Question

我有一句话：

Name: JOHN J. SMITH Sometag:

我如何抓住JOHN J SMITH部分？

Sometag并不总是一样的，所以更像是获得所有全部大写的词，直到不是。

更新

"[A-Z. ]*"返回JOHN J. SMITH S
"[A-Z. ]*\b"只返回任何内容 "\b[A-Z. ]*\b"

Answer 1

试试这个

[A-Z. ]*\b

让我知道它是怎么回事

你可以更完整地使用这个

[\p{Lu}\p{M}\p{Z}\p{N}\p{P}\p{S}]*\b

但它满口

Match a single character present in the list below «[\p{Lu}\p{M}\p{Z}\p{N}\p{P}\p{S}]*»
   Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
   A character with the Unicode property “uppercase letter” (an uppercase letter that has a lowercase variant) «\p{Lu}»
   A character with the Unicode property “mark” (a character intended to be combined with another character (e.g. accents, umlauts, enclosing boxes, etc.)) «\p{M}»
   A character with the Unicode property “separator” (any kind of whitespace or invisible separator) «\p{Z}»
   A character with the Unicode property “number” (any kind of numeric character in any script) «\p{N}»
   A character with the Unicode property “punctuation” (any kind of punctuation character) «\p{P}»
   A character with the Unicode property “symbol” (math symbols, currency signs, dingbats, box-drawing characters, etc.) «\p{S}»
Assert position at a word boundary «\b»

或更短

\P{Ll}*\b

更新1

编辑后我会用这个

Name: (\P{Ll}*)[ ]

所需的匹配将在第1组中。请注意，我最后添加了一个[]以表示单个空格。如果需要，可以将此字符类转换为空格。

在C＃中，这变为

string resultString = null;
try {
    Regex regexObj = new Regex(@"Name: (\p{Ll}*)[ ]");
    resultString = regexObj.Match(subjectString).Groups[1].Value;
} catch (ArgumentException ex) {
    // Syntax error in the regular expression
}

Answer 2

无法使用负面预测并发现大写字母后面没有小写字母？

（（[A-Z。]）（？！[a-z：]））+

String caps=Regex.Match("Name: JOHN J. SMITH Sometag: ","(([A-Z. ])(?![a-z:]))+").ToString()

所有大写单词的正则表达式直到小写

2 个答案: