Question

通过在向数据库添加新实体时添加条件来解决，它检查实体是否不为空...显然有空实体试图保存。现在控制器代码如下所示：

...
$ciudades_id = explode(';', $this->getRequest()->getParam('ciudades_id'));
           foreach($ciudades_id as $ciudad_id){
               $ciudad = $this->_em->find("Application_Model_Ciudades", intval($ciudad_id));
               if($ciudad!= null){
                $carrera->getCiudad()->add($ciudad);                  
               }
           }


           $instituciones_id = explode(';', $this->getRequest()->getParam('instituciones_id'));
           foreach($instituciones_id as $institucion_id){
               $institucion = $this->_em->find("Application_Model_Instituciones", intval($institucion_id));
               if($institucion != null){
                  $carrera->getInstituciones()->add($institucion); 
               }
           }
...

感谢那些帮助#doctrine IRC频道的人：）

这是我的问题......我得到了一个名为“Carreras”（carreers）的实体，它有一些关联，并且新的carreers被添加到数据库中，带有一个Web表单。对我来说，一个carreer是一个测试，它有问题和其他属性，用户可以选择申请该测试的城市和机构。

因此，当我尝试在实体上保存新数据时，我收到此错误：

An error occurred
Application error
Exception information:

Message: A new entity was found through the relationship
'Application_Model_Carreras#ciudad' that was not configured 
to cascade persist operations for entity: Doctrine\ORM\UnitOfWork@. 
Explicitly persist    the new entity or configure cascading persist 
operations on the relationship. If you cannot find out which entity 
causes the problem implement 'Application_Model_Ciudades#__toString()' 
to get a clue.

这是“Carreras”的模型

use Doctrine\Common\Collections\ArrayCollection;
/**
 * @Entity
 * @Table(name="carreras")
 */
class Application_Model_Carreras
{
    /**
     * @Id @Column(type="integer")
     * @GeneratedValue
     */
    private $id;

    /** @Column(type="string") */
    private $nombre;

    /**
     * @ManyToMany(targetEntity="Application_Model_PruebasCarrera")
     * @JoinTable(name="Carreras_PruebasCarrera",
     *      joinColumns={@JoinColumn(name="carreras_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="pruebascarrera_id", referencedColumnName="id")}
     *      )
     */
    private $pruebas;


    /** @Column(type="integer") */
    private $valor;

    /** @Column(type="date") */
    private $fechainicio;

    /** @Column(type="date") */
    private $fechafin;

    /**
     * This association causes error
     * @ManyToMany(targetEntity="Application_Model_Ciudades")
     * @JoinTable(name="carrera_ciudades",
     *      joinColumns={@JoinColumn(name="carrera_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="ciudad_id", referencedColumnName="id")}
     *      )
     */
    private $ciudad;

    /**
     * @ManyToMany(targetEntity="Application_Model_Instituciones")
     * @JoinTable(name="carrera_instituciones",
     *      joinColumns={@JoinColumn(name="carrera_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="institucion_id", referencedColumnName="id")}
     *      )
     */
    private $instituciones;

    public function __construct()
    {
        $this->pruebas = new ArrayCollection();
        $this->ciudad = new ArrayCollection();
        $this->instituciones = new ArrayCollection();
    }

    public function setNombre($nombre){
        $this->nombre = $nombre;
    }

    public function setValor($valor){
        $this->valor = $valor;
    }

    public function setFechainicio($fechainicio){
        $this->fechainicio = $fechainicio;
    }

    public function setFechafin($fechafin){
        $this->fechafin = $fechafin;
    }

    public function getCiudad(){
        return $this->ciudad;
    }

    public function getPruebas(){
        return $this->pruebas;
    }

    public function getInstituciones(){
        return $this->instituciones;
    }
}

现在控制器上的操作：

 /*
     * This is an action for adding a new career
     */
    public function agregarAction()
    {
       $formtest = new Admin_Form_AgregarCarrera();
       $this->view->formtest = $formtest;
       if ($this->getRequest()->isPost() && $this->view->formtest->isValid($this->_getAllParams()))
       {
           /*
            * If the form is okay creating new Carreer model object
            * This model has some attributes and three associations (for now) 
            * you can see them later in detail
            */
           $carrera = new Application_Model_Carreras();
           $carrera->setNombre($this->getRequest()->getParam("nombre"));
           $carrera->setValor($this->getRequest()->getParam("valor"));
           $carrera->setFechainicio(new \DateTime($this->getRequest()->getParam("fechainicio")));
           $carrera->setFechafin(new \DateTime($this->getRequest()->getParam("fechafin")));
           /*
            * This is the first association. It's working fine (for now)
            */
           $pruebas = $this->getRequest()->getParam("pruebas");
           foreach($pruebas as $prueba){
              if($prueba != '0'){
                  $tmp = $this->_em->find("Application_Model_PruebasCarrera", $prueba);
                  $carrera->getPruebas()->add($tmp);
              }
           }
           /*
            * This is the second associations, i'm getting the error with this one
            */
           $ciudades_id = explode(';', $this->getRequest()->getParam('ciudades_id'));
           foreach($ciudades_id as $ciudad_id){
               $ciudad = $this->_em->find("Application_Model_Ciudades", intval($ciudad_id));
               $carrera->getCiudad()->add($ciudad);
           }
           /*
            * This is the third one. Nothing to say about this.
            */
           $instituciones_id = explode(';', $this->getRequest()->getParam('instituciones_id'));
           foreach($instituciones_id as $institucion_id){
               $institucion = $this->_em->find("Application_Model_Instituciones", intval($institucion_id));
               $carrera->getInstituciones()->add($institucion);
           }

