Question

我有一个使用地址簿的应用。我正在尝试使用

显示地址簿中的已排序名称列表

sortedArray = [arr_contactList sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];

然后当用户选择其中一个联系人时，会显示其电话号码。

我可以对iPhone地址簿电话号码进行排序。

我使用以下方法对电话号码进行排序：

ABRecordRef source = ABAddressBookCopyDefaultSource(ab);
NSArray *thePeople = (NSArray*)ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering(ab, source, kABPersonSortByFirstName);

NSString *name;
for (id person in thePeople)
{
    name = (NSString *)ABRecordCopyValue(person, kABPersonFirstNameProperty);

    ABMultiValueRef phones = ABRecordCopyValue(person, kABPersonPhoneProperty);

    for(CFIndex j = 0; j < ABMultiValueGetCount(phones); j++)
    {  
        NSString* num = (NSString*)ABMultiValueCopyValueAtIndex(phones, j);

        CFStringRef locLabel1 = ABMultiValueCopyLabelAtIndex(phones, j);

        NSString *phoneLabel1 =(NSString*) ABAddressBookCopyLocalizedLabel(locLabel1);

        [tempPhoneArray addObject:num];        
    }       
}

但我的实际问题是，我的名字数组的联系人以列表顶部的特殊字符开头，当我选择电话号码时，联系人列表以字母A开头。所以我的电话号码错了。< / p>

如何匹配这两种排序 - 名称排序和数字排序？

Answer 1

在这个例子中，你将制作27个数组，每个字母1个，但这个概念可以应用于特殊字符vs大/小写的任何检查。希望这会有所帮助。

const int capacity = 27;    
NSMutableArray *subArrays = [NSMutableArray array];

//Prepopulate the subArray with 26 empty arrays
for(int i = 0; i < capacity; i++)
    [subArrays addObject:[NSMutableArray array]];
char currFirstLetter = 'a';

for(int i = 0; i < sortedArray.count; i++)
{
    NSString *currString = [[sortedArray objectAtIndex:i] lowercaseString];

    NSLog(@"%@", currString);
    NSLog(@"%c", [currString characterAtIndex:0]);
    NSLog(@"%c", currFirstLetter);

    if([currString characterAtIndex:0] == currFirstLetter)
    {
        //65 is the position of 'a' in the ascii table, so when we subtract 97, it correlates to 0 in our array.
        [[subArrays objectAtIndex:currFirstLetter-97] addObject:[sortedArray objectAtIndex:i]];
    }
    else if([currString characterAtIndex:0] < 65 || ([currString characterAtIndex:0] > 90 && [currString characterAtIndex:0] < 97) || [currString characterAtIndex:0] > 122)
    {
        //If it's a symbol (65-90 are uppercase, 97-122 are lowercase)
        [[subArrays objectAtIndex:26] addObject:[sortedArray objectAtIndex:i]];
        //Increment the letter we're looking for, but decrement the count to try it again with the next letter
    }
    else
    {
        currFirstLetter++;
        i--;
    }
}

从iPhone地址簿中排序联系人

1 个答案: