方法changeFlowers失败,索引超出范围异常。
我是java的新手,我正在调用已经实例化的FishOne(Arraylist可再生类)的方法“changeColor()” 但它的失败与索引超出范围异常。
public void changeFlowers(int i)
{
FlowerOne f1 = (FlowerOne)(this._fishes.get(i)); // Is this the right way to call ????
f1.changeColor(this._theme);
}
Aquarium.java,FishOne.java下面的代码 感谢您的帮助。
public class Aquarium {
private AquariumThread _aquariumThread;
private SurfaceHolder _surfaceHolder;
private ArrayList<Renderable> _fishes;
private Bitmap _backgroundImage;
private Context _context;
public void render(){
Canvas canvas = null;
try{
canvas = this._surfaceHolder.lockCanvas(null);
synchronized (this._surfaceHolder) {
this.onDraw(canvas);
}
}finally{
if(canvas != null){
this._surfaceHolder.unlockCanvasAndPost(canvas);
}
}
}
protected void onDraw(Canvas canvas) {
this.renderBackGround(canvas);
for (Renderable renderable : this._fishes) {
renderable.render(canvas);
}
};
public void initialize(Context context, SurfaceHolder surfaceHolder) {
this._fishes = new ArrayList<Renderable>();
}
protected void onDraw(Canvas canvas) {
this.renderBackGround(canvas);
for (Renderable renderable : this._fishes) {
renderable.render(canvas);
}
};
public void start(){
this._aquariumThread.switchOn();
}
public void stop(){
boolean retry = true;
this._aquariumThread.switchOff();
while (retry) {
try {
this._aquariumThread.join();
retry = false;
} catch (InterruptedException e) {
// we will try it again and again...
}
}
}
public synchronized void addFishes() {
Point startPoint1 = new Point(1,300);
this._fishes.add(new fishOne(this._context, this, startPoint1, 90));
Point startPoint2 = new Point(100,300);
this._fishes.add(new fishOne(this._context, this, startPoint2, 90));
Point startPoint3 = new Point(200,300);
this._fishes.add(new fishOne(this._context, this, startPoint3, 90));
}
public void changeFlowers(int i)
{
FlowerOne f1 = (FlowerOne)(this._fishes.get(i));
f1.changeColor(this._theme);
}
}
public class fishOne extends Animal {
private static final int TOTAL_FRAMES_IN_SPRITE = 1;
private static final int CLOWN_FISH_FPS = 1;
int _fishColor;
Bitmap leftBitmap;
Bitmap rightBitmap;
public fishOne(Context context, Aquarium aquarium, Point startPoint, int speed){
super(context, aquarium);
this.changeColor(1);
this.initialize(this.leftBitmap, this.rightBitmap, CLOWN_FISH_FPS, TOTAL_FRAMES_IN_SPRITE, startPoint, speed);
}
public void changeColor(int mfishColor)
{
switch(mfishColor) {
case 1:
BitmapFactory.Options options = new BitmapFactory.Options();
options.inPurgeable = true;
this.leftBitmap = BitmapFactory.decodeResource(getContext().getResources(), com.gotit.livewallpaper.fishshd.R.drawable.fish1, options);
BitmapFactory.Options options1 = new BitmapFactory.Options();
options1.inPurgeable = true;
this.rightBitmap = BitmapFactory.decodeResource(getContext().getResources(), com.gotit.livewallpaper.fishshd.R.drawable.fish2, options1);
break;
case 2:
BitmapFactory.Options options2 = new BitmapFactory.Options();
options2.inPurgeable = true;
this.leftBitmap = BitmapFactory.decodeResource(getContext().getResources(), com.gotit.livewallpaper.fishshd.R.drawable.redfish1, options2);
BitmapFactory.Options options3 = new BitmapFactory.Options();
options3.inPurgeable = true;
this.rightBitmap = BitmapFactory.decodeResource(getContext().getResources(), com.gotit.livewallpaper.fishshd.R.drawable.redfish2, options3);
break;
default:
}
}
public void render(Canvas canvas){
super.render(canvas);
}
}
答案 0 :(得分:0)
这完全取决于代码的错误安全性。基本上如果你确定changeFlowers不会在参数i大于ArrayList大小的情况下调用那么它是Okoteonwise你必须把vheck放在changeFlowers函数中。
喜欢
public void changeFlowers(int i)
{
if(null!=this._fishes && this._fishes.size()>i){
FlowerOne f1 = (FlowerOne)(this._fishes.get(i));
f1.changeColor(this._theme);
}
}
但是,由于存在actulal问题,最好使代码安全,因为这个函数被调用。 上面的代码会停止错误,但您还需要在调用fumction的地方更正。