Question

所以我想创建一个包含应用程序的Dll。我的代码：

BOOL APIENTRY DllMain( HANDLE hModule, 
                       DWORD  ul_reason_for_call, 
                       LPVOID lpReserved
                     )
{
    switch(ul_reason_for_call)
    {
        case DLL_PROCESS_ATTACH:
            StartApp();
            break;
    }

    return TRUE;
}

StartApp功能：

void StartApp()
{   
    //some declartions
    iPtr->Start();
}

问题是函数Start（）在连续循环中运行（就像while（true）），我认为这是问题导致dll永远不会中断并返回true。我试图在不同的线程中运行它，但这不起作用。

所以我的问题是如何使用dll？

如果DllMain没有完成并且没有返回TRUE会有问题吗？

Answer 1

是的，有一个问题是DllMain没有返回，正如文档所述：

When a DLL entry-point function is called because a process is loading, the function returns TRUE to indicate success. For processes using load-time linking, a return value of FALSE causes the process initialization to fail and the process terminates. For processes using run-time linking, a return value of FALSE causes the LoadLibrary or LoadLibraryEx function to return NULL, indicating failure. (The system immediately calls your entry-point function with DLL_PROCESS_DETACH and unloads the DLL.) The return value of the entry-point function is disregarded when the function is called for any other reason.

Source

您可以为StartApp函数创建一个包装函数，并通过您的dll公开它。之后，您可以从可执行文件中调用导出的StartApp函数（在加载dll之后）。确保你从一个不同的线程中调用它，因为它会阻止它。

在DLL中启动应用程序

1 个答案: