Question

我正在努力应对Group By和Null，如下所示。

我有两张表，如下面

Table : 1 accountmast       
companyID   accname             category    
102         PURCHASE ACCOUNT    Purchase Account    
102         LOCAL PURCHASE      Purchase Account    
102         SALES ACCOUNT       Sales Account   

Table: 2 ledger     
companyID   name                debit   credit
102         PURCHASE ACCOUNT    4742.3  
102         LOCAL PURCHASE      51106   
102         SALES ACCOUNT               8010
102         SALES ACCOUNT               4330000
102         PURCHASE ACCOUNT    5480000

我问过如下：

select  
case    
when a.catagory ='Purchase Account' then    
l.name  
end as PurchaseAccount, 

case    
when a.catagory ='Purchase Account' then    
sum(coalesce(l.debit,0))-sum(coalesce(l.credit,0) ) 
end as PurAmt,  

case    
when a.catagory = 'Sales Account' then  
l.name      
end as SalesAccount,    
case    
when a.catagory = 'Sales Account' then  
sum(coalesce(l.credit,0))-sum(coalesce(l.debit,0) ) 
end as SalesAmt 

from ledger l join accountmast a    
on l.companyID=a.companyID  
and l.name = a.accname  
where l.companyID=102   
and a.catagory IN('Purchase Account','Sales Account')   
group by l.name,a.catagory

结果是：

Purchase Account    PurAmt          Sales Account   SalesAmt
LOCAL PURCHASE      51106.00         NULL           NULL
PURCHASE ACCOUNT    5484742.30       NULL           NULL
NULL                NULL            SALES ACCOUNT  4338010.00

要求是：

Purchase Account    PurAmt           Sales Account   SalesAmt
LOCAL PURCHASE      51106.00         SALES ACCOUNT   4338010.00
PURCHASE ACCOUNT    5484742.30

解决方案是什么？。

如果我使用Group By，那么它允许Null值关联表的列。

如果我使用MAX，MIN，则会显示单个记录。我该怎么办？

如果有人有更好的解决方案，请建议。

Answer 1

WITH    q AS
        (
        SELECT  am.category, l.name,
                CASE am.category WHEN 'Purchase Account' THEN amt ELSE -amt END
        FROM    accountmast am
        CROSS APPLY
                (
                SELECT  name, SUM(COALESCE(credit, 0) - COALESCE(debit, 0)) AS amt
                FROM    ledger l
                WHERE   l.name = am.accname
                        AND l.companyId = am.companyId
                GROUP BY
                        name
                ) l
        WHERE   am.companyId = 102
        )
SELECT  l1.name, l1.amt, l2.name, l2.amt
FROM    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   category = 'Purchase account'
        ) l1
FULL JOIN
        (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   category = 'Sales account'
        ) l2
ON      l2.rn = l1.rn

Answer 2

注意：这不是答案这是Quassnoi考虑的参考。

这里我做了一些修改供你考虑。

WITH    q AS
(
SELECT  am.catagory, l.name,
CASE am.catagory WHEN 'Purchase Account' THEN Amount ELSE -Amount     END as Amount -- Here I provide the column name and alter the Column
FROM    accountmast am
    CROSS APPLY
    (
    SELECT  name, SUM(COALESCE(debit, 0) - COALESCE(credit, 0)) AS Amount --Reverse the sum function which is oppose of yours. And your's shows the value in minus.
    FROM    ledger l
    WHERE   l.name = am.accname
    AND l.companyId = am.companyId
    GROUP BY
             name
    ) l
    WHERE   am.companyId = 102
)
SELECT  l1.name as PurACC, l1.Amount as PurAmt, l2.name as SalACC, l2.Amount as SalAmt -- alter the columns for Binding Purpose.
FROM
    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   catagory = 'Purchase account'
    ) l1
FULL JOIN
    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   catagory = 'Sales account'
    ) l2
ON l2.rn = l1.rn

以上更改很重要，否则您的答案仍然不正确，并会检查错误。

Null Rows＆＃39;由于通过分组连接表而存在

2 个答案: