我不知道为什么Android / Java会这样做,这很难想象,因为我非常疲惫,而且现在还不能自己思考。
我正在创建静态函数并以这种方式输入和执行代码,我不认为这是因为它还没有超过if语句;你们都在想什么?我敢打赌,这是一个简单的解决方案,我无法理解我的生活。
代码:
public class LogIn extends Activity {
Button login;
EditText user;
EditText pass;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
TextView top = (TextView) findViewById(R.id.textView2);
EditText user = (EditText) findViewById(R.id.etUser);
EditText pass = (EditText) findViewById(R.id.etPass);
CheckBox stay = (CheckBox) findViewById(R.id.cBStay);
Button login = (Button) findViewById(R.id.btLogin);
Process();
}
private void Process() {
// TODO Auto-generated method stub
login.setOnClickListener( new View.OnClickListener() {
public void onClick(View v) {
// TODO Auto-generated method stub
String user1 = user.getText().toString();
String pass1 = pass.getText().toString();
if(user1 !=null &user1.length()>=1 & pass1 !=null &pass1.length()>=1) {
ComHelper.SendLogin(user1, pass1);
}
}
});
}
}
logcat的:
06-03 22:34:01.178: E/AndroidRuntime(2599): FATAL EXCEPTION: main
06-03 22:34:01.178: E/AndroidRuntime(2599): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.gta5news.qwuik/com.gta5news.qwuik.LogIn}: java.lang.NullPointerException
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1956)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1981)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.app.ActivityThread.access$600(ActivityThread.java:123)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1147)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.os.Handler.dispatchMessage(Handler.java:99)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.os.Looper.loop(Looper.java:137)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.app.ActivityThread.main(ActivityThread.java:4424)
06-03 22:34:01.178: E/AndroidRuntime(2599): at java.lang.reflect.Method.invokeNative(Native Method)
06-03 22:34:01.178: E/AndroidRuntime(2599): at java.lang.reflect.Method.invoke(Method.java:511)
06-03 22:34:01.178: E/AndroidRuntime(2599): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784)
06-03 22:34:01.178: E/AndroidRuntime(2599): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551)
06-03 22:34:01.178: E/AndroidRuntime(2599): at dalvik.system.NativeStart.main(Native Method)
06-03 22:34:01.178: E/AndroidRuntime(2599): Caused by: java.lang.NullPointerException
06-03 22:34:01.178: E/AndroidRuntime(2599): at com.gta5news.qwuik.LogIn.Process(LogIn.java:32)
06-03 22:34:01.178: E/AndroidRuntime(2599): at com.gta5news.qwuik.LogIn.onCreate(LogIn.java:26)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.app.Activity.performCreate(Activity.java:4465)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1049)
06-03 22:34:01.178: E/AndroidRuntime(2599): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1920)
答案 0 :(得分:6)
我知道这是事实,但仅仅因为Process()
方法中有一行。
您的实例成员login
从未初始化,因此它是null
,因此,当您调用NullPointerException
方法时,它会抛出Process()
。
如果您查看onCreate()
方法,则不会将Button
'登录'保存到实例成员,而是保存到本地成员。
login = (Button) findViewById(R.id.btLogin);
这应解决一个问题,但您的其他实例成员也会遇到同样的问题(至少user
和pass
)。
user = (EditText) findViewById(R.id.etUser);
pass = (EditText) findViewById(R.id.etPass);