Question

这适用于player1name，但如何解决player2name？

当我在这里时，如果您知道任何有用的视觉查询构建器，请告诉我;）


SELECT 
_game.player1,
_user.username AS player1name,
_game.player2,
_user.username AS player2name,
FROM _game
LEFT JOIN _user ON _game.player1 = _user.id

Answer 1

SELECT player1,
_user.username AS player1name,
 player2,
_user2.username AS player2name
FROM _game
LEFT JOIN _user ON (_headsup.player1 = _user.id)
LEFT JOIN _user _user2 ON (_headsup.player2 = _user2.id)

Answer 2

我没有运行ATM的mySQL，但它应该像......

SELECT 
player1,
u1.username AS player1name,
 player2,
u2.username AS player2name,
FROM _game
INNER JOIN _user u1 ON _headsup.player1 = u1.id
INNER JOIN _user u2 ON _headsup.player2 = u2.id

即。联接上的别名，使用select中的别名。

然而，我对_headsup的来源感到茫然！

Answer 3

SELECT 
   player1,
   usr1.username AS player1name,
   player2,
   usr2.username AS player2name,
FROM _game
LEFT JOIN _user usr1 ON usr1.id= _game.player1
LEFT JOIN _user usr2 ON usr2.id= _game.player2

Answer 4

当您加入_game ON _user时，我认为您必须指定在这两个表上加入哪些字段。您指定了该加入，但随后尝试加入_headsup和_user。

不确定player1和player2是什么，但由于您没有说明它们来自哪个表格，因此可能会出现模糊字段。

首先在_game加入_user，然后在_user上与_headsup进行第二次加入

FROM _game
LEFT JOIN _user ON _game.someField = _user.someField
JOIN _headsup ON _user.id = _headsup.player1

简单的MySQL加入

4 个答案: