我有一个代码,它改变了UIImage中的像素。我需要将触摸位置的像素设置为透明,之后再触摸那里时非透明。我该怎么办?
代码
//It create new image with changed pixels
- (UIImage*)fromImage:(UIImage*)source
colorBuffer:(NSArray *)colors erase:(BOOL)eraser
{
CGContextRef ctx;
CGImageRef imageRef = [source CGImage];
NSUInteger width = CGImageGetWidth(imageRef);
NSUInteger height = CGImageGetHeight(imageRef);
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
byte *rawData = malloc(height * width * 4);
NSUInteger bytesPerPixel = 4;
NSUInteger bytesPerRow = bytesPerPixel * width;
NSUInteger bitsPerComponent = 8;
CGContextRef context = CGBitmapContextCreate(rawData, width, height,
bitsPerComponent, bytesPerRow, colorSpace,
kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big);
CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef);
CGContextRelease(context);
int byteIndex = 0;
for (int ii = 0 ; ii < width * height ; ++ii)
{
if(eraser)
{
// SET PIXEL TRANSPARENT
}
else
{
//SET PIXEL NON-TRANSPARENT
}
}
ctx = CGBitmapContextCreate(rawData,
CGImageGetWidth( imageRef ),
CGImageGetHeight( imageRef ),
8,
bytesPerRow,
colorSpace,
kCGImageAlphaPremultipliedLast );
CGColorSpaceRelease(colorSpace);
imageRef = CGBitmapContextCreateImage (ctx);
UIImage* rawImage = [UIImage imageWithCGImage:imageRef];
CGImageRelease(imageRef);
CGContextRelease(ctx);
free(rawData);
return rawImage;
}