模板使用代码错误

时间:2012-06-03 11:37:34

标签: c++ templates

我最近开始学习C ++并且在理解模板机制方面存在问题。 首先,任务是构建用户定义的二叉树。我无法编译我的代码。

#include <iostream>
using namespace std;
template <typename DataType> struct TreeNode
{
    TreeNode(DataType val, TreeNode *leftPtr = null, TreeNode *rightPtr = null)
    {
        left = leftPtr;
        right = rightPtr;
        data = val;
    }
    TreeNode *left, *right;
    DataType data;
};
template <typename DataType> TreeNode *BuildTree()
{
    TreeNode *root = new TreeNode(10, new TreeNode(20), new TreeNode(30));

    TreeNode *curRoot = root;
    curRoot = curRoot->left;
    curRoot->left = new TreeNode(40);
    curRoot->left->left = new TreeNode(70);
    curRoot->right = new TreeNode(50);
    curRoot = curRoot->right;
    curRoot->left = new TreeNode(80, new TreeNode(100), new TreeNode(110));
    curRoot = root->right;
    curRoot->left = new TreeNode(60);
    curRoot = curRoot->left;
    curRoot->right = new TreeNode(90, new TreeNode(120), new TreeNode(130));

    return root;
}
int main()
{
    TreeNode *treeRoot = BuildTree<int>();
    cin.get();
    return 0;
}

函数BuildTree使用具体的数据类型构建树的具体实例。请帮我理解我的错误。 请不要注意使用后我没有记忆的事实。那只是一个草案。

2 个答案:

答案 0 :(得分:4)

由于TreeNode是模板类,因此您必须在使用时指定专业化:

template <typename DataType> TreeNode *BuildTree()

应该是

template <typename DataType> TreeNode<DataType> *BuildTree()

TreeNode *root = new TreeNode(10, new TreeNode(20), new TreeNode(30));

应该是

TreeNode<DataType> *root = new TreeNode(10, new TreeNode(20), new TreeNode(30));

和方法中的其他人,加上main

TreeNode<int> *treeRoot = BuildTree<int>();

而不是

TreeNode *treeRoot = BuildTree<int>();

答案 1 :(得分:0)

我认为您的代码应如下所示:

#include <iostream>
using namespace std;
template <typename DataType> struct TreeNode
{
    TreeNode(DataType val, TreeNode<DataType> *leftPtr = null, TreeNode<DataType> *rightPtr = null)
    {
        left = leftPtr;
        right = rightPtr;
        data = val;
    }
    TreeNode<DataType> *left, *right;
    DataType data;
};
template <typename DataType> TreeNode<DataType> *BuildTree()
{
    TreeNode<DataType> *root = new TreeNode(10, new TreeNode<DataType>(20), new TreeNode<DataType>(30));

    TreeNode<DataType> *curRoot = root;
    curRoot = curRoot->left;
    curRoot->left = new TreeNode<DataType>(40);
    curRoot->left->left = new TreeNode<DataType>(70);
    curRoot->right = new TreeNode<DataType>(50);
    curRoot = curRoot->right;
    curRoot->left = new TreeNode<DataType>(80, new TreeNode<DataType>(100), new TreeNode<DataType>(110));
    curRoot = root->right;
    curRoot->left = new TreeNode<DataType>(60);
    curRoot = curRoot->left;
    curRoot->right = new TreeNode<DataType>(90, new TreeNode<DataType>(120), new TreeNode<DataType>(130));

    return root;
}
int main()
{
    TreeNode<int> *treeRoot = BuildTree<int>();
    cin.get();
    return 0;
}
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