush();
那么这段代码不起作用,我不能发布在墙上。关于我可能出错的地方有什么建议吗?
答案 0 :(得分:0)
我很确定这是因为你没有指定application/x-www-form-urlencoded
内容类型,试试这个:
URLConnection connection = new URL("https://graph.facebook.com/me/feed").openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
DataOutputStream out = new DataOutputStream(connection.getOutputStream());
out.writeBytes(data);
out.flush();
out.close()
好的,所以还有两件事可能导致这个问题:
此代码经过测试且有效:
StringBuffer buffer = new StringBuffer();
buffer.append("access_token").append('=').append(ACCESS_TOKEN);
buffer.append('&').append("message=").append('=').append("YO!");
String content = buffer.toString();
URLConnection connection = new URL("https://graph.facebook.com/me/feed").openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length", Integer.toString(content.length()));
DataOutputStream out = new DataOutputStream(connection.getOutputStream());
out.writeBytes(content);
out.flush();
out.close();
BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) {
System.out.println(inputLine);
}
in.close();