Question

我的OnItemSelectedListener有一个Spinner，但是当所选项目与前一项目相同时，不会调用它。显然OnClickListener不是Spinner的选项。每次用户点击某个项目时我都需要抓住。有什么想法吗？

也许这个Spinner位于ActionBar内部会扰乱正常行为？

@Override
public void onCreateOptionsMenu(Menu menu, MenuInflater inflater) {
    inflater.inflate(R.menu.tracklist_menu, menu);
    Spinner spinner = (Spinner) menu.findItem(R.id.option_ordering_spinner)
            .getActionView();
    spinner.setAdapter(mSpinnerAdapter);
    spinner.setSelection(PrefsHelper.getOrderingSpinnerPos(prefs));
    spinner.setOnItemSelectedListener(new OnItemSelectedListener() {

        @Override
        public void onItemSelected(AdapterView<?> parent, View view,
                int position, long id) {
            String str = "selected";
            System.out.println(str);
            if (optionMenuInitialized) {

                switch (position) {
                case 0:
                    // rdm
                    getActivity()
                            .sendBroadcast(
                                    new Intent(
                                            MyIntentAction.DO_RESHUFFLE_PLAYLIST));
                    smp.setCurrentTracklistCursorPos(-1);
                    trackAdapter.notifyDataSetChanged();
                    break;
                case 1:
                    // artist
                    getActivity()
                            .sendBroadcast(
                                    new Intent(
                                            MyIntentAction.DO_ORDER_PLAYLIST_BY_ARTIST));
                    smp.setCurrentTracklistCursorPos(-1);
                    trackAdapter.notifyDataSetChanged();
                    break;
                case 2:
                    // folder
                    getActivity()
                            .sendBroadcast(
                                    new Intent(
                                            MyIntentAction.DO_ORDER_PLAYLIST_BY_FOLDER));
                    smp.setCurrentTracklistCursorPos(-1);
                    trackAdapter.notifyDataSetChanged();
                    break;
                }
                PrefsHelper.setOrderingSpinnerPos(prefEditor, position);
                prefEditor.commit();
            }
            optionMenuInitialized = true;
        }

        @Override
        public void onNothingSelected(AdapterView<?> parent) {
        }
    });
}

Answer 1

好的，我终于找到了一个解决方案，通过创建我自己的扩展Spinner的类：

public class MySpinner extends Spinner {
OnItemSelectedListener listener;

public MySpinner(Context context, AttributeSet attrs) {
    super(context, attrs);
}

@Override
public void setSelection(int position) {
    super.setSelection(position);
    if (listener != null)
        listener.onItemSelected(null, null, position, 0);
}

public void setOnItemSelectedEvenIfUnchangedListener(
        OnItemSelectedListener listener) {
    this.listener = listener;
}
}

Answer 2

我发现了这项工作，而不是提供的工作

/** Spinner extension that calls onItemSelected even when the selection is the same as its previous value */
public class NDSpinner extends Spinner {

  public NDSpinner(Context context)
  { super(context); }

  public NDSpinner(Context context, AttributeSet attrs)
  { super(context, attrs); }

  public NDSpinner(Context context, AttributeSet attrs, int defStyle)
  { super(context, attrs, defStyle); }

  @Override public void
  setSelection(int position, boolean animate)
  {
    boolean sameSelected = position == getSelectedItemPosition();
    super.setSelection(position, animate);
    if (sameSelected) {
      // Spinner does not call the OnItemSelectedListener if the same item is selected, so do it manually now
      getOnItemSelectedListener().onItemSelected(this, getSelectedView(), position, getSelectedItemId());
    }
  }

  @Override public void
  setSelection(int position)
  {
    boolean sameSelected = position == getSelectedItemPosition();
    super.setSelection(position);
    if (sameSelected) {
      // Spinner does not call the OnItemSelectedListener if the same item is selected, so do it manually now
      getOnItemSelectedListener().onItemSelected(this, getSelectedView(), position, getSelectedItemId());
    }
  }
}

Answer 3

这里有一个更好的实施：

public class SpinnerPlus extends Spinner {
    AdapterView.OnItemSelectedListener listener;

    public SpinnerPlus(Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    @Override
    public void setSelection(int position) {
        super.setSelection(position);
        if (listener != null)
            listener.onItemSelected(this, getSelectedView(), position, 0);
    }

    public void setOnItemSelectedEvenIfUnchangedListener(
            AdapterView.OnItemSelectedListener listener) {
        this.listener = listener;
    }
}

Answer 4

尽管选择了最后一个索引的值，但要使微调器更改，只需使用：

spinner.setSelection(0);

在调用其他选择之前

spinner.setSelection(number);

这样，微调器将触发两次 OnItemSelected 事件。只要确保它第二次做你需要的任何事情。

Answer 5

如果它仍然是实际的，则应该正确调用回调

@Override
public void setSelection(int position) {
    super.setSelection(position);
    if(listener != null)
        listener.onItemSelected(this, getChildAt(position), position, 0);
}

马丁

Answer 6

重写常见的解决方案，但具有：

牢记androidx
从AppCompatSpinner扩展
使用内置的OnItemSelectedListener侦听器，而不是创建自己的侦听器
添加了初始侦听器调用技巧

这里：

import android.content.Context;

import androidx.annotation.Nullable;
import androidx.appcompat.widget.AppCompatSpinner;


public class FixedSpinner extends AppCompatSpinner {
    // add other constructors that you need
    public FixedSpinner(Context context, int mode) {
        super(context, mode);
    }

    private void processSelection(int position) {
        boolean sameSelected = position == getSelectedItemPosition();
        final OnItemSelectedListener listener = getOnItemSelectedListener();
        if (sameSelected && listener != null) {
            // Spinner does not call the OnItemSelectedListener if the same item is selected, so do it manually now
            listener.onItemSelected(this, getSelectedView(), position, getSelectedItemId());
        }
    }

    @Override
    public void setSelection(int position) {
        processSelection(position);
        super.setSelection(position);
    }

    @Override
    public void
    setSelection(int position, boolean animate) {
        processSelection(position);
        super.setSelection(position, animate);
    }

    @Override
    public void setOnItemSelectedListener(@Nullable OnItemSelectedListener listener) {
        // hack for initial listener call
        setSelection(0, false);
        super.setOnItemSelectedListener(listener);
    }
}

Answer 7

最简单的解决方案：

spinner.performItemClick（视图，位置，ID）

Answer 8

我遇到了同样的问题，每次适配器更改项目时都通过设置onItemSelectedListener来解决。

Answer 9

这是一个更好的实现-

自定义微调器类-

import android.content.Context;
import android.util.AttributeSet;
import androidx.appcompat.widget.AppCompatSpinner;

public class CSpinner extends AppCompatSpinner {

    private int lastPosition = 0;

    public CSpinner(Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    @Override
    public void setSelection(int position) {
        super.setSelection(position);
        boolean sameSelected = lastPosition == getSelectedItemPosition();
        OnItemSelectedListener onItemSelectedListener = getOnItemSelectedListener();
        if (sameSelected && onItemSelectedListener != null) {
            onItemSelectedListener.onItemSelected(this, getSelectedView(), position, getSelectedItemId());
        }
        lastPosition = position;
    }
}

设置侦听器-

spn.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
            Log.d("onItemSelected", String.valueOf(position));
        }

        @Override
        public void onNothingSelected(AdapterView<?> parent) {
            
        }
    });

Answer 10

我找到了一个简单的解决方案

再次调用setAdapter代替第二个微调器的notifyDataSetChanged

Spinner：当选定项保持不变时，不会调用onItemSelected

10 个答案: