Question

我正在尝试使用HQL从数据库中发出选择

这是代码：

public Collection<Link> getAllLinksForDevice(Device device) {
    Session session = sessionFactory.getCurrentSession();
    String hql = "SELECT Link as l WHERE l.device1 = :deviceId OR l.device2 = :deviceId";
    Query query = session.createQuery(hql); <-- Fails here!!
    query.setParameter("deviceId",device.getId());
    Collection<Link> linkList  = query.list();
    return linkList;
}

和链接实体：

@Id
@Column(name = "id")
@GeneratedValue
private int id;

@ManyToOne
@JoinColumn(name="device1_id")
private Device device1;

@ManyToOne
@JoinColumn(name="device2_id")
private Device device2;

设备实体：

@Entity
@Table(name = "device")
public class Device {

    @Id
    @Column(name = "id")
    @GeneratedValue
    private int id;

    @Column(name = "dns_Name")
    private String dnsName;

    @Column(name = "ip_address_v4")
    private String ipV4;

    @Column(name = "device_type")
    private int deviceType;

    @ManyToOne
    @JoinColumn(name="area_id")
    private Area area;

但我得到一个例外：

15：10：55,570 DEBUG ErrorCounter：51 - ：0：0：子树意外结束：0：0：子树的意外结束在org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList（HqlSqlBaseWalker.java:3117）在org.hibernate.hql.antlr.HqlSqlBaseWalker.fromClause（HqlSqlBaseWalker.java:720）在org.hibernate.hql.antlr.HqlSqlBaseWalker.query（HqlSqlBaseWalker.java:571）在org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement（HqlSqlBaseWalker.java:288）在org.hibernate.hql.antlr.HqlSqlBaseWalker.statement（HqlSqlBaseWalker.java:231）在org.hibernate.hql.ast.QueryTranslatorImpl.analyze（QueryTranslatorImpl.java:254）在org.hibernate.hql.ast.QueryTranslatorImpl.doCompile（QueryTranslatorImpl.java:185）

和

15：10：54,622 ERROR PARSER：56 - 路径无效：'l.device1' 15：10：54,628 DEBUG ErrorCounter：51 - 路径无效：'l.device1' 路径无效：'l.device1' 在org.hibernate.hql.ast.util.LiteralProcessor.lookupConstant（LiteralProcessor.java:135）在org.hibernate.hql.ast.tree.DotNode.resolve（DotNode.java:216）在org.hibernate.hql.ast.tree.FromReferenceNode.resolve（FromReferenceNode.java:117）在org.hibernate.hql.ast.tree.FromReferenceNode.resolve（FromReferenceNode.java:113）在org.hibernate.hql.ast.HqlSqlWalker.resolve（HqlSqlWalker.java:854）在org.hibernate.hql.antlr.HqlSqlBaseWalker.expr(HqlSqlBaseWalker.java:1293）在org.hibernate.hql.antlr.HqlSqlBaseWalker.exprOrSubquery（HqlSqlBaseWalker.java:4243）在org.hibernate.hql.antlr.HqlSqlBaseWalker.comparisonExpr（HqlSqlBaseWalker.java:3722）

Answer 1

您的HQL查询中有两个语法错误：

没有from子句。 select Link as l where...无效。正确的语法是select l from Link as l where ...或只是select l from Link l where...。
“链接”实体的device1（和device2字段）字段属于Device类型。您无法将其与ID进行比较。您可以将其与Device个实例进行比较，也可以将device1的ID与ID where l.device1 = :someDeviceInstanceContainingTheIdYouSearchFor或where l.device1.id = :someDeviceId进行比较。

HQL在无效路径上选择异常

1 个答案: