我试图通过interviewstreet学习erlang。我现在只是学习这门语言所以我什么都不知道。我想知道如何从stdin读取并写入stdout。
我想写一个简单的程序,写下" Hello World!" stdin收到的次数。
所以使用stdin输入:
6
写入stdout:
Hello World!
Hello World!
Hello World!
Hello World!
Hello World!
Hello World!
理想情况下,我会一次读取stdin一行(即使在这种情况下它只是一位数),所以我想我会使用get_line。这就是我现在所知道的全部。
感谢
由于
答案 0 :(得分:22)
这是另一种解决方案,可能更具功能性。
#!/usr/bin/env escript
main(_) ->
%% Directly reads the number of hellos as a decimal
{ok, [X]} = io:fread("How many Hellos?> ", "~d"),
%% Write X hellos
hello(X).
%% Do nothing when there is no hello to write
hello(N) when N =< 0 -> ok;
%% Else, write a 'Hello World!', and then write (n-1) hellos
hello(N) ->
io:fwrite("Hello World!~n"),
hello(N - 1).
答案 1 :(得分:1)
这是我的镜头。我已经使用了escript,因此它可以从命令行运行,但它可以很容易地放入模块中:
#!/usr/bin/env escript
main(_Args) ->
% Read a line from stdin, strip dos&unix newlines
% This can also be done with io:get_line/2 using the atom 'standard_io' as the
% first argument.
Line = io:get_line("Enter num:"),
LineWithoutNL = string:strip(string:strip(Line, both, 13), both, 10),
% Try to transform the string read into an unsigned int
{ok, [Num], _} = io_lib:fread("~u", LineWithoutNL),
% Using a list comprehension we can print the string for each one of the
% elements generated in a sequence, that goes from 1 to Num.
[ io:format("Hello world!~n") || _ <- lists:seq(1, Num) ].
如果您不想使用列表推导,这是对最后一行代码的类似方法,使用list:foreach和相同的序列:
% Create a sequence, from 1 to Num, and call a fun to write to stdout
% for each one of the items in the sequence.
lists:foreach(
fun(_Iteration) ->
io:format("Hello world!~n")
end,
lists:seq(1,Num)
).
答案 2 :(得分:0)
% Enter your code here. Read input from STDIN. Print output to STDOUT
% Your class should be named solution
-module(solution).
-export([main/0, input/0, print_hello/1]).
main() ->
print_hello(input()).
print_hello(0) ->io:format("");
print_hello(N) ->
io:format("Hello World~n"),
print_hello(N-1).
input()->
{ok,[N]} = io:fread("","~d"),
N.