所以我有一个看起来像这样的文件:
1st 2nd nth
e1, v1, 1
e1, v3, 2
e1, v4, 4
e1, v5, 7
e2, v1, 1
., ., .
., ., .
., ., .
我希望第一列成为散列映射的关键字(e1,或e2或e3),并将值作为名为“Ratings”的ArrayList,我希望第二列具有它的值( int),在arraylist的第n个索引中。
到目前为止,这是我的完整代码:
import java.util.*;
import java.io.*;
public class Setup
{
public static void Setup(String[] args)
{
String user;
int value, location;
//Create a Hashmap that holds a string key and an ArrayList value
HashMap<String, ArrayList<Integer>> userRatings = new HashMap<String, ArrayList<Integer>>();
try
{
BufferedReader bufferReader = new BufferedReader(new FileReader("Student list.txt")); //read from file
String line, sentence; //declare two string variables
String[] sData; //declare a string array (store the contents here)
line = bufferReader.readLine(); //Read the line
while (line != null) //While there is a line, do this:
{
line = bufferReader.readLine();
sData = line.split(", "); //Into the string array, enter individual values in the line split by the ", " characters
int iData[] = new int[sData.length]; //Create an int array the size of the string array
user = sData[0];
for (int i = 0; i <sData.length; i++) //fill the int array with the int-version of the string array
{
iData[i] = Integer.parseInt(sData[i]); //pass the strings as integers into the integer array
}
value = iData[1];
location = iData[2];
if(!userRatings.containsKey(user)) //The user does not have ratings.
{
ArrayList<Integer> ratings = new ArrayList<Integer>();
// ratings = userRatings.get(user);
for (int j = 0; j < 50; j++)
{
ratings.add(j);
}
System.out.println(user + " " + userRatings.get(user));
}
else //The user has ratings
{
userRatings.get(user).add(location,value);
System.out.println(user + " " + userRatings.get(user));
}
}
bufferReader.close();
} catch (FileNotFoundException e)
{
System.out.println("File does not exist or could not be found.");
}
catch (IOException e)
{
System.out.println("Can't read from file");
}
catch (NullPointerException e)
{
}
}
}
我在修改arraylist的内容方面遇到了问题。
总结: 文件第1列中的每个字符串在hashmap(userList)中都有自己的键 程序将检查它是否有密钥,如果没有密钥,它将创建一个新的arraylist作为密钥的值。 arrayList将填充50个索引,其中包含“0”。 之后,arraylist将从文件中添加新值,其中第二列中的整数将添加到第n列的相应值。
我如何填充arraylist,如何编辑它以便如果我想在用户e6的第n个索引处添加一个新整数,我可以吗?
答案 0 :(得分:1)
我认为您可以只读取第n个值并使用它在列表中插入值。
e.g。
List<Integer> list = new ArrayList<Integer>();
//values values (0) will be inserted into the list
//after that for each value in the nth you do something as follows
//i is the value in the nth column, if the least value for i is 1 otherwise just use i
list.add(i-1, value);
同样用于引用,接口而不是按如下方式实现类 -
Map<String, List<Integer>> userRatings = new HashMap<String, List<Integer>>();
List<Integer> ratings = new ArrayList<Integer>();
将值插入用户e6的第n个索引:
List<Integer> ratings = userRatings.get(user);
if(ratings == null) {
ratings = new ArrayList<Integer>(); //it's not in the map yet
//insert 50 0s here
userRatings.put(user, ratings);
}
ratings.add(i, value); //i is the nth index and value is the rating
答案 1 :(得分:0)
如果地图中没有给定的密钥,则必须添加新的密钥值对
if(!userRatings.containsKey(user)) //The user does not have ratings.
{
ArrayList<Integer> ratings = new ArrayList<Integer>();
for (int j = 0; j < 50; j++) {
ratings.add(j);
}
userRatings.put(user, ratings); // place new mapping
System.out.println(user + " " + userRatings.get(user));
} else //The user has ratings
{
ArrayList<Integer> ratings = userRatings.get(user);
ratings.add(location,value); // Update your list with location and value
System.out.println(user + " " + userRatings.get(user));
}
iData[i] = Integer.parseInt(sData[i]);
这不起作用,因为你的文件内容会抛出NumberFormatException
,因为v1无法解析为int。
相反,你可以这样做:
value = Integer.parseInt(sData[1].trim().substring(1));
location = Integer.parseInt(sData[2].trim());
要比较两个键的值:
方法1
ArrayList<Integer> first = userRatings.get(e1);
ArrayList<Integer> second = userRatings.get(e2);
//Taking the smallest size will ensure that we don't get IndexOutOfBoundsException.
int length = first.size() < second.size() ? first.size() : second.size();
for(int iDx = 0; iDx < legth; iDx++){
//compare content
}
方法2
ArrayList<Integer> first = userRatings.get(e1);
ArrayList<Integer> second = userRatings.get(e2);
Arrays.equals(first.toArray(), second.toArray());