这是我的shell脚本:
# Deletes data from the 'sample' table starting August 30, 2011.
# This is done in stages with a 7 second break every
# 2 seconds or so to free up the database for other users.
# The message "Done." will be printed when there are
# no database entries left to delete.
user="*****"
pass="*****"
while(true); do
starttime=`date +%s`
while [[ $((`date +%s` - $starttime)) -lt 2 ]]; do
sqlplus $user/$pass@//blabla <<EOF
whenever sqlerror exit 1
delete from
sample
where
sampletime >= to_date('08-30-2011','mm-dd-yyyy') and
rownum <= 2;
commit;
EOF
rows = ???
if [ $rows -eq 0 ] ; then
echo "Done."
exit 0;
fi
done
sleep 7
done
如果没有办法获得行数,也许我可以使用sqlplus返回的错误代码来确定何时结束脚本?有什么想法吗?
谢谢!
答案 0 :(得分:1)
我使用sql%rowcount
告诉你最后一个DML语句影响了多少行。
delete from
sample
where
sampletime >= to_date('08-30-2011','mm-dd-yyyy') and
rownum <= 2;
if sql%rowcount = 0 then
dbms_output.put_line('Free');
end if;
commit;
答案 1 :(得分:0)
请使用以下内容 注意:没有经过测试
user="*****"
pass="*****"
while(true);
do
starttime=`date +%s`
while [[ $((`date +%s` - $starttime)) -lt 2 ]];
do
rows=`sqlplus -silent $user/$pass@//blabla << EOF
whenever sqlerror exit 1
SET PAGESIZE 0 FEEDBACK OFF VERIFY OFF HEADING OFF ECHO OFF
select count(1) from
sample
where
sampletime >= to_date('08-30-2011','mm-dd-yyyy') and
rownum <= 2;
EOF`
if [ $rows -neq 0] ;
then
sqlplus $user/$pass@//blabla << EOF1
delete from
sample
where
sampletime >= to_date('08-30-2011','mm-dd-yyyy') and
rownum <= 2;
commit;
EOF1
else
echo "Done."
exit 0;
fi
done
sleep 7
done
答案 2 :(得分:0)
请试试这个:
rows=`sqlplus -s ${DB_USER}/${DB_PASSWD}@${DB_SID} <<EOF
delete from sample where sampletime >= to_date('08-30-2011','mm-dd-yyyy') and rownum <= 2;
commit;
exit;
EOF` 网络
echo rows = $rows