我有一个包含很多符号的图层,我想隐藏并显示整个图层的所有元素。
隐藏我使用myLayer.remove();
执行此操作,但要显示它没有方法...
在他们的教程中,他们说project.activeLayer.addChild(myObject);
但它似乎不适用于图层。 (http://paperjs.org/tutorials/project-items/project-hierarchy/)
如果有人可以帮助我,或者告诉我是否需要采取不同的方式?
非常感谢。
答案 0 :(得分:8)
调用Layer.remove()时,将从project.layers数组中删除该Layer实例。要重新显示已删除的图层(以及其中的任何对象),请将其推回到project.layers。
var blueSquare = Path.Rectangle(new Point(0, 0), new Size (50, 50));
blueSquare.fillColor = 'blue';
var newLayer = new Layer();
newLayer.activate(); // so that redCircle will be added to newLayer
var redCircle = Path.Circle(new Point(100, 100), 50);
redCircle.fillColor = 'red';
newLayer.remove(); // this prevents the redCircle from being drawn
project.layers.push(newLayer); // now the redCircle is back
或者,代替newLayer.remove();
,您可以使用newLayer.visible = false;
或newLayer.opacity = 0;
,以便newLayer永远不会从project.layers数组中删除,尽管使用这些方法选择的项目仍会显示线框即使实际项目无法看到。
答案 1 :(得分:0)
对于图层,有一个称为 visibility 的属性。您可以将其设置为true / false。
"""
Docstring.
"""
import chess
import chess.svg
from PyQt5.QtCore import pyqtSlot
from PyQt5.QtSvg import QSvgWidget
COORDINATES = True
FLIPPED = False
class Chessboard(QSvgWidget):
"""
Docstring.
"""
def __init__(self):
"""
Docstring.
"""
super().__init__()
self.clicked_square = -20
self.move_from_square = -20
self.move_to_square = -20
self.piece_to_move = [None, None]
viewbox_size = 400
self.margin = chess.svg.MARGIN * 800 / viewbox_size if COORDINATES else 0
self.file_size = chess.svg.SQUARE_SIZE * 800 / viewbox_size
self.rank_size = chess.svg.SQUARE_SIZE * 800 / viewbox_size
self.chessboard = chess.Board()
self.draw_chessboard()
@pyqtSlot(QSvgWidget)
def mousePressEvent(self, event):
"""
Docstring.
"""
x_coordinate = event.x()
y_coordinate = event.y()
file = int(x_coordinate / 800 * 8)
rank = 7 - int(y_coordinate / 800 * 8)
if file < 0:
file = 0
if rank < 0:
rank = 0
if file > 7:
file = 7
if rank > 7:
rank = 7
self.clicked_square = chess.square(file,
rank)
piece = self.chessboard.piece_at(self.clicked_square)
file_character = chr(file + 97)
rank_number = str(rank + 1)
ply = f"{file_character}{rank_number}"
if self.piece_to_move[0]:
move = chess.Move.from_uci(f"{self.piece_to_move[1]}{ply}")
if move in self.chessboard.legal_moves:
self.chessboard.push(move)
self.move_from_square = move.from_square
self.move_to_square = move.to_square
piece = None
ply = None
self.piece_to_move = [piece, ply]
self.draw_chessboard()
def draw_chessboard(self):
"""
Docstring.
"""
is_it_check = self.chessboard.king(self.chessboard.turn) \
if self.chessboard.is_check() \
else None
self.svg_chessboard = chess.svg.board(board=self.chessboard,
lastmove=chess.Move(from_square=self.move_from_square,
to_square=self.move_to_square),
arrows=[(self.clicked_square, self.clicked_square),
(self.move_from_square, self.move_to_square)],
check=is_it_check,
flipped=FLIPPED,
coordinates=COORDINATES,
size=800)
self.svg_chessboard_encoded = self.svg_chessboard.encode("utf-8")
self.load(self.svg_chessboard_encoded)
现在,当您创建新图层时,可以在对象上调用show或hide方法来更改可见性。
paper.Layer.prototype.hide = function(){
this.visibility = false
}
paper.Layer.prototype.show = function(){
this.visibility = true
}
但是,这并不会从活动层中删除该层。 您所做的任何更改都将位于活动层中,即使其 隐藏。
为此,我将一层称为。 rootLayer 并将其隐藏时设置为活动状态(baseLayer = new Layer()
// hiding layer
baseLayer.hide()
//showing layer
baseLayer.show()
)。这是一个hack,但可以完成工作