Question

在Java Http请求中，我们可以这样做以进行多部分HTTP POST。

HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);

FileBody bin = new FileBody(new File(fileName));
StringBody comment = new StringBody("Filename: " + fileName);

MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("bin", bin);
reqEntity.addPart("comment", comment);
httppost.setEntity(reqEntity);

HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();

我如何使用WS.url或WS.WSRequest实现相同的目标？

WSRequestHolder wsReq = WS.url("http//url");            
wsReq.setHeader("Content-type", "multipart/form-data");

Answer 1

这很草率，绝对可以清理，但这就是我做的工作。随意把它做得更好。

import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;

import play.libs.WS;

import com.ning.http.multipart.FilePart;
import com.ning.http.multipart.MultipartRequestEntity;
import com.ning.http.multipart.Part;

ByteArrayOutputStream bos = new ByteArrayOutputStream();

// Build up the Multiparts
List<Part> parts = new ArrayList<>();
parts.add(new FilePart("file", new File(filename)));
Part[] partsA = parts.toArray(new Part[parts.size()]);

// Add it to the MultipartRequestEntity
MultipartRequestEntity reqE = new MultipartRequestEntity(partsA, null);
reqE.writeRequest(bos);
InputStream reqIS = new ByteArrayInputStream(bos.toByteArray());
WS.WSRequestHolder req = WS.url(InterchangeConfig.conflateUrl+"dataset")
    .setContentType(reqE.getContentType());
req.post(reqIS).map(...);
// or req.post(reqIS).get();

这都是使用Play 2.0框架中已有的部分。

Answer 2

现在唯一的解决方案是，不依赖于外部库，似乎是手动创建Multipart Form Data请求。这是一个使用play.libs.WS.url：

完成工作的示例

WSRequestHolder wsRequestHolder = WS.url(URL);

String boundary = "--XYZ123--";

String body = "";
for (String key : data.keySet()) {
  body += "--" + boundary + "\r\n"
       + "Content-Disposition: form-data; name=\""
       + key + "\"\r\n\r\n"
       + data.get(key) + "\r\n";
}
body += "--" + boundary + "--";

wsRequestHolder.setHeader("Content-Type", "multipart/form-data; boundary=" + boundary);
wsRequestHolder.setHeader("Content-length", String.valueOf(body.length()));

wsRequestHolder.post(body);

data将是java.util.Map<String, String>，其中包含您要作为表单参数传递的所有名称/值对。 randomString是一个随机值，用于使请求与请求之间的边界更改。添加二进制数据将以相同的方式工作。

此http://www.htmlcodetutorial.com/forms/form_enctype.html是了解规格的好地方。

Answer 3

使用上述方法进行游戏2.3的工作示例，同时在上传文件时添加了contentType。

public Promise<WSResponse> upload(Http.MultipartFormData.FilePart policyFilePart, String contentType) {
    ByteArrayOutputStream bos = new ByteArrayOutputStream();
    List<Part> parts = new ArrayList<>();
    try {
        parts.add(new FilePart("file", policyFilePart.getFile(), contentType, null));
        parts.add(new StringPart("param1", "value1"));
        parts.add(new StringPart("param2", "value2"));
        Part[] partsA = parts.toArray(new Part[parts.size()]);

        // Add it to the multipart request entity
        MultipartRequestEntity requestEntity = new MultipartRequestEntity(partsA, new FluentCaseInsensitiveStringsMap());
        requestEntity.writeRequest(bos);
        InputStream reqIS = new ByteArrayInputStream(bos.toByteArray());
        return WS.url(baseUrl + "upload")
                .setContentType(requestEntity.getContentType())
                .post(reqIS).map(new Function<WSResponse, WSResponse>() {
                    @Override
                    public WSResponse apply(WSResponse wsResponse) throws Throwable {
                            return wsResponse;
                    }
                });
    } catch (IOException e) {
        e.printStackTrace();
        return null;
    }
}

Answer 4

根据播放API文档，似乎没有内置多部分POST主体。

但是，可以使用方法

创建自己的多部分主体

post[T](body: T)(implicit wrt: Writeable[T], ct: ContentTypeOf[T]): Future[Response]

使用您选择的类型T，以及相应的Writeable和ContentTypeOf类型。

但这意味着要深入研究多部分机构如何使用HTTP。

Answer 5

正如Romain Sertelon建议的那样，你可以编写一个Writeable来处理这种情况。这是我写的：

package utilities

import java.io.{ByteArrayOutputStream, File}

import com.ning.http.client.FluentCaseInsensitiveStringsMap
import com.ning.http.multipart.{MultipartRequestEntity, FilePart, StringPart}
import play.api.http.HeaderNames._
import play.api.http.{ContentTypeOf, Writeable}
import play.api.mvc.{Codec, MultipartFormData}

object MultipartFormDataWriteable {

    implicit def contentTypeOf_MultipartFormData[A](implicit codec: Codec): ContentTypeOf[MultipartFormData[A]] = {
        ContentTypeOf[MultipartFormData[A]](Some("multipart/form-data; boundary=__X_PROCESS_STREET_BOUNDARY__"))
    }

    implicit def writeableOf_MultipartFormData(implicit contentType: ContentTypeOf[MultipartFormData[File]]): Writeable[MultipartFormData[File]] = {
        Writeable[MultipartFormData[File]]((formData: MultipartFormData[File]) => {

            val stringParts = formData.dataParts flatMap {
                case (key, values) => values map (new StringPart(key, _))
            }

            val fileParts = formData.files map { filePart =>
                new FilePart(filePart.key, filePart.ref, filePart.contentType getOrElse "application/octet-stream", null)
            }

            val parts = stringParts ++ fileParts

            val headers = new FluentCaseInsensitiveStringsMap().add(CONTENT_TYPE, contentType.mimeType.get)
            val entity = new MultipartRequestEntity(parts.toArray, headers)
            val outputStream = new ByteArrayOutputStream
            entity.writeRequest(outputStream)

            outputStream.toByteArray

        })(contentType)
    }

}

以下是如何使用它：

import utilities.MultipartFormDataWriteable._

...

val url = "https://example.com"

val dataParts = Map(
    "foo" -> Seq("bar"),
    "alice" -> Seq("bob")
)

val file = new jave.io.File(... path to a jpg ...)
val fileParts = Seq(new FilePart("attachment", "foo.jpg", Some("image/jpeg"), file)

val multipartFormData = MultipartFormData(dataParts, fileParts, Seq(), Seq())

WS.url(url).post(multipartFormData)

Answer 6

接受的答案不适用于播放2.5。 play 2.6文档中的答案也不适用于2.5。
以下工作正常：

Http.MultipartFormData.FilePart part = new Http.MultipartFormData.FilePart("fileKey",
                "abc.zip", "multipart/form-data",
                FileIO.fromFile(new File("/home/testData/abc.zip")));
List<Http.MultipartFormData.Part<Source<ByteString, ?>>> data = Arrays.asList(part);
Http.RequestBuilder requestBuilder = AuthFakeRequest.getAuthFakeRequest(routes.MyController.uploadZip()).method(POST)
                .bodyMultipart(data, mat);
Result result = route(app, requestBuilder);

对于mat和app对象，它们是在继承play.test.WithApplication类时获得的。

Play 2.0如何使用WS.url或WS.WSRequest发布MultipartFormData

6 个答案: