Question

在我的控制器中，我添加了（$ id = null）函数。如果iput add / 43则有效。但是，如果任何验证失败它重新加载没有添加/ 43。（显示错误消息后）。怎么办？1.3版 控制器：

    function add($id = null) {    
if (!empty($this->data)) {     
              $this->ConsultingDet->create();   
      if ($this->ConsultingDet->save($this->data)) {  
          $this->Session->setFlash('The consulting det has been saved', true);  
          $this->redirect(array('controller' => 'patients', 'action' => 'home'));  
      } else {  
          $this->Session->setFlash('The consulting det could not be saved. Please,     try   again.', true);  
      }  
  }  
  if (is_null($id)) {  
      $this->set('id', 0);  
  }

}
add.ctp：

<div class="consultingDets form">
<?php echo $this->Form->create('ConsultingDet');?>  
<fieldset> 
    <div class="sub1">
        <?php

        echo $this->Form->input('patient_id', array('type' => 'hidden', 'value' => $patient['Patient']['id'])); 
        if ($id>0)       //This (id) brings out error on redirection
            echo $this->Form->input('id',array('type' => 'hidden', 'value' => $id));
            echo $this->Form->input('temperature');
        ?>            
    </div>         
</fieldset>
<?php echo $this->Form->end(__('Submit', true)); ?>

Answer 1

<?php echo $this->Form->create(null, array('url' => 
            array('controller' => 'consultingdets', 'action' => 'add', $id))); ?>
//<form action="consultingdets/add/43"

基本上将您需要的id作为参数传递给表单。这种方式，当你提交和验证失败时，蛋糕重定向到正确的URL（即你需要作为参数的id）

您的控制器名称可能有所不同。

Answer 2

你可以试试这个：

function add($id = null) {    
   if (!empty($this->data)) {     
              $this->ConsultingDet->create();   
      if ($this->ConsultingDet->save($this->data)) {  
          $this->Session->setFlash('The consulting det has been saved', true);  
          $this->redirect(array('controller' => 'patients', 'action' => 'home'));  
      } else {  
          $this->Session->setFlash('The consulting det could not be saved. Please,   try   again.', true);  
          //redirect to referrer page
          $this->redirect($this->referer());           
      }  
  }  
  if (is_null($id)) {  
      $this->set('id', 0);  
  }

添加功能时出错

2 个答案: