Question

在我的查询中，我想检查具有指定权限的用户是否存在。目前我正在使用以下查询。它将检索具有指定条件的授权用户行。

select a.ixUserAuthorization from tblechecklistuserroleassignmentxref r
inner join tblechecklistuserrole u on u.ixUserRole=r.ixUserRole and u.sname='Initiator'
inner join tblechecklistuserauthorization a on a.ixUserAuthorization=r.ixUserAuthorization
and a.ixcustomer='1'and a.ixprogram='1'and a.ixworkpackage='1'and a.ixactivity='1' and a.ixUser='626e28e8-e67a-4d11-8d2c-129d0ab79e96';

如果返回任何行，我想将结果显示为true，如果上述查询没有返回任何行，我想将结果显示为false。

如何修改以获得真或假的结果。

Answer 1

SELECT CASE 
         WHEN Count(*) >= 1 THEN 'true' 
         ELSE 'false' 
       END AS Answer 
FROM   (SELECT a.ixUserAuthorization 
        FROM   tblechecklistuserroleassignmentxref r 
               INNER JOIN tblechecklistuserrole u 
                 ON u.ixUserRole = r.ixUserRole 
                    AND u.sname = 'Initiator' 
               INNER JOIN tblechecklistuserauthorization a 
                 ON a.ixUserAuthorization = r.ixUserAuthorization 
                    AND a.ixcustomer = '1' 
                    AND a.ixprogram = '1' 
                    AND a.ixworkpackage = '1' 
                    AND a.ixactivity = '1' 
                    AND a.ixUser = '626e28e8-e67a-4d11-8d2c-129d0ab79e96') a

Answer 2

使用函数mysql_num_rows

例如：

if(mysql_num_rows($result))
  echo "true";
else
   echo "false";

其中$ result是您的查询结果

格式化mysql查询输出

2 个答案: