如果尝试使用相同的键名,则更新json值

时间:2012-05-31 09:16:18

标签: javascript jquery

如果尝试添加具有相同名称的新密钥,我正在尝试编写一个更新json密钥值的函数

所以小提琴 - http://jsfiddle.net/adrianjsfiddlenetuser/C6Ssa/57/

单击“添加”按钮时,应更新jSon数组toUpdate:

   name: "addThis2",
   id : 10   

应该成为

   name: "addThis2",
   id : 11  

这不是吗?

示例JSON:

{
    "toAdd": [
        {
            "name": "addThis",
            "id": 10
        }
    ],
    "toRemove": [
        {
            "name": "removeThis"
        }
    ]
}

2 个答案:

答案 0 :(得分:1)

function updateKeyVal() {
    $.each(toUpdate, function(i,e) {
        $.each(e, function(j, f) {
            if (f.name===valToCheck) f.id=11;
        });
    });
}​

FIDDLE

答案 1 :(得分:0)

您应该更改数组的索引,如下所示:

var toUpdate = {
    toAdd: [],
    toRemove: []
};
toUpdate.toAdd[0].push({
    name: "addThis1",
    id: 10
});
toUpdate.toRemove[0].push({
    name: "removeThis1"
});
toUpdate.toAdd[1].push({
    name: "addThis2",
    id: 10
});
toUpdate.toRemove[1].push({
    name: "removeThis2"
});

然后你可以尝试

$.each(toUpdate, function(index, data) {
   $.each(data, function(key, val) {  // here this refer to toAdd, toRemove..
    console.log(key);   // here this point key of object like name, id ...
    console.log(val[key]);  // output: addThis, addThis, removeThis
  });
});