Question

我必须从此网站获取号码的位置

lookupexpert.com/search_phone?phone_number=7322691678

我想要一个匹配

内的任何内容的正则表达式

<p class="location">OCEAN GATE, NJ</p>

我该怎么做？

这是我到目前为止所做的事情

<?php

$subject = file_get_contents("http://lookupexpert.com/search_phone?phone_number=7322691678");

$pattern = '#\<p class="location"\>(.+?)\<\/p\>#s';
preg_match($pattern, $subject, $matches, PREG_OFFSET_CAPTURE, 3);
print_r($matches);

?>

并且......我尝试使用Xpath，但没有那么好用，因为它没有经过适当的验证

/html/body/div/div[2]/div/ul/li[2]/p[4]

Answer 1

试试这个：

$subject = file_get_contents( 'http://www.lookupexpert.com/search_phone?phone_number=7322691678');
preg_match_all( '#<p class="location">(.*?)</p>#', $subject, $matches);
var_dump( $matches[1][1]);

输出：

string(14) "OCEAN GATE, NJ"

Demo

Answer 2

使用此XPath

//p[@class='location']/text()

或此RegEx

(?<=<p class="location">)([^<>]+)(?=</p>)

<强>码

preg_match_all('%(?<=<p class="location">)([^<>]+)(?=</p>)%', $subject, $result, PREG_PATTERN_ORDER);
$result = $result[1];

Answer 3

试试这个..

$string = '<p class="location">OCEAN GATE, NJ</p>';
$pattern = '/<p class="location">(.*)<\/p>/';

$preg = preg_match_all($pattern, $string, $match);
print_r($match);

Answer 4

最好不要依赖不可靠的正则表达式来解析HTML并使用DOM解析器。使用这样的代码：

$doc = new DOMDocument();
libxml_use_internal_errors(true);
// assuming search_phone.html contains your saved HTML source
#$doc->loadHTMLFile('search_phone.html'); // loads your html
$xpath = new DOMXPath($doc);
$value = $xpath->evaluate("string(//li[starts-with(@class, 'recordItem')]/
                           p[@class='location']/text())"); 
echo "Location Name: [$value]\n"; // prints your location

输出：

Location Name: [OCEAN GATE, NJ]

Preg匹配2个字符串之间的任何内容

4 个答案:

输出：