Question

此JSON请求：

$.ajax({
    url:jSONurl+'?orderID='+thisOrderID+'&variationID='+thisVariationID+'&quantity='+thisQuantity+'&callback=?',
    async: false,
    type: 'POST',
    dataType: 'json',
    success: function(data) {
        if (data.response == 'success'){
            //show the tick. allow the booking to go through
            $('#loadingSML'+thisVariationID).hide();
            $('#tick'+thisVariationID).show();
        }else{
            //show the cross. Do not allow the booking to be made
            $('#loadingSML'+thisVariationID).hide();
            $('#cross'+thisVariationID).hide();
            $('#unableToReserveError').slideDown();
            //disable the form
            $('#OrderForm_OrderForm input').attr('disabled','disabled');
        }
    },
    error: function(data){
        alert('error');
    }
})

在某些情况下会以以下形式带回500错误：

jQuery17205593111887289146_1338951277057({"message":"Availability exhausted","status":500});

然而，这对我来说仍然有用，我需要能够正确处理这个问题。

由于某些原因，当返回此500错误时，我的错误函数未被调用，我只是在firebug中出现“NetworkError：500 Internal Server Error”错误。

我该如何处理？

Answer 1

您是否尝试过statuscode回调

 $.ajax({
    statusCode: {
        500: function() {
          alert("Script exhausted");
        }
      }
   });

Answer 2

查看jqXHR Object文档。您可以使用fail方法捕获任何错误。

您的案例如下：

$.post(jSONurl+'?orderID='+thisOrderID+'&variationID='+thisVariationID+'&quantity='+thisQuantity+'&callback=?')
.done(function(data){
        if (data.response == 'success'){
            //show the tick. allow the booking to go through
            $('#loadingSML'+thisVariationID).hide();
            $('#tick'+thisVariationID).show();
        }else{
            //show the cross. Do not allow the booking to be made
            $('#loadingSML'+thisVariationID).hide();
            $('#cross'+thisVariationID).hide();
            $('#unableToReserveError').slideDown();
            //disable the form
            $('#OrderForm_OrderForm input').attr('disabled','disabled');
        }
      }, "json")
.fail(function(jqXHR, textStatus, errorThrown){
      alert("Got some error: " + errorThrown);
      });

我还会考虑通过post传递json数据字符串而不是附加查询变量：

$.post(jSONurl, $.toJSON({orderID: thisOrderID, variationID: thisVariationID, quantity: thisQuantity, callback: false}))

Answer 3

我认为你可以通过添加这个来抓住它：

$.ajax({
    statusCode: {
      500: function() {
      alert("error");
       }
    },
    url:jSONurl+'?orderID='+thisOrderID+'&variationID='+thisVariationID+'&quantity='+thisQuantity+'&callback=?',
    async: false,
    type: 'POST',
    dataType: 'json',
    success: function(data) {
        if (data.response == 'success'){
            //show the tick. allow the booking to go through
            $('#loadingSML'+thisVariationID).hide();
            $('#tick'+thisVariationID).show();
        }else{
            //show the cross. Do not allow the booking to be made
            $('#loadingSML'+thisVariationID).hide();
            $('#cross'+thisVariationID).hide();
            $('#unableToReserveError').slideDown();
            //disable the form
            $('#OrderForm_OrderForm input').attr('disabled','disabled');
        }
    },
    error: function(data){
        alert('error');
    }
})

Answer 4

如果您使用的是POST，可以使用以下内容：

$.post('account/check-notifications')
    .done(function(data) {
        // success function
    })
    .fail(function(jqXHR){
        if(jqXHR.status==500 || jqXHR.status==0){
            // internal server error or internet connection broke  
        }
    });

Answer 5

我从ajax调用中删除了dataType：json，我能够捕获错误。在这些情况下，我不需要返回的jSON的内容;只知道返回有错误，所以现在就足够了。 Firebug仍然适合他，但我至少能够在出现错误时执行某些操作

$.ajax({
            url:'http://example.com/jsonservice/LiftieWeb/reserve?token=62e52d30e1aa70831c3f09780e8593f8&orderID='+thisOrderID+'&variationID='+reserveList+'&quantity='+thisQuantity+'&callback=?',
            type: 'POST',
            success: function(data) {
                if (data.response == 'Success'){
                    //show the tick. allow the booking to go through
                    $('#loadingSML'+thisVariationID).hide();
                    $('#tick'+thisVariationID).show();
                }else{
                    //show the cross. Do not allow the booking to be made
                    $('#loadingSML'+thisVariationID).hide();
                    $('#cross'+thisVariationID).hide();
                    $('#unableToReserveError').slideDown();
                    //disable the form
                    $('#OrderForm_OrderForm input').attr('disabled','disabled');
                }
            },
            error: function(data){
                alert('error');
            }
        })

处理JSON中的500个错误（jQuery）

5 个答案: