Question

我通过引用两个同义词创建了一个视图。我要收获查看表的当前查询如下

SELECT  dbo.synonym1.JobNo
      , dbo.synonym1.Customer
      , dbo.synonym2.PostalService
      , dbo.synonym2.FirstDate
      , dbo.synonym2.SecondDate
FROM dbo.synonym1 
  INNER JOIN dbo.synonym2 ON dbo.synonym1.JobNo = sbo.synonym2.JobNo
WHERE dbo.synonym2.PostalService = 'UPS'

现在，我想在每一行中找到dbo.synonym2.FirstDate和dbo.synonym2.SecondDate之间的区别，并在同一行中再次INSERT与查看表中的差异，因为存在差异。< / p>

例如，如果FirstDate为2012-06-03 00:00:00.000且SecondDate为2012-06-05 00:00:00.000，那么它应该插入相同的行两次。

我正在使用SQL Server 2008 R2，而且我是SQL的新手。请帮帮我

目前在视图中使用上述查询填充的示例数据如下所示

JobNo  Customer PostalService FirstDate                 SecondDate  
1      ABC      UPS           2012-06-03 00:00:00.000   2012-06-03 00:00:00.000
2      DEF      UPS           2012-06-03 00:00:00.000   2012-06-06 00:00:00.000
3      XYZ      UPS           2012-06-03 00:00:00.000   2012-06-05 00:00:00.000

我需要一个结果如下

JobNo  Customer PostalService FirstDate                 SecondDate  
1      ABC      UPS           2012-06-03 00:00:00.000   2012-06-03 00:00:00.000
2      DEF      UPS           2012-06-03 00:00:00.000   2012-06-05 00:00:00.000
2      DEF      UPS           2012-06-03 00:00:00.000   2012-06-05 00:00:00.000
2      XYZ      UPS           2012-06-03 00:00:00.000   2012-06-05 00:00:00.000
3      XYZ      UPS           2012-06-03 00:00:00.000   2012-06-06 00:00:00.000
3      XYZ      UPS           2012-06-03 00:00:00.000   2012-06-06 00:00:00.000

如果您看到JobNo 2的日期之间的差异为3，那么数据将重复三次。并且JobNo 3为2，因此数据重复两次。

Answer 1

您的请求有点令人困惑，因为通常不会插入视图。

但是，以下内容会将行插入表

insert into ViewTable(JobNo, Customer, PostalService, FirstDate, SecondDate)
    SELECT dbo.synonym1.JobNo, dbo.synonym1.Customer, dbo.synonym2.PostalService,
           dbo.synonym2.FirstDate, dbo.synonym2.SecondDate
     FROM dbo.synonym1 INNER JOIN
          dbo.synonym2
          ON dbo.synonym1.JobNo = sbo.synonym2.JobNo
     WHERE dbo.synonym2.PostalService = 'UPS' and
           datediff(d, FirstDate, SecondDate) <> 0

您需要将ViewTable定义为实际表格。

Answer 2

听起来你想要的是下面的union语句来填充这个临时表。除非我误解了你要求的东西。

DECLARE @MyTable as TABLE(JobNo VARHCAR(50), Customer VARCHAR(50), 
                       Postalservice VARCHAR(50), MyDate DateTime)

INSERT into @MyTable 
SELECT  dbo.synonym1.JobNo 
  , dbo.synonym1.Customer 
  , dbo.synonym2.PostalService 
  , dbo.synonym2.FirstDate 

FROM dbo.synonym1  
INNER JOIN dbo.synonym2 ON dbo.synonym1.JobNo = sbo.synonym2.JobNo 
WHERE dbo.synonym2.PostalService = 'UPS'  
UNION
SELECT  dbo.synonym1.JobNo 
  , dbo.synonym1.Customer 
  , dbo.synonym2.PostalService 

  , dbo.synonym2.SecondDate 
FROM dbo.synonym1  
INNER JOIN dbo.synonym2 ON dbo.synonym1.JobNo = sbo.synonym2.JobNo 
WHERE dbo.synonym2.PostalService = 'UPS'

从@MyTable

插入您的视图

Answer 3

Create Table #temp
(
    StartDate DateTime,
    EndDate DateTime
)

Insert into #temp(StartDate, EndDate)
                    Values('2012-06-03 00:00:00.000', '2012-06-03 00:00:00.000');
Insert into #temp(StartDate, EndDate)
                    Values('2012-06-03 00:00:00.000', '2012-06-06 00:00:00.000');
Insert into #temp(StartDate, EndDate)
                    Values('2012-06-03 00:00:00.000', '2012-06-05 00:00:00.000');

With DateRange As
(
    select Convert(DateTime, '2012-06-02 00:00:00.000') as StartDate, 
          DATEADD(dd, 1, Convert(DateTime, '2012-06-02 00:00:00.000')) as EndDate
    Union All
    select EndDate, DATEADD(dd, 1, EndDate) From DateRange 
                    Where EndDate <= Convert(DateTime, '2012-06-10 00:00:00.000')
)

Select T.* from #temp T
Left Join DateRange R on ((T.StartDate < R.EndDate and T.EndDate > R.StartDate) 
          or (T.StartDate = R.EndDate and T.EndDate = R.StartDate))
order  by T.EndDate

Drop table #temp

INSERT INTO动态查看

3 个答案: