如标题中所述。如何遍历我从服务器获取的json数据。我得到这种json数据
{
"tag":"home",
"success":1,
"error":0,
"uid":"4fc8f94f1a51c5.32653037",
"name":"Saleem",
"profile_photo":"http:\/\/example.info\/android\/profile_photos\/profile1.jpg",
"places":
{
"place_photo":"http:\/\/example.info\/android\/places_photos\/place1.jpg",
"created_at":"2012-06-02 00:00:00",
"seeked":"0"
}
}
{
"tag":"home",
"success":1,
"error":0,
"uid":"4fc8f94f1a51c5.32653037",
"name":"Name",
"profile_photo":"http:\/\/example.info\/android\/profile_photos\/profile1.jpg",
"places":
{
"place_photo":"http:\/\/example.info\/android\/places_photos\/place1.jpg",
"created_at":"2012-06-02 00:00:00",
"seeked":"0"
}
}
{
"tag":"home",
"success":1,
"error":0,
"uid":"4fc8f94f1a51c5.32653037",
"name":"Name",
"profile_photo":"http:\/\/example.info\/android\/profile_photos\/profile1.jpg",
"places":
{
"place_photo":"http:\/\/example.info\/android\/places_photos\/place1.jpg",
"created_at":"2012-06-02 00:00:00",
"seeked":"0"
}
}
这是我获取json数据的地方
public class Home extends Activity {
Button btnLogout;
ScrollView svHome;
UserFunctions userFunctions;
LoginActivity userid;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
userid = new LoginActivity();
svHome = (ScrollView)findViewById(R.id.svHome);
setContentView(R.layout.home);
userFunctions = new UserFunctions();
/***********************************************************/
//here is where my above mentioned json data is
JSONObject json = userFunctions.homeData();
try {
if(json != null && json.getString("success") != null) {
//login_error.setText("");
String res = json.getString("success");
//userid = json.getString("uid").toString();
if(Integer.parseInt(res) == 1) {
//currently this only shows the first json object
Log.e("pla", json.toString());
} else {
//login_error.setText(json.getString("error_msg"));
}
} else {
Toast.makeText(getBaseContext(), "No data", Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
e.printStackTrace();
}
/*******************************************************/
}
}
更新
根据答案中给出的链接进行更改后。这是我的更改
/***********************************************************/
JSONObject json = userFunctions.homeData();
String jsonData = json.toString();
try {
if(json != null && json.getString("success") != null) {
//login_error.setText("");
String res = json.getString("success");
//userid = json.getString("uid").toString();
if(Integer.parseInt(res) == 1) {
JSONArray jsonArray = new JSONArray(jsonData);
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject jsonObject = jsonArray.getJSONObject(i);
Log.e("Object", jsonObject.getString("places"));
//Log.i(ParseJSON.class.getName(), jsonObject.getString("text"));
}
Log.e("pla", json.toString());
} else {
//login_error.setText(json.getString("error_msg"));
}
} else {
Toast.makeText(getBaseContext(), "No data", Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
e.printStackTrace();
}
答案 0 :(得分:2)
请查看链接
http://www.androidhive.info/2012/01/android-json-parsing-tutorial/
如果可能的话,在json中进行了更改,因为在json中没有数组括号“[”“]”,你需要在循环中进行操作
json应该是那样的
{
"arrayKey": [
{
"tag": "home",
"success": 1,
"error": 0,
"uid": "4fc8f94f1a51c5.32653037",
"name": "Saleem",
"profile_photo": "http://example.info/android/profile_photos/profile1.jpg",
"places": {
"place_photo": "http://example.info/android/places_photos/place1.jpg",
"created_at": "2012-06-02 00:00:00",
"seeked": "0"
}
},
{
"tag": "home",
"success": 1,
"error": 0,
"uid": "4fc8f94f1a51c5.32653037",
"name": "Saleem",
"profile_photo": "http://example.info/android/profile_photos/profile1.jpg",
"places": {
"place_photo": "http://example.info/android/places_photos/place1.jpg",
"created_at": "2012-06-02 00:00:00",
"seeked": "0"
}
}
]
}
答案 1 :(得分:0)
您可以使用如下的json库:
import org.json.JSONArray; import org.json.JSONObject;
允许您将json数据读入数组:
JSONArray jsonArray = new JSONArray([你的json数据]);
试用本教程:http://www.vogella.com/articles/AndroidJSON/article.html
答案 2 :(得分:0)
正如您的logcat所述,您正在尝试将JSONObject转换为JSONArray:
org.json.JSONException: Value {"uid":"4fc8f94f1a51c5.32653037","places":{"place_photo":"http://example.info/android/places_photos/place1.jpg","created_at":"2012-06-02 00:00:00","seeked":"0","longitude":"24.943514","latitude":"60.167112"},"error":0,"success":1,"tag":"home","profile_photo":"http://example.info/android/profile_photos/profile1.jpg","name":"Zafar Saleem"} of type org.json.JSONObject cannot be converted to JSONArray
尝试调试代码 - 找出引发异常的位置,并在那里创建一个JSONObject而不是JSONArray。
答案 3 :(得分:0)
我推荐的另一种方法是使用GSON库,这很容易减轻痛苦。格式良好的Json