Question

我有两个HTML输入框，需要计算JavaScript onBlur的时差（因为我需要实时）并将结果插入新的输入框。

格式示例：10：00＆amp; 12:30需要给我：02：30

谢谢！

Answer 1

以下是一种可能的解决方案：

function diff(start, end) {
    start = start.split(":");
    end = end.split(":");
    var startDate = new Date(0, 0, 0, start[0], start[1], 0);
    var endDate = new Date(0, 0, 0, end[0], end[1], 0);
    var diff = endDate.getTime() - startDate.getTime();
    var hours = Math.floor(diff / 1000 / 60 / 60);
    diff -= hours * 1000 * 60 * 60;
    var minutes = Math.floor(diff / 1000 / 60);

    // If using time pickers with 24 hours format, add the below line get exact hours
    if (hours < 0)
       hours = hours + 24;

    return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes;
}

DEMO： http://jsfiddle.net/KQQqp/

Answer 2

这项工作几乎很棒。现在使用这个代码来计算：23：50 - 00:10然后看看你得到了什么。甚至23:30 - 01:30。那是一团糟。因为在PHP中以另一种方式获得答案是：

$date1 = strtotime($_POST['started']);
$date2 = strtotime($_POST['ended']);
$interval = $date2 - $date1;
$playedtime = $interval / 60;

但是，它仍然像你的一样。我想还要带上日期吗？

再一次：我的艰苦研究和发展帮助了我。

if (isset($_POST['calculate'])) {
$d1 = $_POST['started'];
$d2 = $_POST['ended'];
if ($d2 < $d1) {
    $date22 = date('Y-m-');
    $date222 = date('d')-1;
    $date2 = $date22."".$date222;
} else {
$date2 = date('Y-m-d');
}
$date1 = date('Y-m-d');
$start_time = strtotime($date2.' '.$d1);
$end_time = strtotime($date1.' '.$d2); // or use date('Y-m-d H:i:s') for current time
$playedtime = round(abs($start_time - $end_time) / 60,2);
}

这就是你计算第二天的时间的方法。 //编辑。首先我改变了date1和date2。我需要-1，因为这个计算仅在第二天出现，并且是昨天的第一个日期。

经过与朋友的改善和大量的脑力，我们得出了这个：

$begin=mktime(substr($_GET["start"], 0,2),substr($_GET["start"], 2,2),0,1,2,2003);
$end=mktime(substr($_GET["end"], 0,2),substr($_GET["end"], 2,2),0,1,3,2003);
$outcome=($end-$begin)-date("Z");
$minutes=date("i",$outcome)+date("H",$outcome)*60; //Echo minutes only
$hours = date("H:i", $outcome); //Echo time in hours + minutes like 01:10 or something.

因此，您实际上只需要4行代码即可获得结果。您可以只花几分钟或显示全职（如差异是02:32）2小时32分钟。最重要的是：你仍然可以在24小时计时过夜计算：开始时间11:50 PM，比如01:00 AM（24小时时间23:50 - 01:00），因为在12小时模式下，无论如何都可以。 / p>

最重要的是：您无需格式化输入。您可以使用普通2300作为23:00输入。此脚本将自己将文本字段输入转换为正确的格式。最后一个脚本使用带有method =“get”的标准html表单，但您也可以将其转换为使用POST方法。

Answer 3

你提供的秒数没有得到结果给我，请找到我的更新功能，在这里给你正确的秒数 - 作者：Dinesh J

function diff(start, end) {
    start = start.split(":");
    end = end.split(":");
    var startDate = new Date(0, 0, 0, start[0], start[1],start[2], 0);
    var endDate = new Date(0, 0, 0, end[0], end[1],end[2], 0);
    var diff = endDate.getTime() - startDate.getTime();
    var hours = Math.floor(diff / 1000 / 60 / 60);
    diff -= hours * 1000 * 60 * 60;
    var minutes = Math.floor(diff / 1000 / 60);
    var seconds = Math.floor(diff / 1000)-120;

    // If using time pickers with 24 hours format, add the below line get exact hours
    if (hours < 0)
        hours = hours + 24;

    return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes+ ":" + (seconds <= 9 ? "0" : "") + seconds;
}

Answer 4

试试这个

var dif = ( new Date("1970-1-1 " + end-time) - new Date("1970-1-1 " + start-time) ) / 1000 / 60 / 60;

Answer 5

这是已提交的版本的更新版本。这是秒。

function diff(start, end) {
    start = start.split(":");
    end = end.split(":");
    var startDate = new Date(0, 0, 0, start[0], start[1], 0);
    var endDate = new Date(0, 0, 0, end[0], end[1], 0);
    var diff = endDate.getTime() - startDate.getTime();
    var hours = Math.floor(diff / 1000 / 60 / 60);
    diff -= hours * (1000 * 60 * 60);
    var minutes = Math.floor(diff / 1000 / 60);
    diff -= minutes * (1000 * 60);
    var seconds = Math.floor(diff / 1000);

    // If using time pickers with 24 hours format, add the below line get exact hours
    if (hours < 0)
       hours = hours + 24;

    return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes + (seconds<= 9 ? "0" : "") + seconds;
}

