Question

经过广泛的研究，我得出结论我的案例是独一无二的，我需要问。我的PHP知识非常有限，我试图仅仅根据Google的结果来完成这项工作。

目标：创建一个显示包含5列HTML表的网页（端口，L1状态，L2状态，帧错误，活动呼叫）每个列的日期存储在一个数据库表中，这就是技巧，这些数据的大部分来自同一领域...这意味着我需要创建5个不同的查询。我试图创建一个单一的查询（我相信如果可以的话，我会这样做），但我无法做到。

到目前为止的结果：仅包含第5个查询结果的表格以及表格的其余部分仅重复填充第1个查询。

这是我的代码：

<!-- Simple HTML to Create the table layout -->
<table border=1 style="background-color:#F0F8FF;" >
<caption><EM>HEADER</EM></caption>
<tr>
<th>Port</th>
<th>L1 Status</th>
<th>L2 Status</th>
<th>Framing Errors</th>
<th>Active calls</th>
</tr>
<!-- END Simple HTML to Create the table layout -->
<?php
$server = "localhost";
$dbname = "database";
$user = "user";
$password = "password";
$con = mysql_connect($server,$user,$password) or die (mysql_error());
mysql_select_db($dbname) or die (mysql_error());

$query1="select right(name, 10) as 'Port' from items where hostid = (select hostid from hosts where name = 'MIAGATE01') and key_ like '%activeChannels[%' and key_ not like '%SNMPINDEX%' order by name";
$query2="select lastvalue as 'Layer1' from items where hostid = (select hostid from hosts where name = 'MIAGATE01') and key_ like '%statusLayer1[%' and key_ not like '%SNMPINDEX%' order by name";
$query3="select lastvalue as 'Layer2' from items where hostid = (select hostid from hosts where name = 'MIAGATE01') and key_ like '%statusLayer1[%' and key_ not like '%SNMPINDEX%' order by name";
$query4="select lastvalue as 'Framing_Errors'from items where hostid = (select hostid from hosts where name = 'MIAGATE01') and key_ like '%frameErrors[%' and key_ not like '%SNMPINDEX%' order by name";
$query5="select lastvalue as 'Active_Calls' from items where hostid = (select hostid from hosts where name = 'MIAGATE01') and key_ like '%activeChannels[%' and key_ not like '%SNMPINDEX%' order by name";
$result1=mysql_query($query1) or die(mysql_error());
$result2=mysql_query($query2) or die(mysql_error());
$result3=mysql_query($query3) or die(mysql_error());
$result4=mysql_query($query4) or die(mysql_error());
$result5=mysql_query($query5) or die(mysql_error());

while($row1 = mysql_fetch_array($result1)){
while($row2 = mysql_fetch_array($result2)){
while($row3 = mysql_fetch_array($result3)){
while($row4 = mysql_fetch_array($result4)){
while($row5 = mysql_fetch_array($result5)){
echo "<tr>";
echo "<td>" . $row1['Port'] . "</td>";
echo "<td>" . $row2['Layer1'] . "</td>";
echo "<td>" . $row3['Layer2'] . "</td>";
echo "<td>" . $row4['Framing_Errors'] . "</td>";
echo "<td>" . $row5['Active_Calls'] . "</td>";
echo "</tr>";
}
}
}
}
}
mysql_close($con);
?>

Answer 1

首先尝试此查询，看看它是否立即获得了所有必需的结果。

SELECT h.hostid, 
  RIGHT(port.name,10) AS 'Port', 
  l1.lastvalue AS 'Layer1', 
  l2.lastvalue AS 'Layer2', 
  fe.lastvalue AS 'Framing_Errors', 
  ac.lastvalue AS 'Active_Calls' 
FROM hosts h 
INNER JOIN items port 
  ON port.hostid = h.hostid 
    AND port.key_ LIKE '%activeChannels[%' 
    AND port.key_ not LIKE '%SNMPINDEX%' 
INNER JOIN items l1 
  ON l1.hostid = h.hostid 
    AND l1.key_ LIKE '%statusLayer1[%' 
    AND l1.key_ not LIKE '%SNMPINDEX%'
INNER JOIN items l2 
  ON l2.hostid = h.hostid 
    AND l2.key_ LIKE '%statusLayer2[%' 
    AND l2.key_ not LIKE '%SNMPINDEX%'
INNER JOIN items fe 
  ON fe.hostid = h.hostid 
    AND fe.key_ LIKE '%frameErrors[%' 
    AND fe.key_ not LIKE '%SNMPINDEX%'
INNER JOIN items ac 
  ON ac.hostid = h.hostid 
    AND ac.key_ LIKE '%activeChannels[%' 
    AND ac.key_ not LIKE '%SNMPINDEX%'
WHERE h.name = 'MIAGATE01'
ORDER BY h.name;

如果这样做，您只需要一个while循环来填充表格。

while ( $row = mysql_fetch_array($result)) {
  echo "<tr>";
  echo "<td>" . $row['Port'] . "</td>";
  echo "<td>" . $row['Layer1'] . "</td>";
  echo "<td>" . $row['Layer2'] . "</td>";
  echo "<td>" . $row['Framing_Errors'] . "</td>";
  echo "<td>" . $row['Active_Calls'] . "</td>";
  echo "</tr>";
}

Answer 2

首先：

您的预期HTML表格的每个ROW都包含所有五个数据项吗？问另一种方式，每个端口有一行吗？你的问题并不明显。从您的逻辑中可以确定不同参数的出现次数不同。

无论如何......你需要将一堆包含hostid的参数连接在一起，将你的显示放在一起。我想是这样的。（您的数据非常复杂）。

select hostid.hostid, port.Port, layer1.Layer1, layer2.Layer2
  from
            (select hostid, name
             from hosts
            where name = 'MIAGATE01'
            ) hostid
  left join
            (select hostid, right(name,10) as 'Port'
               from items
              where key_ like '%activeChannels[%' and key_ not like '%SNMPINDEX%'  
            ) port 
        on hostid.hostid = port.hostid
  left join
           (select hostid, lastvalue as 'Layer1'
              from items
             where key_ like '%statusLayer1[%' and key_ not like '%SNMPINDEX%'  
           ) layer1 
        on hostid.hostid = layer1.hostid
  left join
           (select hostid, lastvalue as 'Layer2'
              from items
             where key_ like '%statusLayer2[%' and key_ not like '%SNMPINDEX%'  
           ) layer2 
        on hostid.hostid = layer2.hostid
order by hostid.name, port.Port

看看怎么样？您有很多小选项可以生成值列表值与您的key_选择条件匹配的hostid值项目列表。然后，您将所有这些加入到他们的hostid值中。第一个小选择只是为你想要的特定主机提供了正确的hostid。

我没有完成你的所有参数，但是你不应该很难完成这个查询。至于它的调试......如果没有看到你的items表，那很难知道。这可能是一个很大的毛球。但你已经知道了。

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2 个答案: