{
[2012-05-23] => 1
[2012-05-24] => 1
[2012-05-25] => 1
[2012-05-26] => 1
[2012-05-27] => 1
[2012-05-28] => 11
[2012-05-29] => 11
[2012-05-30] => 12
}
例如这是我的数组,我只想获得数值大于10的数组的索引
所以在这种情况下答案必须听起来像那样
{
[0] => 2012-05-28
[1] => 2012-05-29
[2] => 2012-05-30
}
答案 0 :(得分:2)
$new_array = array();
foreach ($array as $r => $a)
{
if ($a>10)
$new_array[] = $r;
}
答案 1 :(得分:0)
$array=//Your array in original post.
$newarray=array();
foreach ($array as $key=>$val) {
if ($key>10) {
$newarray[]=$key;
}
}
答案 2 :(得分:0)
如果$array
是您的第一个阵列:
$new_array = array();
foreach($array as $key => $value) {
if( $value > 10 ) {
$new_array[] = $key;
}
}
答案 3 :(得分:0)
试试这个(假设<pre>
中的数组被称为$dates
):
$result = array();
foreach($dates as $date => $value) {
if($value > 10) $result[] = $date;
}
print_r($result);
答案 4 :(得分:0)
$testData = array ('2012-05-23' => 1,
'2012-05-24' => 1,
'2012-05-25' => 1,
'2012-05-26' => 1,
'2012-05-27' => 1,
'2012-05-28' => 11,
'2012-05-29' => 11,
'2012-05-30' => 12,
);
$testNeedle = 10;
$result = array_filter($testData,
function($arrayEntry) use ($testNeedle) {
return $arrayEntry > $testNeedle;
}
);
$result = array_keys($result);
var_dump($result);
答案 5 :(得分:0)
此代码可以完成这项工作。
$array1 = array(
'2012-05-23' => 1,
'2012-05-24' => 1,
'2012-05-25' => 1,
'2012-05-26' => 1,
'2012-05-27' => 1,
'2012-05-28' => 11,
'2012-05-29' => 11,
'2012-05-30' => 12
);
$result = (array_keys(array_filter($array1, "select")));
function select($var)
{ return($var > 10); }
您还可以在空数组中使用带有array_push的for循环来跳过回调函数。