Question

我似乎无法使用JAX-WS Web服务和hibernate。尽管我做了什么，@XMLInverseReference不起作用。我希望它能填写application上的Site变量。我在做什么或理解错了？

我收到：org.hibernate.PropertyValueException: not-null property references a null or transient value: Site.application。如果我将@XMLElement添加到Site.application，那么我会从JAXB获得循环引用异常。

值得一提的是，所有的编组和解组都是由JAX-WS WSServlet端点处理的。

此外，我通过执行以下操作验证了我的jaxb.properties是否正常工作：

public class Run {
    public static void main(String[] args) throws Exception {
        System.out.println(JAXBContext.newInstance(Site.class).getClass());
    }
}

<小时/> 应用：

@Entity
@Table(schema = "dbo", name = "Applications")
@XmlAccessorType(XmlAccessType.NONE)
@XmlRootElement
public class Application {
    @Id
    @Column(name = "id", nullable = false, insertable = false, updatable = false)
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @RemoteProperty
    @XmlElement
    private Integer id;
    @Column(name = "code", nullable = false, unique = true)
    @NaturalId
    @XmlElement
    private String code;
    @Column(name = "name")
    @XmlElement
    private String name;
    @OneToMany(mappedBy = "application", fetch = FetchType.EAGER)
    @Cache(usage = org.hibernate.annotations.CacheConcurrencyStrategy.READ_WRITE)
    @Cascade(value = {CascadeType.MERGE, CascadeType.PERSIST, CascadeType.DELETE, CascadeType.DELETE_ORPHAN})
    @Sort(type = SortType.NATURAL)
    @XmlElement
    private Set<Site> sites = new TreeSet<Site>();
}

网站：

@Entity
@Table(schema = "dbo", name = "Sites")
@XmlAccessorType(XmlAccessType.NONE)
@XmlRootElement
public class Site implements Identifiable<Integer>, Comparable<Site> {
    @Id
    @Column(name = "id", nullable = false, insertable = false, updatable = false)
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;
    @Column(name = "address", unique = true)
    @NaturalId(mutable = true)
    @XmlID
    private String address;
    @Column(name = "ssl")
    @XmlAttribute(required = true)
    private boolean ssl;
    @ManyToOne
    @JoinColumn(name = "applicationCode", nullable = false, referencedColumnName = "code")
    @XmlInverseReference(mappedBy = "code")
    private Application application;
}

jaxb.properties

javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory

Answer 1

JAX-WS实现不一定尊重JAXB.properties。如果您使用的是WebLogic 12.1.1或GlassFish 3.1.2，则以下内容将有所帮助：

XmlInverseReference，Hibernate，JAXWS和Moxy

1 个答案: