我需要一些帮助。我有一个包含这个字符串的变量;
[{"id":"17","value":"123456789"},{"id":"18","value":"2012-06-13"},{"id":"19","value":"Kampala"},{"id":"20","value":"1"},{"id":"21","value":"500g"},{"id":"22","value":"Emirrets"},{"id":"23","value":"q"},{"id":"24","value":"q"},{"id":"25","value":"q"},{"id":"26","value":"q"},{"id":"27","value":"q"},{"id":"28","value":"q"},{"id":"29","value":"2"},{"id":"30","value":"987654321"},{"id":"45","value":"1"},{"id":"46","value":"1"}]
我需要检索每对的id和值,并在PHP中创建任何数组。
答案 0 :(得分:1)
您可以使用json_decode并将第二个参数传递为true
,以便它返回一个这样的数组
$json = '[{"id":"17","value":"123456789"},{"id":"18","value":"2012-06-13"},{"id":"19","value":"Kampala"},{"id":"20","value":"1"},{"id":"21","value":"500g"},{"id":"22","value":"Emirrets"},{"id":"23","value":"q"},{"id":"24","value":"q"},{"id":"25","value":"q"},{"id":"26","value":"q"},{"id":"27","value":"q"},{"id":"28","value":"q"},{"id":"29","value":"2"},{"id":"30","value":"987654321"},{"id":"45","value":"1"},{"id":"46","value":"1"}]';
$decoded = json_decode($json,true);
print_r($decoded);
输出
Array
(
[0] => Array
(
[id] => 17
[value] => 123456789
)
[1] => Array
(
[id] => 18
[value] => 2012-06-13
)
[2] => Array
(
[id] => 19
[value] => Kampala
)
[3] => Array
(
[id] => 20
[value] => 1
)
.......
)
您可以使用foreach来循环使用。
foreach($decoded as $de){
// access id with $de['id']
// access value with $de['value']
}
答案 1 :(得分:0)
你有一个json字符串。您可以使用函数json_decode将其转换为数组 检查此代码。
$str = '[{"id":"17","value":"123456789"},{"id":"18","value":"2012-06-13"}, {"id":"19","value":"Kampala"},{"id":"20","value":"1"},{"id":"21","value":"500g"},{"id":"22","value":"Emirrets"},{"id":"23","value":"q"},{"id":"24","value":"q"},{"id":"25","value":"q"},{"id":"26","value":"q"},{"id":"27","value":"q"},{"id":"28","value":"q"},{"id":"29","value":"2"},{"id":"30","value":"987654321"},{"id":"45","value":"1"},{"id":"46","value":"1"}]';
$array = json_decode($str);
foreach($array as $temp){
echo "ID : ".$temp->id."\t Value: ".$temp->value;
echo "<br />";
}