Question

我目前正在编写一个SQL脚本来计算两个日期之间的差异，它会给我DD：HH：MI：SEC格式的结果。例：日期1：7/30/12 4:00 PM 日期2：5/4/12 10:31 AM

结果应该是87：05：29：00

你能为这个剧本提供帮助吗？问候，阿琼

Answer 1

如果您使用的是sql-server，那么您可以这样做：

declare @x int, 
        @dt1 smalldatetime = '1996-03-25 03:24:16', 
        @dt2 smalldatetime = getdate()

set @x = datediff (s, @dt1, @dt2)


SELECT convert(varchar, @x / (60 * 60 * 24)) + ':'
+ convert(varchar, dateadd(s, @x, convert(datetime2, '0001-01-01')), 108)

参考here

Answer 2

嗨我有类似的问题，花了一些时间思考，这里是我的解决方案，我已经有了用户订阅的表，有悲伤的开始时间和关闭时间，我的问题有点复杂一点基本上它降下来对此：

SELECT subscription_id, time_open, time_closed, TIMESTAMPDIFF(DAY,time_open,time_closed) AS Day,

HOUR(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Hour,

MINUTE(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Minute,

SECOND(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Second

FROM `user_subscription`

所以基本上这个查询的作用是它通过在第一行中推断日期来计算天数。然后它将整天的数量添加到开始时间并减少我的总和的结束时间，所以剩下的是当天的时间。之后，您只需选择小时，分钟和秒。如果你想要它们，你可以连接字符串，但这样你可以进一步使用它，不像字符串。

Answer 3

好吧，如果你想进行一些计算，你也可以这样做：

DECLARE @SecsInADay INT = 60 * 60 * 24
DECLARE @DATE1 DATETIME = CONVERT(DATETIME,'30/07/2012 16:00:00')
DECLARE @DATE2 DATETIME = CONVERT(DATETIME,'04/05/2012 10:31:00')
DECLARE @Days INT = DATEDIFF(DAY, @DATE2, @DATE1)
DECLARE @DiffInSeconds INT = DATEDIFF(SECOND, @DATE2, @DATE1)
DECLARE @TotalDaysInSeconds INT = @Days * @SecsInADay
DECLARE @RemainingHours INT = @DiffInSeconds - @TotalDaysInSeconds
DECLARE @Hours INT = @RemainingHours / 3600
DECLARE @Seconds INT = @RemainingHours % 3600
DECLARE @Minutes INT = @Seconds / 60
DECLARE @RemainingSeconds INT = @Seconds % 60

SELECT
CASE WHEN @Days < 10 THEN '0' + CAST(@Days AS VARCHAR) ELSE CAST(@Days AS VARCHAR) END + ':' +
CASE WHEN @Hours < 10 THEN '0' + CAST(@Hours AS VARCHAR) ELSE CAST(@Hours AS VARCHAR) END + ':' +
CASE WHEN @Minutes < 10 THEN '0' + CAST(@Minutes AS VARCHAR) ELSE CAST(@Minutes AS VARCHAR) END + ':' +
CASE WHEN @RemainingSeconds < 10 THEN '0' + CAST(@RemainingSeconds AS VARCHAR) ELSE CAST(@RemainingSeconds AS VARCHAR) END

以天为单位计算SQL中的DateDiff：小时：分钟：秒格式

3 个答案: