Question

我完全是html，css，javascript和编程的总菜鸟。请耐心等待。

我试图用jquery填充我的表。数据将来自xml文件。

football_player.xml

<?xml version="1.0" encoding="UTF-8"?>

<football_player>
  <name>Cristiano Ronaldo</name>
  <club>Real Madrid</club>
  <number>7</number>
  <country>Portugal </country>

  <name>Fernando Torres </name>
  <club>Chelsea </club>
  <number>9</number>
  <country>Spain</country>

  <name>Iker Casillas</name>
  <club>Real Madrid </club>
  <number>1</number>
  <country>Spain</country>

  <name>David Beckham</name>
  <club>Los Angeles Galaxy</club>
  <number>23</number>
  <country>England</country>
</football_player>

我的html表：

<table>
  <thead>
    <tr>
      <th>Name</th>
      <th>Club</th>
      <th>Number</th>
      <th>Country</th>
    </tr>
  </thead>
  <tbody>
  </tbody>
  </tfoot>
  </tfoot>
</table>

我的javascript / jquery脚本：

$(document).ready(function () {
  $.ajax({
    type: "GET",
    url: "football_player.xml",
    dataType: "xml",
    success: function(xml) {
      $(xml).find("football_player").each(function () {
        $("table tbody").append("<tr>");
        $("table tbody").append("<td>" + $(this).find("name").text() + "</td>");
        $("table tbody").append("<td>" + $(this).find("club").text() + "</td>");
        $("table tbody").append("<td>" + $(this).find("number").text() + "</td>");
        $("table tbody").append("<td>" + $(this).find("country").text() + "</td>");
        $("table tbody").append("</tr>");           
      });
    }
  });
});

我发誓我真的是个菜鸟。我不知道我在做什么。请帮忙。我真的很想学。提前谢谢。

Answer 1

示例XML：

<?xml version="1.0" encoding="utf-8" ?>
    <RecentBooks>
     <Book>
      <Title>My Cool Book Title</Title>
    <Description>The my cool book is possibly the best cool book in that any developer could use to     be a great web designer.</Description>
    <Date>12/1/2010</Date>
    </Book>
    <Book>
     <Title>Another PHP book</Title>
    <Description>Learn everything about PHP with 'Another PHP book,' your ultimate guide to the ins and outs of PHP.</Description>
    <Date>4/1/2010</Date>
    </Book>
    <Book>
    <Title>jQuery Techniques</Title>
    <Description>jQuery techniques runs you through real life examples of jQuery from beginner to expert</Description>
     <Date>6/2/2010</Date>
     </Book>
     <Book>
    <Title>MySQL Database Book</Title>
    <Description>Brush up your knowledge with the best MySQL database book on the market.          </Description>
    <Date>14/2/2010</Date>
    </Book>
    </RecentBooks>

HTML＆amp; jquery的。

$(document).ready(function () {
$.ajax({
    type: "GET",
    url: "books.xml",
    dataType: "xml",
    success: xmlParser
   });
});

function xmlParser(xml) {

$('#load').fadeOut();

$(xml).find("Book").each(function () {

    $(".main").append('<div class="book"><div class="title">' + $(this).find("Title").text() +   '</div><div class="description">' + $(this).find("Description").text() + '</div><div   class="date">Published ' + $(this).find("Date").text() + '</div></div>');
    $(".book").fadeIn(1000);

 });

}

<div class="main">
<div align="center" class="loader"><img src="loader.gif" id="load" width="16" height="11"   align="absmiddle"/></div>
</div>

 <div class="clear"></div>

你可以通过这个例子来了解相同的

Answer 2

我遇到了类似的问题，我使用HTTP GET获取XML数据然后进行解析。举个例子：

$.ajax({
    type: "GET",
    url: "football_player.xml",
    ->dataType: "text",
    success: function(xml) {
        var parser = new DOMParser();
        var xmlDoc = parser.parseFromString(xml, "text/xml");
        var json = ->getJson(xmlDoc);
        for(var i =0; i< json[0].football_player.length;i++) {
            var player = json[0].football_player[i];
            $("table tbody").append("<tr>");
            $("table tbody").append("<td>" + ->player.name + "</td>");
            $("table tbody").append("<td>" + ->player.club + "</td>");
            $("table tbody").append("<td>" + ->player.number + "</td>");
            $("table tbody").append("<td>" + ->player.country + "</td>");
            $("table tbody").append("</tr>");
        }
    }
});

需要注意的三件事（ - ＆gt;）：

dataType: "text"我创建了http请求，数据类型为TEXT而不是XML，因此我将xml数据作为字符串数据类型。
getJson(xmlDoc)方法：我写了一个小函数来将XML转换为Javascript对象（JSON）。还有其他小型实用程序可以做同样的事情。
player.name：由于此转换，您可以将XML内容用作javascript对象，从而更易于解析和阅读。

我在下面粘贴getJson()功能（未经过测试，我为POC做了，但为我工作）：

function getJson(xmlDoc) {
    var result = [];

    for (var i = 0; i < xmlDoc.children.length; i++) {
        var child = xmlDoc.children[i];
        if (result[child.tagName] === undefined) {
            result[child.tagName] = [];
        }

        var nodeJson = getJsonFromNode(xmlDoc.children[i]);
        result[child.tagName].push(nodeJson);
    }

    return result;
}

function getJsonFromNode(node) {
    var nodeJson = {};
    // for attributes
    for (var i = 0; i < node.attributes.length; i++) {
        var att = node.attributes[i];
        nodeJson[att.localName] = att.value;
    }

    // for child nodes
    for (var i = 0; i < node.children.length; i++) {
        var child = node.children[i];
        if (nodeJson[child.tagName] === undefined) {
            nodeJson[child.tagName] = [];
        }
        var result = getJsonFromNode(node.children[i]);
        nodeJson[child.tagName].push(result);
    }

    return nodeJson;
}

jquery - 如何获取xml数据

2 个答案: