想象一下,你有一个内部使用IDisposable对象的方法(例如streamreader),并且yield会在从文件中读取时返回项目。像这样:
public IEnumerable<YourObject> Read(string filename)
{
using(var filestream = new FileStream(filename, FileMode.Open))
{
using(var reader = new StreamReader(filestream))
{
string line;
while((line = reader.ReadLine()) != null)
{
yield return new YourObject(line);
}
}
}
}
当我使用不迭代完整集合的LINQ方法时,reader
和filestream
会被处理吗?
YourOjbect firstLine = Read("myfile.txt").First();
答案 0 :(得分:27)
当您使用yield
关键字编译器生成嵌套类时,该类实现IEnumerable
,IEnumerator
和IDisposable
并存储所有上下文数据:
[CompilerGenerated]
private sealed class <Read>d__0 : IEnumerable<YourObject>, IEnumerable, IEnumerator<YourObject>, IEnumerator, IDisposable
{
// Fields
private int <>1__state;
private YourObject <>2__current;
public string <>3__filename;
public Foo <>4__this;
private int <>l__initialThreadId;
public FileStream <filestream>5__1;
public string <line>5__3;
public StreamReader <reader>5__2;
public string filename;
// Methods
[DebuggerHidden]
public <Read>d__0(int <>1__state);
private void <>m__Finally4();
private void <>m__Finally5();
private bool MoveNext();
[DebuggerHidden]
IEnumerator<YourObject> IEnumerable<YourObject>.GetEnumerator();
[DebuggerHidden]
IEnumerator IEnumerable.GetEnumerator();
[DebuggerHidden]
void IEnumerator.Reset();
void IDisposable.Dispose();
// Properties
YourObject IEnumerator<YourObject>.Current { [DebuggerHidden] get; }
object IEnumerator.Current { [DebuggerHidden] get; }
}
如您所见,yielding方法的上下文中的所有局部变量都被移动到此生成的类的字段中。有趣的方法是那些名字中有m_Finally
的方法:
private void <>m__Finally4()
{
this.<>1__state = -1;
if (this.<filestream>5__1 != null)
{
this.<filestream>5__1.Dispose();
}
}
如您所见,这些方法处理您的一次性对象(FileStream
和StreamReader
)。什么时候叫?在枚举结束时,或者在调用Dispose
时:
private bool MoveNext()
{
bool CS$1$0000;
try
{
int CS$4$0001 = this.<>1__state;
if (CS$4$0001 != 0)
{
if (CS$4$0001 != 3)
{
goto Label_00AB;
}
goto Label_0074;
}
this.<>1__state = -1;
this.<filestream>5__1 = new FileStream(this.filename, FileMode.Open);
this.<>1__state = 1;
this.<reader>5__2 = new StreamReader(this.<filestream>5__1);
this.<>1__state = 2;
while ((this.<line>5__3 = this.<reader>5__2.ReadLine()) != null)
{
this.<>2__current = new YourObject(this.<line>5__3);
this.<>1__state = 3;
return true;
Label_0074:
this.<>1__state = 2;
}
this.<>m__Finally5();
this.<>m__Finally4();
Label_00AB:
CS$1$0000 = false;
}
fault
{
this.System.IDisposable.Dispose();
}
return CS$1$0000;
}
void IDisposable.Dispose()
{
switch (this.<>1__state)
{
case 1:
case 2:
case 3:
try
{
switch (this.<>1__state)
{
case 2:
case 3:
break;
default:
break;
}
try
{
}
finally
{
this.<>m__Finally5();
}
}
finally
{
this.<>m__Finally4();
}
break;
}
}
如果您期待First()
Enumerable
的实施,那么您会看到 - 它在返回第一项后调用Dispose
:
using (IEnumerator<TSource> enumerator = source.GetEnumerator())
{
if (enumerator.MoveNext())
{
return enumerator.Current;
}
}
因此将调用Dispose
自动生成的类,并且所有需要处置的局部变量将通过调用m_Finally
方法来处理。
BTW(不是关于使用LINQ)如果查看foreach statement implementation,您会看到枚举后枚举器被释放。因此,即使在Dispose
或异常的情况下,也会调用生成的类break
。
答案 1 :(得分:17)
是的,他们被处置了。
[编辑]
只要您使用LINQ方法或foreach循环,就会自动处理。但是,如果您决定在方法上手动调用.Enumerator().MoveNext()
,则需要自行处理。
[/编辑]
此代码:
class something : IDisposable
{
public void Dispose()
{
Console.WriteLine("Disposing");
Console.WriteLine(Environment.StackTrace);
}
}
static IEnumerable<string> ie()
{
using (new something())
{
Console.WriteLine("first");
yield return "first";
Console.WriteLine("second");
yield return "second";
}
}
static void Main(string[] args)
{
Console.WriteLine("before");
ie().First();
Console.WriteLine("after");
}
打印:
before
first
Disposing
at System.Environment.GetStackTrace(Exception e, Boolean needFileInfo)
at System.Environment.get_StackTrace()
at TestApp.Program.something.Dispose() in C:\Users\Tim\Documents\Visual Studi
o 2010\Projects\TestApp\TestApp\Program.cs:line 198
at TestApp.Program.<ie>d__0.<>m__Finally2() in C:\Users\Tim\Documents\Visual
Studio 2010\Projects\TestApp\TestApp\Program.cs:line 0
at TestApp.Program.<ie>d__0.System.IDisposable.Dispose() in C:\Users\Tim\Docu
ments\Visual Studio 2010\Projects\TestApp\TestApp\Program.cs:line 0
at System.Linq.Enumerable.First[TSource](IEnumerable`1 source)
at TestApp.Program.Main(String[] args) in C:\Users\Tim\Documents\Visual Studi
o 2010\Projects\TestApp\TestApp\Program.cs:line 214
at System.AppDomain._nExecuteAssembly(RuntimeAssembly assembly, String[] args
)
at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySec
urity, String[] args)
at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, C
ontextCallback callback, Object state, Boolean ignoreSyncCtx)
at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, C
ontextCallback callback, Object state)
at System.Threading.ThreadHelper.ThreadStart()
after
答案 2 :(得分:1)
这是一个普通的LINQ问题/问题,是的 - LINQ将在执行时处理它所获得的所有一次性元素。