           $this->_em->persist($carrera);
           $this->_em->flush();
           //$this->redirector->gotoSimpleAndExit('index','Carrera','admin');     
        }
    }

嗯，我不知道还有什么可以展示......如果你能帮助我，请发表评论：）

- 编辑

我在模型“Carreras”的关联中添加了cascade = {“persist”}并且更改了错误：

An error occurred
Application error
Exception information:

Message: Class Doctrine\ORM\UnitOfWork is not a 
valid entity or mapped super class.

现在这是“Ciudades”模型，它存储了可用于测试的城市，并与每个城市中存在的机构相关联。

use Doctrine\Common\Collections\ArrayCollection;
/**
 * @Entity
 * @Table(name="ciudades")
 */
class Application_Model_Ciudades {
    /**
     * @Id @Column(type="integer")
     * @GeneratedValue
     */
    private $id;

    /** @Column(type="string") */
    private $ciudad;

    /** @Column(type="string") */
    private $departamento;

    /** @Column(type="string") */
    private $pais;

    /**
     * @ManyToMany(targetEntity="Application_Model_Instituciones")
     * @JoinTable(name="Ciudades_Instituciones",
     *      joinColumns={@JoinColumn(name="ciudades_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="instituciones_id", referencedColumnName="id")}
     *      )
     */
    private $instituciones;

    public function __construct()
    {
        $this->instituciones = new ArrayCollection();
    }

    public function getCiudad(){
        return $this->ciudad;
    }

    public function getId(){
        return $this->id;
    }

    public function getInstituciones(){
        return $this->instituciones;
    }

}

现在这是“Instituciones”模型，它存储了可用于测试的机构。

/**
 * @Entity
 * @Table(name="instituciones")
 */
class Application_Model_Instituciones {
    /**
     * @Id @Column(type="integer")
     * @GeneratedValue
     */
    private $id;

    /** @Column(type="string") */
    private $nombre;

    public function getId(){
        return $this->id;
    }

    public function getNombre(){
        return $this->nombre;
    }

}

现在这是“PruebasCarrera”模型，对我来说这个模型实体存储了测试的问题，每个问题都可以有一个支持这个问题的合作伙伴：

use Doctrine\Common\Collections\ArrayCollection;
/**
 * @Entity
 * @Table(name="pruebas_carrera")
 */
class Application_Model_PruebasCarrera extends Application_Model_PruebasBase{

    /**
     * @Id @Column(type="integer")
     * @GeneratedValue
     */
    private $id;

    /**
     * @ManyToMany(targetEntity="Application_Model_Patrocinadores")
     * @JoinTable(name="pruebascarrera_patrocinadores",
     *      joinColumns={@JoinColumn(name="pruebas_id", referencedColumnName="id", unique="true")},
     *      inverseJoinColumns={@JoinColumn(name="patrocinadores_id", referencedColumnName="id", unique=false)}
     *      )
     */
    protected $patrocinadores;

    /** @Column(type="string") */
    private $respuesta; 

    public function __construct() {
        $this->patrocinadores = new ArrayCollection();
    }

    public function setRespuesta($respuesta){
        $this->respuesta = $respuesta;
    }

    public function getPatrocinadores(){
        return $this->patrocinadores;
    }

    public function getId(){
        return $this->id;
    }

    public function getRespuesta(){
        return $this->respuesta;
    }

}

Answer 1

请显示相关实体的代码： Application_Model_Ciudades Application_Model_PruebasCarrera Application_Model_Instituciones

此时查看http://docs.doctrine-project.org/en/latest/reference/working-with-associations.html#transitive-persistence-cascade-operations

此时我认为你应该将cascade = {＆＃34; persist＆＃34;}添加到Application_Model_Ciudades实体。

学说2：将数据插入具有关联的实体

1 个答案: