我有三个火线相机可以通过硬件自动同步,我正在尝试捕捉帧,将它们保存到我的硬盘中并在窗口中显示。
一切正常,但目前,我只能同时在三个不同的窗口中显示框架。
我想在一个窗口中显示框架,但我不知道该怎么做。 在这个link有cvShowManyImages()函数,但你必须同时传递三个帧,但我有一个for()循环,它可以一次考虑一帧。
这是我正在使用的代码:
for ( int j = 0; j < k_numImages; j++ )
{
// Display the timestamps for all cameras to show that the image
// capture is synchronized for each image
for ( unsigned int i = 0; i < numCameras; i++ )
{
Image image;
error = ppCameras[i]->RetrieveBuffer( &image );
if (error != PGRERROR_OK)
{
PrintError( error );
return -1;
}
IplImage* destImage = ConvertImageToOpenCV(&image);
char titolo[50];
sprintf(titolo, "titolo%d", i);
cvShowImage(titolo, destImage);
waitKey(1);
}
}
效果不错但为每个摄像机创建了不同的窗口,而我想在同一窗口中显示所有摄像机帧。
请帮帮我吗?
编辑:这是ConvertImageToOpenCV()函数。
IplImage* ConvertImageToOpenCV(Image* pImage)
{
IplImage* cvImage = NULL;
bool bColor = true;
CvSize mySize;
mySize.height = pImage->GetRows();
mySize.width = pImage->GetCols();
switch ( pImage->GetPixelFormat() )
{
case PIXEL_FORMAT_MONO8: cvImage = cvCreateImageHeader(mySize, 8, 1 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 1;
bColor = false;
break;
case PIXEL_FORMAT_411YUV8: cvImage = cvCreateImageHeader(mySize, 8, 3 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_422YUV8: cvImage = cvCreateImageHeader(mySize, 8, 3 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_444YUV8: cvImage = cvCreateImageHeader(mySize, 8, 3 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_RGB8: cvImage = cvCreateImageHeader(mySize, 8, 3 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_MONO16: cvImage = cvCreateImageHeader(mySize, 16, 1 );
cvImage->depth = IPL_DEPTH_16U;
cvImage->nChannels = 1;
bColor = false;
break;
case PIXEL_FORMAT_RGB16: cvImage = cvCreateImageHeader(mySize, 16, 3 );
cvImage->depth = IPL_DEPTH_16U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_S_MONO16: cvImage = cvCreateImageHeader(mySize, 16, 1 );
cvImage->depth = IPL_DEPTH_16U;
cvImage->nChannels = 1;
bColor = false;
break;
case PIXEL_FORMAT_S_RGB16: cvImage = cvCreateImageHeader(mySize, 16, 3 );
cvImage->depth = IPL_DEPTH_16U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_RAW8: cvImage = cvCreateImageHeader(mySize, 8, 3 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_RAW16: cvImage = cvCreateImageHeader(mySize, 8, 3 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_MONO12: printf("Not supported by OpenCV");
bColor = false;
break;
case PIXEL_FORMAT_RAW12: printf("Not supported by OpenCV");
break;
case PIXEL_FORMAT_BGR: cvImage = cvCreateImageHeader(mySize, 8, 3 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 3;
break;
case PIXEL_FORMAT_BGRU: cvImage = cvCreateImageHeader(mySize, 8, 4 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 4;
break;
case PIXEL_FORMAT_RGBU: cvImage = cvCreateImageHeader(mySize, 8, 4 );
cvImage->depth = IPL_DEPTH_8U;
cvImage->nChannels = 4;
break;
default: printf("Some error occured...\n");
return NULL;
}
if(bColor) {
if(!bInitialized)
{
colorImage.SetData(new unsigned char[pImage->GetCols() * pImage->GetRows()*3], pImage->GetCols() * pImage->GetRows()*3);
bInitialized = true;
}
pImage->Convert(PIXEL_FORMAT_BGR, &colorImage); //needs to be as BGR to be saved
cvImage->width = colorImage.GetCols();
cvImage->height = colorImage.GetRows();
cvImage->widthStep = colorImage.GetStride();
cvImage->origin = 0; //interleaved color channels
cvImage->imageDataOrigin = (char*)colorImage.GetData(); //DataOrigin and Data same pointer, no ROI
cvImage->imageData = (char*)(colorImage.GetData());
cvImage->widthStep = colorImage.GetStride();
cvImage->nSize = sizeof (IplImage);
cvImage->imageSize = cvImage->height * cvImage->widthStep;
}
else
{
cvImage->imageDataOrigin = (char*)(pImage->GetData());
cvImage->imageData = (char*)(pImage->GetData());
cvImage->widthStep = pImage->GetStride();
cvImage->nSize = sizeof (IplImage);
cvImage->imageSize = cvImage->height * cvImage->widthStep;
//at this point cvImage contains a valid IplImage
}
return cvImage;
}
答案 0 :(得分:2)
由于显而易见的原因,我无法测试下面的代码,但它说明了一种方法:
for ( int j = 0; j < k_numImages; j++ )
{
// Display the timestamps for all cameras to show that the image
// capture is synchronized for each image
IplImage* destImage[3]; // A-ha moment
for ( unsigned int i = 0; i < numCameras; i++ )
{
Image image;
error = ppCameras[i]->RetrieveBuffer( &image );
if (error != PGRERROR_OK)
{
PrintError( error );
return -1;
}
/* Since ConvertImageToOpenCV() doesn't copy the image data,
* we need to do that ourselves, because when this loop is done Image
* is destroyed and the data is lost.
*/
IplImage* tmp = ConvertImageToOpenCV(&image);
destImage[i] = cvCreateImage(cvGetSize(tmp), tmp->depth, tmp->nChannels);
cvCopy(tmp, destImage[i], NULL);
char titolo[50];
sprintf(titolo, "titolo%d", i);
}
cvShowManyImages("all", 3, destImage[0], destImage[1], destImage[2]);
waitKey(0);
// when you finish using them, release the allocated resources to prevent memory leaks
cvReleaseImage(&destImage[0]);
cvReleaseImage(&destImage[1]);
cvReleaseImage(&destImage[2]);
}
这个想法是创建一个IplImage*
数组来存储摄像机检索到的图像,所以在循环之后你可以访问所有这三个图像,并能够在一个窗口上显示它们。
修改强>
总结一下私人聊天,问题是cvShowManyImages()
采用彩色(3通道)图像,而他的相机正在返回灰度(单通道)图像。解决方案只是改变cvShowManyImages()
的实现,来自:
DispImage = cvCreateImage( cvSize(100 + size*w, 60 + size*h), 8, 3 );
要:
DispImage = cvCreateImage( cvSize(100 + size*w, 60 + size*h), 8, 1 );