我的更新版本：

允许您将日期转换为毫秒，而不是拆分。

示例 - 年/月/周/天/小时/分/秒

示例：https://jsfiddle.net/jff7ncyk/308/

Answer 6

根据您允许输入的内容，此功能可以使用。如果你想允许凌晨1点到1点，可能会出现一些边界问题

注意：这不是使用日期对象或moment.js

＆＃13;

function pad(num) {
  return ("0"+num).slice(-2);
}
function diffTime(start,end) {
  var s = start.split(":"), sMin = +s[1] + s[0]*60,
      e =   end.split(":"), eMin = +e[1] + e[0]*60,
   diff = eMin-sMin;
  if (diff<0) { sMin-=12*60;  diff = eMin-sMin }
  var h = Math.floor(diff / 60),
      m = diff % 60;
  return "" + pad(h) + ":" + pad(m);
}  
document.getElementById('button').onclick=function() {
  document.getElementById('delay').value=diffTime(
      document.getElementById('timeOfCall').value, 
      document.getElementById('timeOfResponse').value
  );
}

＆＃13;

<input type="time" id="timeOfCall">
<input type="time" id="timeOfResponse">
<button type="button" id="button">CLICK</button>
<input type="time" id="delay">

＆＃13;

Answer 7

   calTimeDifference(){
    this.start = dailyattendance.InTime.split(":");
    this.end = dailyattendance.OutTime.split(":");
    var time1 = ((parseInt(this.start[0]) * 60) + parseInt(this.start[1]))
    var time2 = ((parseInt(this.end[0]) * 60) + parseInt(this.end[1]));
    var time3 = ((time2 - time1) / 60);
    var timeHr = parseInt(""+time3);
    var  timeMin = ((time2 - time1) % 60);
}

Answer 8

TimeCount = function()
{
    t++;
    var ms = t;
    if (ms == 99)
    {
        s++;
        t = 0;
        if ( s == 60)
        {
            m++;
            s = 0;
        }
    }

    Dis_ms = checkTime(ms);
    Dis_s = checkTime(s);
    Dis_m = checkTime(m);
    
    document.getElementById("time_val").innerHTML = Dis_m + ":" + Dis_s+ ":" + Dis_ms;
}

function checkTime(i) 
{
  if (i<10) {
    i = "0" + i;
  }
  return i;
}

Answer 9

此解决方案适用于计算不同军事时间之间的时差

示例格式：开始= 23:00 /结束= 02:30

function diff(start, end) {
start = start.split(":");
end = end.split(":");
if(Number(start[0]) > Number(end[0]) ) {
  var num = Number(start[0])
  var countTo = Number(end[0]);
  var count = 0;
  for (var i = 1; num != countTo;) {
    num = num + i
    if(num > 24) {
      num = 0
    }
    count++
  }
  var hours = count - 1;
  var startDate = new Date(0, 0, 0, start[0], start[1], 0);
  var endDate = new Date(0, 0, 0, end[0], end[1], 0);
  if(startDate.getMinutes() > endDate.getMinutes()) {
    var hours = count - 2;
    var diff = 60 - (startDate.getMinutes() - endDate.getMinutes());      
  } else {
    var diff = endDate.getMinutes() - startDate.getMinutes();      
  }
  var minutes = diff
} else {
  var startDate = new Date(0, 0, 0, start[0], start[1], 0);
  var endDate = new Date(0, 0, 0, end[0], end[1], 0);
  var diff = endDate.getTime() - startDate.getTime();
  var hours = Math.floor(diff / 1000 / 60 / 60);
  diff -= hours * 1000 * 60 * 60;
  var minutes = Math.floor(diff / 1000 / 60);
}

var returnValue = (hours < 9 ? "0" : "") + hours + ":" + (minutes < 9 ? "0" : "") + minutes

return returnValue;

}

Answer 10

试试这个：实际上这是来自codeeval.com的问题

我以这种方式解决了它。

这个程序以文件为参数，所以我使用了一个小节点js来读取文件。

这是我的代码。

var fs  = require("fs");
fs.readFileSync(process.argv[2]).toString().split('\n').forEach(function (line) {
    if (line !== "") {
        var arr = line.split(" ");
        var arr1 = arr[0].split(":");
        var arr2 = arr[1].split(":");
        var time1 = parseInt(arr1[0])*3600 + parseInt(arr1[1])*60 + parseInt(arr1[2]);
        var time2 = parseInt(arr2[0])*3600 + parseInt(arr2[1])*60 + parseInt(arr2[2]);
        var dif = Math.max(time1,time2) - Math.min(time1,time2);
        var ans = [];
        ans[0] = Math.floor(dif/3600);
        if(ans[0]<10){ans[0] = "0"+ans[0]}
        dif = dif%3600;
        ans[1] = Math.floor(dif/60);
        if(ans[1]<10){ans[1] = "0"+ans[1]}
        ans[2] = dif%60;
        if(ans[2]<10){ans[2] = "0"+ans[2]}
        console.log(ans.join(":"));
    }
});

Answer 11

我们通常需要时间差来估计I / O操作，SP调用等所花费的时间，NodeJ的最简单的解决方案（控制台在回调 - 异步执行中）如下：

var startTime = new Date().getTime();
//This will give you current time in milliseconds since 1970-01-01

callYourExpectedFunction(param1, param2, function(err, result){
    var endTime = new Date().getTime();
    //This will give you current time in milliseconds since 1970-01-01

    console.log(endTime  - startTime)
    //This will give you time taken in milliseconds by your function

   if(err){
   }
   else{
   }
})

使用JavaScript计算时差

11 个答案: