我似乎无法弄清楚如何使用ItemFileWriteStore和TreeStoreModel在dijit.Tree中搜索。一切都是声明性的,我正在使用Dojo 1.7.1,这是我到目前为止所拥有的:
<input type="text" dojoType="dijit.form.TextBox" name="search_fruit" id="search_fruit" onclick="search_fruit();">
<!-- store -->
<div data-dojo-id="fruitsStore" data-dojo-type="dojo.data.ItemFileWriteStore" clearOnClose="true" urlPreventCache="true" data-dojo-props='url:"fruits_store.php"'></div>
<!-- model -->
<div data-dojo-id="fruitsModel" data-dojo-type="dijit.tree.TreeStoreModel" data-dojo-props="store:fruitsStore, query:{}"></div>
<!-- tree -->
<div id="fruitsTree" data-dojo-type="dijit.Tree"
data-dojo-props='"class":"container",
model:fruitsModel,
dndController:"dijit.tree.dndSource",
betweenThreshold:5,
persist:true'>
</div>
fruits_store.php返回的json是这样的:
{"identifier":"id",
"label":"name",
"items":[{"id":"OYAHQIBVbeORMfBNZXFGOHPdaRMNUdWEDRPASHSVDBSKALKIcBZQ","name":"Fruits","children":[{"id":"bSKSVDdRMRfEFNccfTZbWHSACWbLJZMTNHDVVcYGcTBDcIdKIfYQ","name":"Banana"},{"id":"JYDeLNIGPDBRMcfSTMeERZZEUUIOMNEYYcNCaCQbCMIWOMQdMEZA","name":"Citrus","children":[{"id":"KdDUfEDaKOQMFNJaYbSbAcAPFBBdLALFMIPTFaYSeCaDOFaEPbJQ","name":"Orange"},{"id":"SDWbXWbTWKNJDIfdAdJbbbRWcLZFJHdEWASYDCeFOZYdcZUXJEUQ","name":"Lemon"}]},{"id":"fUdQTEZaIeBIWCHMeBZbPdEWWIQBFbVDbNFfJXNILYeBLbWUFYeQ","name":"Common ","children":[{"id":"MBeIUKReBHbFWPDFACFGWPePcNANPVdQLBBXYaTPRXXcTYRTJLDQ","name":"Apple"}]}]}]}
使用网格而不是树,我的search_fruit()函数将如下所示:
function search_fruit() {
var grid = dijit.byId('grid_fruits');
grid.query.search_txt = dijit.byId('search_fruit').get('value');
grid.selection.clear();
grid.store.close();
grid._refresh();
}
如何使用树实现相同的目标?谢谢!
答案 0 :(得分:2)
dijit.Tree
的刷新变得有点复杂,因为涉及一个模型(在网格afaik内置,网格组件实现查询功能)
但是如何搜索,在使用ItemFileReadStore
时非常容易。语法是这样的:
myTree.model.store.fetch({
query: {
name: 'Oranges'
},
onComplete: function(items) {
dojo.forEach(items, function(item) {
console.log(myTree.model.store.getValue(item, "ID"));
});
}
});
如上所示,存储将获取,完整的有效负载被放入其_allItemsArray,然后存储查询引擎过滤掉它通过查询参数告诉fetch方法的内容。在任何时候,即使没有为json内容发送XHR,我们也可以在存储上调用fetch - 使用query参数获取可以被视为一个简单的过滤器。
让Model
知道这个查询会变得有点有趣。如果你这样做,它只会根据{{treeNode
的结果来创建store.fetch({query:model.query});
来填充树。 1}}
因此,不要使用回调发送store.fetch,而是让_try设置模型查询并更新树。
// seing as we are working with a multi-parent tree model (ForestTree), the query Must match a toplevel item or else nothing is shown
myTree.model.query = { name:'Fruits' };
// below method must be implemented to do so runtime
// and note, that the DnD might become invalid
myTree.update();
您需要完成与商店相关的操作。关闭它,然后重建模型。模型包含所有TreeNode
s(在其根节点下),Tree
本身映射一个需要清除的itemarray以避免内存泄漏。
因此,执行以下步骤将重建树 - 但是此示例不考虑,如果您已激活DnD,则dndSource / dndContainer仍将引用旧DOM,从而“保持活动”以前的DOMNode层次结构(隐藏的.c。
通过告诉模型其rootNode为UNCHECKED
,将检查其子节点是否有变化。一旦树完成其_load()
关闭商店(以便商店进行新的获取())。
this.model.store.clearOnClose = true;
this.model.store.close();
完全删除dijit.Tree
中的每个节点 delete this._itemNodesMap;
this._itemNodesMap = {};
this.rootNode.state = "UNCHECKED";
delete this.model.root.children;
this.model.root.children = null;
销毁小部件
this.rootNode.destroyRecursive();
重新创建模型,(再次使用模型)
this.model.constructor(this.model)
重建树
this.postMixInProperties();
this._load();
Creds;所有这些一起,限制在dijit.Tree:
new dijit.Tree({
// arguments
...
// And additional functionality
update : function() {
this.model.store.clearOnClose = true;
this.model.store.close();
delete this._itemNodesMap;
this._itemNodesMap = {};
this.rootNode.state = "UNCHECKED";
delete this.model.root.children;
this.model.root.children = null;
this.rootNode.destroyRecursive();
this.model.constructor(this.model)
this.postMixInProperties();
this._load();
}
});