我正在开发一个应用程序,我正在使用第三方解析简历。第三方以xml的形式返回我的回复。我将整个xml存储在单列中。 每次节点数量不同取决于提供的简历。
现在我的要求是在此xml数据类型列上执行全文或普通搜索。我还需要提取候选人姓名,姓氏,电子邮件和其他一些重要信息。我的问题是如何在我不知道节点名称的列上进行搜索。
答案 0 :(得分:0)
xml数据类型列仅存储XML文档和片段,并且只有XML过滤器用于文档。因此,不需要类型列。在xml列上,全文索引索引XML元素的内容,但忽略XML标记。属性值是全文索引,除非它们是数值。元素标记用作标记边界。支持格式良好的XML或HTML文档以及包含多种语言的片段。 有关查询xml列的详细信息,请参阅XML列上的全文索引。 http://msdn.microsoft.com/en-us/library/bb522491.aspx
另外,您可以使用此SQL(UDF)函数来获取xml节点名称
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[XMLTable](@x XML)
RETURNS TABLE
AS RETURN
WITH cte AS (
SELECT
1 AS lvl,
x.value('local-name(.)','NVARCHAR(MAX)') AS Name,
CAST(NULL AS NVARCHAR(MAX)) AS ParentName,
CAST(1 AS INT) AS ParentPosition,
CAST(N'Element' AS NVARCHAR(20)) AS NodeType,
x.value('local-name(.)','NVARCHAR(MAX)') AS FullPath,
x.value('local-name(.)','NVARCHAR(MAX)')
+ N'['
+ CAST(ROW_NUMBER() OVER(ORDER BY (SELECT 1)) AS NVARCHAR)
+ N']' AS XPath,
ROW_NUMBER() OVER(ORDER BY (SELECT 1)) AS Position,
x.value('local-name(.)','NVARCHAR(MAX)') AS Tree,
x.value('text()[1]','NVARCHAR(MAX)') AS Value,
x.query('.') AS this,
x.query('*') AS t,
CAST(CAST(1 AS VARBINARY(4)) AS VARBINARY(MAX)) AS Sort,
CAST(1 AS INT) AS ID
FROM @x.nodes('/*') a(x)
UNION ALL
SELECT
p.lvl + 1 AS lvl,
c.value('local-name(.)','NVARCHAR(MAX)') AS Name,
CAST(p.Name AS NVARCHAR(MAX)) AS ParentName,
CAST(p.Position AS INT) AS ParentPosition,
CAST(N'Element' AS NVARCHAR(20)) AS NodeType,
CAST(p.FullPath + N'/' + c.value('local-name(.)','NVARCHAR(MAX)') AS NVARCHAR(MAX)) AS FullPath,
CAST(p.XPath + N'/'+ c.value('local-name(.)','NVARCHAR(MAX)')+ N'['+ CAST(ROW_NUMBER() OVER(PARTITION BY c.value('local-name(.)','NVARCHAR(MAX)')
ORDER BY (SELECT 1)) AS NVARCHAR)+ N']' AS NVARCHAR(MAX)) AS XPath,
ROW_NUMBER() OVER(PARTITION BY c.value('local-name(.)','NVARCHAR(MAX)')
ORDER BY (SELECT 1)) AS Position,
CAST( SPACE(2 * p.lvl - 1) + N'|' + REPLICATE(N'-', 1) + c.value('local-name(.)','NVARCHAR(MAX)') AS NVARCHAR(MAX)) AS Tree,
CAST( c.value('text()[1]','NVARCHAR(MAX)') AS NVARCHAR(MAX) ) AS Value, c.query('.') AS this,
c.query('*') AS t,
CAST(p.Sort + CAST( (lvl + 1) * 1024 + (ROW_NUMBER() OVER(ORDER BY (SELECT 1)) * 2) AS VARBINARY(4)) AS VARBINARY(MAX) ) AS Sort,
CAST((lvl + 1) * 1024 + (ROW_NUMBER() OVER(ORDER BY (SELECT 1)) * 2) AS INT)
FROM cte p
CROSS APPLY p.t.nodes('*') b(c)), cte2 AS (
SELECT
lvl AS Depth,
Name AS NodeName,
ParentName,
ParentPosition,
NodeType,
FullPath,
XPath,
Position,
Tree AS TreeView,
Value,
this AS XMLData,
Sort, ID
FROM cte
UNION ALL
SELECT
p.lvl,
x.value('local-name(.)','NVARCHAR(MAX)'),
p.Name,
p.Position,
CAST(N'Attribute' AS NVARCHAR(20)),
p.FullPath + N'/@' + x.value('local-name(.)','NVARCHAR(MAX)'),
p.XPath + N'/@' + x.value('local-name(.)','NVARCHAR(MAX)'),
1,
SPACE(2 * p.lvl - 1) + N'|' + REPLICATE('-', 1)
+ N'@' + x.value('local-name(.)','NVARCHAR(MAX)'),
x.value('.','NVARCHAR(MAX)'),
NULL,
p.Sort,
p.ID + 1
FROM cte p
CROSS APPLY this.nodes('/*/@*') a(x)
)
SELECT
ROW_NUMBER() OVER(ORDER BY Sort, ID) AS ID,
ParentName, ParentPosition,Depth, NodeName, Position,
NodeType, FullPath, XPath, TreeView, Value, XMLData
FROM cte2