Question

我正在检索JSON数据数组并试图显示并访问它。但是当我试图显示它时，它只显示JSON数据数组中的最后一行。当我尝试执行类似json1.get的操作时（ 2）（这里的json1是包含JSONObject的JSONArray）我得到数组超出绑定的错误。请告诉我我做错了什么以及如何重新检索JSON 以下是此问题的相关代码。

谢谢。

从Freebies.java类调用UserFunctions.java类的getAllFreebies函数

UserFunctions uf = new UserFunctions();
JSONObject json = uf.getAllFreebies();

以下是UserFunctions.java类中我的getAllFreebies（）函数的代码：

public JSONObject getAllFreebies(){
    List<NameValuePair> params = new ArrayList<NameValuePair>();
    params.add(new BasicNameValuePair("tag", getAllFreebies_tag));
    JSONObject json  = jsonParser.getJSONFromUrl(getAllFreebiesURL,params);
    JSONArray json1 = new JSONArray();
    json1.put(json);
    try {
        System.out.println(json1.get(2));
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return json;
}

下面是index.php类中的代码，其中我调用了DB_Functions.php类的getFreebies（）函数

else if($tag = 'getAllFreebies'){
                $username = "";
                $catagory = "";
                $subcatagory = "";
                $title = "";
                $condition = "";
                $description = "";
                $address = "";
                $city = "";
                $state = "";
                $country = "";
                $zipcode = "";
                $posted_on= "";
                    $getAllFreebies = $db->getFreebies($username,$catagory,$subcatagory,$title,$condition,$description,$address,$city,$state,$country,$zipcode,$posted_on);
            $data = array();
            while($row = mysql_fetch_assoc($getAllFreebies)) {
            $response["success"] = 1;
            $data[] = array(
            $response["getAllFreebies"]["username"] = $row["username"],
            $response["getAllFreebies"]["catagory"] = $row["catagory"],
            $response["getAllFreebies"]["subcatagory"] = $row["subcatagory"],
            $response["getAllFreebies"]["title"] = $row["title"],
            $response["getAllFreebies"]["item_condition"] = $row["item_condition"],
            $response["getAllFreebies"]["description"] = $row["description"],
            $response["getAllFreebies"]["address"] = $row["address"],
            $response["getAllFreebies"]["city"] =  $row["city"],
            $response["getAllFreebies"]["state"] = $row["state"],
            $response["getAllFreebies"]["country"] = $row["country"],
            $response["getAllFreebies"]["zipcode"] = $row["zipcode"],
            $response["getAllFreebies"]["posted_on"] = $row["posted_on"]);}
            echo json_encode($response);
                    }// end of getAllFreebies tag

以下是DB_Functions.php

的getFreebies（）函数的代码

public function getFreebies(){
$result = mysql_query("SELECT * FROM freebie") or die(mysql_error());
return($result);
}

更新：我在JSONParser类中添加了以下内容以解析JSONArray public JSONArray getJSONArrayFromUrl（String url，List params）{

    // Making HTTP request
    try {
        // defaultHttpClient
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost(url);
        httpPost.setEntity(new UrlEncodedFormEntity(params));
        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "n");
        }
        is.close();
        json = sb.toString();

        Log.e("JSON", json);
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
        jarray.put(jObj);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jarray;

}

我改变了getAllFreebie（）来检索JSONArray

public JSONArray getAllFreebies() {
    List<NameValuePair> params = new ArrayList<NameValuePair>();
    params.add(new BasicNameValuePair("tag", getAllFreebies_tag));
    JSONArray json = jsonParser.getJSONArrayFromUrl(getAllFreebiesURL,
            params);
    return json;
}

仍然我只获得单行而不是所有行。任何人都可以告诉我我做错了什么。谢谢：（

Answer 1

检查以下代码：

JSONObject json  = jsonParser.getJSONFromUrl(getAllFreebiesURL,params);
JSONArray json1 = new JSONArray();
json1.put(json);
try {
    System.out.println(json1.get(2));
} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

您创建一个新的空 JSONArray，向其中添加一个元素，然后尝试访问其第二个元素。

getJSONFromUrl是应该解析对象还是数组？我相信你需要它来代替JSONArray。

Answer 2

~~将您的代码更新为：~~

// Initialize the array with your JSON string.
JSONArray json1 = new JSONArray(json);

// This line adds your String as the first element to
// the JSON array and is incorrect. You can safely remove it.
//json1.put(json);

编辑：试试您发布的代码的更新版本：

// Making HTTP request
try {
    // defaultHttpClient
    DefaultHttpClient httpClient = new DefaultHttpClient();
    HttpPost httpPost = new HttpPost(url);
    httpPost.setEntity(new UrlEncodedFormEntity(params));
    HttpResponse httpResponse = httpClient.execute(httpPost);

    try {
        // Get our response as a String.
        String jsonString = EntityUtils.toString(httpResponse.getEntity());
        Log.d(TAG, "JSON: "+jsonString);

        // Parse the JSON String into a JSONArray object.
        return new JSONArray(jsonString);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }
} catch (UnsupportedEncodingException e) {
    e.printStackTrace();
} catch (ClientProtocolException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}
return null;

检索JSON数组并将其放入java中的数组？

2 个答案: